blocks|key|1096627|text|奥斯特，9+字节数|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1096628|31FᎽGć2Š|code-block|syntax|javascript|1096629|在网上试试！|unstyled|1096630|作为字节，这是|1096631|F3+F1+1B+FF+30+1C+64+F2+42|1096632|或者，编码为UTF-8，|1096633|óñÿ0dòB|1096634|它可以通过省略-u标志来运行(默认情况下在TIO上填充)。注意未显示的0x1b和0x1c字节|style|CODE|1096635|是如何工作的|1096636|31FᎽGć2Š+-+Full+program.+n+is+pushed+to+the+stack
31+++++++-+Push+31
++F++++++-+Subtract;+n-31
+++Ꮍ+++++-+Push+16
++++G++++-+Divide;+(n-31)÷16
+++++ć+++-+Exp;+exp((n-31)÷16)
++++++2Š+-+Round+to+2+decimal+places|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/cairdcoinheringaahing/Orst-Geo|1|https://github.com/cairdcoinheringaahing/Orst-Geo/wiki/Code-Page|2|https://tio.run/##yy8qLvn/39jQ7WHfXvcj7UZHF/y/0Pn/v4nBv/yCksz8vOL/ujkA^0|0|3|0|6|3|1|0|0|0|6|2|0|0|0|0|0|7|2|Z|4|14|4|0|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@$A|1D|B|1E|1|1F]|$A|1G|B|1H|1|1I]]|C|$]]|$1|D|3|E|5|F|7|1J|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|1K|8|@]|9|@$A|1L|B|1M|1|1N]]|C|$]]|$1|L|3|M|5|K|7|1O|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|1P|8|@]|9|@]|C|$G|H]]|$1|P|3|Q|5|K|7|1Q|8|@]|9|@]|C|$]]|$1|R|3|S|5|F|7|1R|8|@]|9|@]|C|$G|H]]|$1|T|3|U|5|K|7|1S|8|@$A|1T|B|1U|V|W]|$A|1V|B|1W|V|W]|$A|1X|B|1Y|V|W]]|9|@]|C|$]]|$1|X|3|Y|5|6|7|1Z|8|@]|9|@]|C|$]]|$1|Z|3|10|5|F|7|20|8|@]|9|@]|C|$G|H]]]|11|$12|$5|13|14|15|C|$16|17]]|18|$5|13|14|15|C|$16|19]]|1A|$5|13|14|15|C|$16|1B]]]]

<h1><a href="https://github.com/cairdcoinheringaahing/Orst-Geo" rel="nofollow noreferrer">Orst</a>, 9 <a href="https://github.com/cairdcoinheringaahing/Orst-Geo/wiki/Code-Page" rel="nofollow noreferrer">bytes</a></h1>
<pre><code>31FᎽGć2Š
</code></pre>
<p><a href="https://tio.run/##yy8qLvn/39jQ7WHfXvcj7UZHF/y/0Pn/v4nBv/yCksz8vOL/ujkA" rel="nofollow noreferrer" title="Orst – Try It Online">Try it online!</a></p>
<p>As bytes, this is</p>
<pre><code>F3 F1 1B FF 30 1C 64 F2 42
</code></pre>
<p>Or, encoded as UTF-8,</p>
<pre><code>óñ&#27;ÿ0&#28;dòB</code></pre>
<p>which can be run by omitting the <code>-u</code> flag (filled by default on TIO). Note the not shown <code>0x1b</code> and <code>0x1c</code> bytes</p>
<h2>How it works</h2>
<pre><code>31FᎽGć2Š - Full program. n is pushed to the stack
31       - Push 31
  F      - Subtract; n-31
   Ꮍ     - Push 16
    G    - Divide; (n-31)÷16
     ć   - Exp; exp((n-31)÷16)
      2Š - Round to 2 decimal places
</code></pre>


