Java 11 HttpClient -缺少表单参数: grant_type
Java 11 HttpClient -缺少表单参数: grant_type
提问于 2020-09-17 16:24:53
我试图通过Java11的HttpClient从Keycloack服务器获取访问令牌，但一直收到错误：
{
"error":"invalid_request",
"error_description":"Missing form parameter: grant_type"
}顺便说一下，有了邮递员，我就可以拿到代币了。我在我的代码中做的是：
Map<String, String> values = new HashMap<>() {{
put("username", username);
put ("password", password);
put("grant_type", "password");
}};
ObjectMapper objectMapper = new ObjectMapper();
String requestBody = objectMapper.writerWithDefaultPrettyPrinter()
.writeValueAsString(values);
HttpRequest request=HttpRequest.newBuilder()
.uri(URI.create(tokenEndpoint))
.setHeader("client_id", clientId)
.setHeader("client_secret", clientSecret)
.setHeader("content-type", "application/x-www-form-urlencoded")
.POST(HttpRequest.BodyPublishers.ofString(requestBody))
.build();
HttpClient.newHttpClient()
.sendAsync(request, HttpResponse.BodyHandlers.ofString())
.thenApply(HttpResponse::body)
.thenAccept(System.out::println);
/*
//Tried also
HttpResponse<String> response = client.send(request, HttpResponse.BodyHandlers.ofString());
System.out.println(response.body());
*/我做错了什么或遗漏了什么？
回答 2
Stack Overflow用户
回答已采纳
发布于 2020-09-17 20:48:28
这就是我们登录的方式：
MultiValueMap<String, String> requestParams = new LinkedMultiValueMap<>();
requestParams.add("client_id", keycloakProperties.getResource());
requestParams.add("username", username);
requestParams.add("password", password);
requestParams.add("grant_type", "password");
requestParams.add("client_secret", String.valueOf(keycloakProperties.getCredentials().get("secret")));
requestParams.add("scope", "openid");
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);
HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<>(requestParams, headers);
String url = keycloakProperties.getAuthServerUrl() + "/realms/" + keycloakProperties.getRealm() + "/protocol/openid-connect/token";
AccessTokenResponse keycloakAccessToken = getAccessTokenResponse(request, url);
// sometimes SSL handshake was failing, so catching error and trying again :)
private AccessTokenResponse getAccessTokenResponse(HttpEntity<MultiValueMap<String, String>> request, String url) {
try {
ResponseEntity<AccessTokenResponse> response = restTemplate.postForEntity(url, request, AccessTokenResponse.class);
return response.getBody();
} catch (ResourceAccessException e) {
log.error("KeyCloak getAccessTokenResponse: " + e.getMessage());
try {
ResponseEntity<AccessTokenResponse> response = restTemplate.postForEntity(url, request, AccessTokenResponse.class);
return response.getBody();
} catch (Exception ex) {
throw ex;
}
} catch (Exception e) {
throw e;
}
}Stack Overflow用户
发布于 2020-11-12 00:53:09
在.setHeader("content-type", "application/x-www-form-urlencoded")行中，请求需要表单数据，但您在请求正文中(通过ObjectMapper.writeValueAsString())发送json。
如果您正在尝试发送表单数据，则这应该是正确的编码：
String requestBody = "username=" + username + "password=" + password + "grant_type=password"如果API需要JSON，则将内容类型标头更改为application/json
HttpRequest request=HttpRequest.newBuilder()
...
.setHeader("content-type", "application/json")
...页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/63934095
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