我是一个新手,试图通过创建一个简单的todo应用程序来学习flask,这是我试图执行的python代码下面的代码,但当我运行时,我得到了sqlite3.OperationalError: no such column: todo.task,我不确定我在这里错过了什么,请协助
import os
from flask import Flask, render_template, request, redirect
from flask_sqlalchemy import SQLAlchemy
project_dir = os.path.dirname(os.path.abspath(__file__))
# sqlite: // / prefix to tell SQLAlchemy which database engine we're using.
database_file = "sqlite:///{}".format(
os.path.join(project_dir, "mydatabase.db"))
app = Flask(__name__)
app.config["SQLALCHEMY_DATABASE_URI"] = database_file
app.config["SQLALCHEMY_TRACK_MODIFICATIONS"] = False
db = SQLAlchemy(app)
class Todo(db.Model):
id = db.Column(db.Integer, primary_key=True)
task = db.Column(db.String(100))
@app.route('/', methods=["GET", "POST"])
def samplehome():
todo_list = Todo.query.all()
print(todo_list)
return render_template("index.html", todo_list=todo_list)
# if request.form:
# print(request.form)
# submitted = Todo(id=request.form.get("id"),task=request.form.get("task"))
# try:
# db.session.add(submitted)
# db.session.commit()
# except Exception as e:
# print(e)
# db.session.rollback()
if __name__ == "__main__":
db.create_all()
app.run(host='0.0.0.0', debug=True)发布于 2021-11-15 08:37:39
我认为问题是您没有在db.create_all()函数之后提交更改。你可以试着这样做。
if __name__ == "__main__":
db.create_all()
db.session.commit()
app.run(host='0.0.0.0', debug=True)还有一个类似的问题:SQLAlchemy create_all() does not create tables
除了你的问题,我不建议直接返回你的db类。你可以签出MVC设计模式。
https://stackoverflow.com/questions/69971126
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