blocks|key|1089191|text|井上，114个字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1089192|当你们都在享受语言中的四舍五入的时候，Io没有任何方便的四舍五入.|unstyled|1089193|method(x,I+:=((((x-31)/16)exp*100)round+asString);I=if(I+size<3,"0","")..+I;I+asMutable+atInsertSeq(I+size-2,"."))|code-block|syntax|javascript|1089194|在网上试试！|entityMap|0|LINK|mutability|MUTABLE|url|http://iolanguage.org/|1|https://tio.run/##RcyxDsIgFIXh3ae4YeIaitAmDtY@AINTV5eagpJUqEAT4ssjJiae7Uv@HOuLgdMA1/LU6eFnmpmqpnW56SQe5BF1XvdSCAx@czNMcUzBujv2arCGKoj2rc8dI4IwQpBzUL2q1WVL023RMCXlog5p1K9f3LSMcIJYDJUtwlrf0uJ2X/1ZPg^0|0|2|0|0|0|0|0|6|1^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$]]|$1|G|3|H|5|I|7|11|8|@]|9|@]|C|$J|K]]|$1|L|3|M|5|F|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

<h1><a href="http://iolanguage.org/" rel="nofollow noreferrer">Io</a>, 114 bytes</h1>
<p>While you all are enjoying rounding built-ins in your language, Io doesn't have any of those convenient rounding built-ins...</p>
<pre><code>method(x,I :=((((x-31)/16)exp*100)round asString);I=if(I size&lt;3,&quot;0&quot;,&quot;&quot;).. I;I asMutable atInsertSeq(I size-2,&quot;.&quot;))
</code></pre>
<p><a href="https://tio.run/##RcyxDsIgFIXh3ae4YeIaitAmDtY@AINTV5eagpJUqEAT4ssjJiae7Uv@HOuLgdMA1/LU6eFnmpmqpnW56SQe5BF1XvdSCAx@czNMcUzBujv2arCGKoj2rc8dI4IwQpBzUL2q1WVL023RMCXlog5p1K9f3LSMcIJYDJUtwlrf0uJ2X/1ZPg" rel="nofollow noreferrer" title="Io – Try It Online">Try it online!</a></p>


blocks|key|1089324|text|果冻，10+字节数|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1089325|_31÷⁴Æeær2|code-block|syntax|javascript|1089326|一种接受浮点数的一元链路，它产生浮点数。(作为一个完整的程序，十进制输入会导致结果被打印。)|unstyled|1089327|在网上试试！|1089328|怎么做？|1089329|_31÷⁴Æeær2+-+Link:+float,+n
+31++++++++-+31
_++++++++++-+subtract+++++++++->+n-31
++++⁴++++++-+16
+++÷+++++++-+divide+++++++++++->+(n-31)/16
+++++Æe++++-+exp(x)+++++++++++->+exp((n-31)/16)
+++++++++2+-+2
+++++++ær++-+round+to+10%5E(-y)+->+round(exp((n-31)/16),+2)|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/DennisMitchell/jelly|1|https://github.com/DennisMitchell/jelly/wiki/Code-pag|2|https://tio.run/##y0rNyan8/z/e2PDw9keNWw63pR5eVmT0//9/EwMA^0|0|2|0|6|3|1|0|0|0|0|6|2|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]|$A|16|B|17|1|18]]|C|$]]|$1|D|3|E|5|F|7|19|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|1A|8|@]|9|@]|C|$]]|$1|L|3|M|5|6|7|1B|8|@]|9|@$A|1C|B|1D|1|1E]]|C|$]]|$1|N|3|O|5|6|7|1F|8|@]|9|@]|C|$]]|$1|P|3|Q|5|F|7|1G|8|@]|9|@]|C|$G|H]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]|10|$5|T|U|V|C|$W|11]]]]

