当按下吉兹罗按钮时，我的LEDS为什么不亮？
当按下吉兹罗按钮时，我的LEDS为什么不亮？
提问于 2020-11-30 19:31:51
我编写了一个简单的python仪表板，使用guizero和gpiozero来打开和关闭LEDS。我只对LEDS有一个问题，他们只亮了一秒钟就熄灭了。我尝试使用time.sleep()查看LEDS是否会持续亮起，但不幸的是情况并非如此，这就是我问这个问题的原因。(我是Python新手，出于隐私考虑，我修改了一些代码行)
这是我的代码：
#!/usr/bin/env python
"""
When the "ok" buttons are pressed, the lights will turn on.
"""
from gpiozero import LED
from gpiozero.pins.pigpio import PiGPIOFactory
from guizero import App, PushButton, Box, Text
__author__ = "Senne De Winter"
__email__ = "senne.dewinter@...."
__status__ = "Development"
IP = PiGPIOFactory(host='192.....')
LED1 = LED(21, pin_factory=IP)
LED2 = LED(20, pin_factory=IP)
LED3 = LED(16, pin_factory=IP)
def turn_led1_on():
if LAMP1.bg == "white":
LAMP1.tk.configure(bg="red")
LED1.on()
elif LAMP1.bg == "red":
LAMP1.tk.configure(bg="white")
LED1.off()
def turn_led2_on():
if LAMP2.bg == "white":
LAMP2.tk.configure(bg="red")
LED2.on()
elif LAMP2.bg == "red":
LAMP2.tk.configure(bg="white")
LED2.off()
def turn_led3_on():
if LAMP3.bg == "white":
LAMP3.tk.configure(bg="red")
LED3.on()
elif LAMP3.bg == "red":
LAMP3.tk.configure(bg="white")
LED3.off()
app = App(title="Dashboard", layout="grid", width=400)
invis_1 = Box(app, grid=[0, 0], width=80)
invis_2 = Box(app, grid=[4, 0], width=20)
invis_3 = Box(app, grid=[8, 0], width=20)
invis_4 = Box(app, grid=[0, 1], width=80, height=10)
invis_5 = Box(app, grid=[4, 1], width=20, height=10)
invis_6 = Box(app, grid=[8, 1], width=20, height=10)
invis_7 = Box(app, grid=[0, 2], width=80)
invis_8 = Box(app, grid=[4, 2], width=20)
invis_9 = Box(app, grid=[8, 2], width=20)
lamp1 = Box(app, border=True, grid=[2,0])
lamp2 = Box(app, border=True, grid=[6,0])
lamp3 = Box(app, border=True, grid=[12,0])
LAMP1 = Text(lamp1, text="LAMP 1")
LAMP1.tk.configure(background="white")
LAMP2 = Text(lamp2, text="LAMP 2", bg="white")
LAMP2.tk.configure(background="white")
LAMP3 = Text(lamp3, text="LAMP 3", bg="white")
LAMP3.tk.configure(background="white")
button1 = PushButton(app, turn_led1_on, text="OK 1", grid=[2,2])
button2 = PushButton(app, turn_led2_on, text="OK 2", grid=[6,2])
button3 = PushButton(app, turn_led3_on, text="OK 3", grid=[12,2])
app.display()invis框是仪表板布局的不可见框。
回答 1
Stack Overflow用户
发布于 2020-12-01 17:39:07
根据我所看到的，你需要用LED1.toggle()来切换你的LED1.on()和LED1.off()，你可以按下仪表板上的一个按钮来打开和关闭它们。
下面是一个例子
def exit_app():
sys.exit()
def toggle_led():
led_01.toggle()
led_02.toggle()
led_03.toggle()
led_04.toggle()
if led_01.is_lit:
ledButton.text = "LED OFF"
else:
ledButton.text = "LED ON"
def led_blink():
for i in range(10):
led_01.on()
led_02.on()
led_03.on()
led_04.on()
time.sleep(1)
led_01.off()
led_02.off()
led_03.off()
led_04.off()
# App
app = App(title="Project house", height=400, width=400)
# Boxes
displayBox = Box(app, border= True, height=35, width=400)
buttonBox = Box(app, layout="grid", align="top")
# Title
title = Text(displayBox, text="Push a button")
title.text_size = 20
# Buttons
ledButton = PushButton(buttonBox, toggle_led, text="LED ON", grid=[0,0])
ledButton.text_size = 25
blinkButton = PushButton(buttonBox, led_blink, text="Push to party", grid=[9,0])
blinkButton.text_size= 25
exitButton = PushButton(app, exit_app, text="EXIT", align="bottom", width=15 ,
height=2)
exitButton.text_size = 32
app.display()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/65072765
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