问在不使用任何内置函数的情况下找到数字的平方根？

EN

  private static double computeSquareRootBinarySearch(double x, double precision) {
    double start = 0;
    double end = x / 2 + 1;
    double mid = (start + ((end - start) / 2));
    double prevMid = 0;
    double diff = Math.abs(mid - prevMid);

    while ((mid * mid != x) && (diff > precision)) {
      if (mid * mid > x) {
        end = mid;
      } else {
        start = mid;
      }
      prevMid = mid;
      mid = (start + end) / 2;
      diff = Math.abs(mid - prevMid);
    }
    return mid;
  }