<h1><a href="https://github.com/DennisMitchell/jelly" rel="nofollow noreferrer">Jelly</a>, 10 <a href="https://github.com/DennisMitchell/jelly/wiki/Code-pag" rel="nofollow noreferrer">bytes</a></h1>
<pre><code>_31÷⁴Æeær2
</code></pre>
<p>A monadic Link accepting a float which yields a float. (As a full program a decimal input causes the result to be printed.)</p>
<p><strong><a href="https://tio.run/##y0rNyan8/z/e2PDw9keNWw63pR5eVmT0//9/EwMA" rel="nofollow noreferrer" title="Jelly – Try It Online">Try it online!</a></strong></p>
<h3>How?</h3>
<pre><code>_31÷⁴Æeær2 - Link: float, n
 31        - 31
_          - subtract         -&gt; n-31
    ⁴      - 16
   ÷       - divide           -&gt; (n-31)/16
     Æe    - exp(x)           -&gt; exp((n-31)/16)
         2 - 2
       ær  - round to 10^(-y) -&gt; round(exp((n-31)/16), 2)
</code></pre>


blocks|key|1096065|text|APL%2BWIN，13字节|type|header-two|depth|inlineStyleRanges|entityRanges|data|1096066|输入n的提示：|unstyled|1096067|⍎2⍕*(⎕-31)÷16|code-block|syntax|javascript|1096068|在网上试试！戴洛格经典礼|offset|length|entityMap|0|LINK|mutability|MUTABLE|url|https://tio.run/##SyzI0U2pTMzJT9dNzkksLs5M/v@ob6qvz6O2CcZcjzra0/4/6u0zetQ7VUsDKK5rbKh5eLuh2X@gzP80LkMjIy4uAA^0|0|0|0|0|C|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|W|8|@]|9|@]|A|$H|I]]|$1|J|3|K|5|D|7|X|8|@]|9|@$L|Y|M|Z|1|10]]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

<h1>APL+WIN, 13 bytes</h1>
<p>Prompts for input of n:</p>
<pre><code>⍎2⍕*(⎕-31)÷16
</code></pre>
<p><a href="https://tio.run/##SyzI0U2pTMzJT9dNzkksLs5M/v@ob6qvz6O2CcZcjzra0/4/6u0zetQ7VUsDKK5rbKh5eLuh2X@gzP80LkMjIy4uAA" rel="nofollow noreferrer" title="APL (Dyalog Classic) – Try It Online">Try it online! Courtesy of Dyalog Classic</a></p>


blocks|key|1096734|text|维沙尔+s，23字节|type|header-two|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1096735|31-16/W∆ehS\.€ḣh2wi\.$W|code-block|syntax|javascript|1096736|在网上试试！|unstyled|1096737|从这个答案来看，Vyxal有两个愚蠢的特性：|1096738|为什么ln(x)%5E{-1}需要取一个列表而不是数字？|unordered-list-item|1096739|说真的，它不能把数字圈成n位小数位，所以这个部分是手工操作的。|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/Lyxal/Vyxal|1|http://lyxal.pythonanywhere.com/?flags=s&code=31-16%252FW%25E2%2588%2586ehS%255C.%25E2%2582%25AC%25E1%25B8%25A3h2wi%255C.%2524W&inputs=40&header=&footer=|2|INLINETEX|IMMUTABLE|teX|ln(x)%5E{-1}^0|4|1|0|3|0|0|0|0|6|1|0|0|3|A|3|A|2|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@$9|1B|A|1C|1|1D]]|E|$]]|$1|F|3|G|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|M|7|1F|8|@]|D|@$9|1G|A|1H|1|1I]]|E|$]]|$1|N|3|O|5|M|7|1J|8|@]|D|@]|E|$]]|$1|P|3|Q|5|R|7|1K|8|@$9|1L|A|1M|B|C]]|D|@$9|1N|A|1O|1|1P]]|E|$]]|$1|S|3|T|5|R|7|1Q|8|@]|D|@]|E|$]]]|U|$V|$5|W|X|Y|E|$Z|10]]|11|$5|W|X|Y|E|$Z|12]]|13|$5|14|X|15|E|$16|17]]]]

