IntPart.Chars[length(IntPart)] in ['1','3','5','7','9'] ...但据我所知,s.Charsxx总是以零为基础的字符串,所以做IntPart.Chars[length(IntPart)] in ['1','3','5','7','9']总是会离开边界?IntPart.Char
我在此基础上重新编写了代码,但现在我想不出在不将empWeeklyPay初始化为0的情况下返回它的方法。如果我将它初始化为零,那么我的工资将始终为零?有谁能想到我能做些什么吗?Integer.toString(getEmployeeId()).charAt(0) == '2'//Java reads in 1010 so need to