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问如何阻止我的Python游戏代码在第3-4行之后关闭？
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Stack Overflow用户

提问于 2019-01-23 13:22:51

回答 3查看 513关注 0票数 0

我三天前才开始学习编程。我决定学习Python，3.7.2版本。今天，我编写了这段代码，试图创建一个游戏，在这个游戏中，你输入一个用户名，然后用石头、纸、剪刀对付一个机器人。然而，在我输入用户名(第2-4行)之后，Python就会关闭。我是通过点击我的资源管理器Windows 10中的文件来运行这个程序的。我想这是一个简单的初学者错误，有人能帮忙吗？

我尝试在第4行添加输入()，当我这样做时，Python在输入用户名后不会关闭。什么都不做，只是换行。当我在换行符中键入什么并按Enter键时，shell将关闭。

这是我的密码：

import random
print('Hello, welcome to Rock, Paper, Scissors. Enter your name to get started.')
usn = input()

def game(choice):
  options = ['rock', 'paper', 'scissors']
  bot = random.choice(options)
  if choice == 'rock' and bot == 'scissors':
    print(usn + ' played rock, I played scissors. You won. Nice!')
  elif choice == 'rock' and bot == 'paper':
    print(usn + ' played rock, I played paper. You lost. Haha, loser!')
  elif choice == 'paper' and bot == 'scissors':
    print(usn + ' played paper, I played scissors. You lost. Haha, loser!')
  elif choice == 'paper' and bot == 'rock':
    print(usn + ' played paper, I played rock. You won. Nice!')
  elif choice == 'scissors' and bot == 'paper':
    print(usn + ' played scissors, I played paper. You won. Nice!')
  elif choice == 'scissors' and bot == 'rocks':
    print(usn + ' played scissors, I played rocks. You lost. Haha, loser!')
  elif choice == bot:
    print("It's a draw, dang it!")

def again(x):
    while True:
        if x == 'Yes':
            game(input('Rock, Paper or Scissors?'))
            again(input('Want to play again? Yes or No'))
        else:
            print('Goodbye. Press Enter to exit.')
            input()

预期:我希望在我输入用户名后，我可以输入岩石，纸或剪刀，然后游戏将发挥。实际结果: Python在输入用户名后关闭。

python

python-3.x

回答 3

Stack Overflow用户

回答已采纳

发布于 2019-01-23 13:30:28

您也需要调用game --尽管此时需要声明game。

我在这里稍微重构了一些东西，使它们对用户来说更方便一些。

game中使用的参数名是username和user_choice，这样就不会隐藏全局名称(或者偶然使用它们)。
again()递归函数被一个while循环所取代，当用户说他们不想再次播放时，这个循环就会被break删除。
RPS和同样的问题输入都是小写和剥离的，因此用户输入" NO“、”nO“、"pAPeR”等就可以了。

接下来我建议考虑的是如何简化game函数中的重复。:)

import random


def game(username, user_choice):
    options = ['rock', 'paper', 'scissors']
    bot = random.choice(options)
    if user_choice == 'rock' and bot == 'scissors':
        print(username + ' played rock, I played scissors. You won. Nice!')
    elif user_choice == 'rock' and bot == 'paper':
        print(username + ' played rock, I played paper. You lost. Haha, loser!')
    elif user_choice == 'paper' and bot == 'scissors':
        print(username + ' played paper, I played scissors. You lost. Haha, loser!')
    elif user_choice == 'paper' and bot == 'rock':
        print(username + ' played paper, I played rock. You won. Nice!')
    elif user_choice == 'scissors' and bot == 'paper':
        print(username + ' played scissors, I played paper. You won. Nice!')
    elif user_choice == 'scissors' and bot == 'rocks':
        print(username + ' played scissors, I played rocks. You lost. Haha, loser!')
    elif user_choice == bot:
        print("It's a draw, dang it!")


print('Hello, welcome to Rock, Paper, Scissors. Enter your name to get started.')
name = input()

while True:  # do forever, unless `break`ed out of (or an exception occurs)
    choice = input('Rock, Paper or Scissors?').lower().strip()
    game(name, choice)
    if input('Want to play again? Yes or No').lower().strip() == 'no':
        print('Goodbye. Press Enter to exit.')
        input()
        break  # break out of the "while true" loop

票数 1

Stack Overflow用户

发布于 2019-01-23 13:30:06

第一个问题是，在收到用户名后，您没有调用任何函数，我会尝试这样做(请注意，我在代码中添加了一些注释)：

import random
print('Hello, welcome to Rock, Paper, Scissors. Enter your name to get started.')
usn = input()

def game(choice):
  options = ['rock', 'paper', 'scissors']
  bot = random.choice(options)
  if choice == 'rock' and bot == 'scissors':
    print(usn + ' played rock, I played scissors. You won. Nice!')
  elif choice == 'rock' and bot == 'paper':
    print(usn + ' played rock, I played paper. You lost. Haha, loser!')
  elif choice == 'paper' and bot == 'scissors':
    print(usn + ' played paper, I played scissors. You lost. Haha, loser!')
  elif choice == 'paper' and bot == 'rock':
    print(usn + ' played paper, I played rock. You won. Nice!')
  elif choice == 'scissors' and bot == 'paper':
    print(usn + ' played scissors, I played paper. You won. Nice!')
  elif choice == 'scissors' and bot == 'rocks':
    print(usn + ' played scissors, I played rocks. You lost. Haha, loser!')
  elif choice == bot:
    print("It's a draw, dang it!")

# Taking this out of the function, it is going to be called right on the execution
x = 'Yes' 
while True: #here you are doing an loop, that will only end when break is called
    if x == 'Yes':
        game(input('Rock, Paper or Scissors?'))
        x = input('Want to play again? Yes or No')
    else:
        print('Goodbye. Press Enter to exit.')
        input()
        break

票数 0

Stack Overflow用户

发布于 2019-01-23 13:24:55

def game(choice):创建一个名为game的函数。您需要告诉python使用一个参数来执行这个函数：choice，如：game(usn)

票数 -1

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/54328278

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