<h1><a href="https://github.com/Lyxal/Vyxal" rel="nofollow noreferrer">Vyxal</a> <code>s</code>, 23 bytes</h1>
<pre><code>31-16/W∆ehS\.€ḣh2wi\.$W
</code></pre>
<p><a href="http://lyxal.pythonanywhere.com?flags=s&amp;code=31-16%2FW%E2%88%86ehS%5C.%E2%82%AC%E1%B8%A3h2wi%5C.%24W&amp;inputs=40&amp;header=&amp;footer=" rel="nofollow noreferrer">Try it Online!</a></p>
<p>From this answer two stupid features of Vyxal:</p>
<ul>
<li>Why <span class="math-container">\$ln(x)^{-1}\$</span> needs to take a list instead of digit?</li>
<li>Seriously it cannot round a digit to n decimal places, so that part is handrolled.</li>
</ul>


blocks|key|1089450|text|R，28字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1089451|round(exp((scan()-31)/16),2)|code-block|syntax|javascript|1089452|在网上试试！|unstyled|1089453|关于尾随零点是否必须打印，似乎存在一些争议。如果是这样的话，下面的35字节解决方案可以工作：|1089454|sprintf("%25.2f",exp((scan()-31)/16))|entityMap|0|LINK|mutability|MUTABLE|url|https://www.r-project.org/|1|https://tio.run/##K/r/vyi/NC9FI7WiQEOjODkxT0NT19hQU9/QTFPHSPO/IZepEZehkeF/AA^0|0|1|0|0|0|0|6|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|13|8|@]|9|@$A|14|B|15|1|16]]|C|$]]|$1|L|3|M|5|K|7|17|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|18|8|@]|9|@]|C|$G|H]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

<h1><a href="https://www.r-project.org/" rel="nofollow noreferrer">R</a>, 28 bytes</h1>
<pre class="lang-r prettyprint-override"><code>round(exp((scan()-31)/16),2)
</code></pre>
<p><a href="https://tio.run/##K/r/vyi/NC9FI7WiQEOjODkxT0NT19hQU9/QTFPHSPO/IZepEZehkeF/AA" rel="nofollow noreferrer" title="R – Try It Online">Try it online!</a></p>
<p>There seems to be some controversy about whether trailing zeros must be printed.
If so, the following 35 byte solution works:</p>
<pre class="lang-r prettyprint-override"><code>sprintf(&quot;%.2f&quot;,exp((scan()-31)/16))
</code></pre>


blocks|key|1089532|text|bc，40字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1089533|scale=2
define+f(n){return+e((n-31)/16)}|code-block|syntax|javascript|1089534|在网上试试！|unstyled|entityMap|0|LINK|mutability|MUTABLE|url|https://www.gnu.org/software/bc/manual/html_mono/bc.html|1|https://tio.run/##S0r@/784OTEn1daIKyU1LTMvVSFNI0@zuii1pLQoTyFVQyNP19hQU9/QTLP2f5qGoZEm1/9/@QUlmfl5xf91cwA^0|0|2|0|0|0|0|6|1^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

<h1><a href="https://www.gnu.org/software/bc/manual/html_mono/bc.html" rel="nofollow noreferrer">bc</a>, 40 bytes</h1>
<pre><code>scale=2
define f(n){return e((n-31)/16)}
</code></pre>
<p><a href="https://tio.run/##S0r@/784OTEn1daIKyU1LTMvVSFNI0@zuii1pLQoTyFVQyNP19hQU9/QTLP2f5qGoZEm1/9/@QUlmfl5xf91cwA" rel="nofollow noreferrer" title="bc – Try It Online">Try it online!</a></p>


blocks|key|1096329|text|木炭，20字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1096330|﹪%25.2fＸ¹·⁰⁶⁴⁴⁹⁴⁴⁵⁻Ｎ³¹|code-block|syntax|javascript|1096331|在网上试试！链接是详细的代码版本。从@JonathanAllan偷来的数字常量。解释：|unstyled|1096332|++++++++++++++++Ｎ++++++Input+as+a+number
+++++++++++++++⁻+³¹++++Subtract+literal+31
+++++Ｘ¹·⁰⁶⁴⁴⁹⁴⁴⁵++++++++Raise+literal+1.06449445+to+that+power
﹪%25.2f+++++++++++++++++++Format+using+literal+format+string+`%25.2f`
++++++++++++++++++++++++Implicitly+print|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/somebody1234/Charcoal|1|https://tio.run/##S85ILErOT8z5/z@gKDOvRMM3P6U0J19DSVXPKE1JRyEgvzy1SMNQz8DMxMTSxMRUR8E3M6@0WMMzr6C0xK80Nwkoq6mjYGyoCQTW//@bmP/XLcsBAA^0|0|2|0|0|0|0|6|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|L|3|M|5|F|7|15|8|@]|9|@]|C|$G|H]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

<h1><a href="https://github.com/somebody1234/Charcoal" rel="nofollow noreferrer">Charcoal</a>, 20 bytes</h1>
<pre><code>﹪%.2fＸ¹·⁰⁶⁴⁴⁹⁴⁴⁵⁻Ｎ³¹
</code></pre>
<p><a href="https://tio.run/##S85ILErOT8z5/z@gKDOvRMM3P6U0J19DSVXPKE1JRyEgvzy1SMNQz8DMxMTSxMRUR8E3M6@0WMMzr6C0xK80Nwkoq6mjYGyoCQTW//@bmP/XLcsBAA" rel="nofollow noreferrer" title="Charcoal – Try It Online">Try it online!</a> Link is to verbose version of code. Numeric constant stolen from @JonathanAllan. Explanation:</p>
<pre><code>                Ｎ      Input as a number
               ⁻ ³¹    Subtract literal 31
     Ｘ¹·⁰⁶⁴⁴⁹⁴⁴⁵        Raise literal 1.06449445 to that power
﹪%.2f                   Format using literal format string `%.2f`
                        Implicitly print
</code></pre>


blocks|key|1089603|text|生锈，38字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1089604|%7Cn%7Cprint!("{:.2}",((n-31.)/16.).exp())|code-block|syntax|javascript|1089605|在网上试试|unstyled|entityMap|0|LINK|mutability|MUTABLE|url|https://www.rust-lang.org/|1|https://tio.run/##RY3BCoMwEETv@YrR0y5oirb0oNWj/yHUUKHdSkxpQfPtaRRKT8Mwu@/Z1@yCETz6UYixKMANs6OwyjrZUVxC6VLp0qcZkeTHQvOhOGvWw2ci5gBwrbxSEbH9XbqWTIWO1fs22CHSutiEzPnEyFsQq01hnhaCUVBo3RRluXuBn1DQYPEZrjHTDBIV22xI0M/YWPX//i4J7d0rH74^0|0|2|0|0|0|0|5|1^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

<h1><a href="https://www.rust-lang.org/" rel="nofollow noreferrer">Rust</a>, 38 bytes</h1>
<pre><code>|n|print!(&quot;{:.2}&quot;,((n-31.)/16.).exp())
</code></pre>
<p><a href="https://tio.run/##RY3BCoMwEETv@YrR0y5oirb0oNWj/yHUUKHdSkxpQfPtaRRKT8Mwu@/Z1@yCETz6UYixKMANs6OwyjrZUVxC6VLp0qcZkeTHQvOhOGvWw2ci5gBwrbxSEbH9XbqWTIWO1fs22CHSutiEzPnEyFsQq01hnhaCUVBo3RRluXuBn1DQYPEZrjHTDBIV22xI0M/YWPX//i4J7d0rH74" rel="nofollow noreferrer">Try it online</a></p>


blocks|key|1096432|text|05AB1E，12字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|1096433|>16/Ížrsm2.ò|code-block|syntax|javascript|1096434|在网上试试！|unstyled|1096435|>16/Ížrsm2.ò++#+full+program
++++++++++.ò++#+round...
+++++žr+++++++#+2.718281828459045...
+++++++sm+++++#+to+the+power+of...
++++++++++++++#+implicit+input...
>+++++++++++++#+plus+1...
+++/++++++++++#+divided+by...
+16+++++++++++#+literal...
++++Í+++++++++#+minus+2...
++++++++++.ò++#+to...
+++++++++2++++#+literal...
++++++++++.ò++#+decimal+places
++++++++++++++#+implicit+output|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/Adriandmen/05AB1E|1|https://tio.run/##yy9OTMpM/f/fztBM/3Dv0X1FxblGeoc3/f9vaGQEAA^0|0|6|0|0|0|0|6|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|11|8|@]|9|@$A|12|B|13|1|14]]|C|$]]|$1|L|3|M|5|F|7|15|8|@]|9|@]|C|$G|H]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

<h1><a href="https://github.com/Adriandmen/05AB1E" rel="nofollow noreferrer">05AB1E</a>, 12 bytes</h1>
<pre><code>&gt;16/Ížrsm2.ò
</code></pre>
<p><a href="https://tio.run/##yy9OTMpM/f/fztBM/3Dv0X1FxblGeoc3/f9vaGQEAA" rel="nofollow noreferrer" title="05AB1E – Try It Online">Try it online!</a></p>
<pre><code>&gt;16/Ížrsm2.ò  # full program
          .ò  # round...
     žr       # 2.718281828459045...
       sm     # to the power of...
              # implicit input...
&gt;             # plus 1...
   /          # divided by...
 16           # literal...
    Í         # minus 2...
          .ò  # to...
         2    # literal...
          .ò  # decimal places
              # implicit output
</code></pre>


<h1>Task</h1>
<p>Take the (integer) number of human years that the dog has lived, <span class="math-container">\$n\$</span>, as input and return its age in dog years, <span class="math-container">\$d\$</span>, to two decimal places.<br />
The number of human years, <span class="math-container">\$n\$</span>, will be between <span class="math-container">\$1\$</span> and <span class="math-container">\$122\$</span> inclusive: <span class="math-container">\$n \in [1,122], n \in \Bbb{N}\$</span>.</p>
<p>According to <a href="https://www.sciencefocus.com/news/new-trick-to-calculate-your-old-dogs-age/" rel="nofollow noreferrer">BBC's Science Focus Magazine</a>, the correct function for determining your dog's age is:
<span class="math-container">$$
n = 16 \times \ln(d) + 31
$$</span>
Where</p>
<p><em><span class="math-container">\$n\$</span> is the age in human years</em></p>
<p><em><span class="math-container">\$d\$</span> is the age in dog years</em></p>
<h1>Rules</h1>
<p>The final output in dog years must be a decimal, <strong>rounded to 2 decimal places.</strong></p>


Find your dog's age

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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社区新版编辑器体验调研

任务以狗所生活的人类年数(整数) n作为输入，并以狗年( d )为单位将其年龄返回到小数点后两位。人类年数( n )将介于1和122 (包括：n \in [1,122], n \in \Bbb{N} )之间。根据英国广播公司科学焦点杂志的说法，确定狗的年龄的正确功能是：n = 16 \times \ln(d) + 31 哪里n是人类的年龄d是狗年的年龄规则狗年的最终输出必须是小数点，四舍五入到小数

问找出你狗的年龄
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回答 10

Code Golf用户

奥斯特，9 字节数

是如何工作的

Code Golf用户

井上，114个字节

Code Golf用户

果冻，10 字节数

在网上试试！

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问找出你狗的年龄EN

任务

规则

回答 10

Code Golf用户

奥斯特，9 字节数

是如何工作的

Code Golf用户

井上，114个字节

Code Golf用户

果冻，10 字节数

在网上试试！

怎么做？

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圈层

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问找出你狗的年龄
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