如何从JSON创建对象集合
如何从JSON创建对象集合
提问于 2018-08-24 10:41:54
我正在学习Swift，我想制作一个应用程序来显示地图上公共汽车的GPS坐标。总线lat和lon来自一个JSON (以下摘录)：
{
"result":[
{
"Lat":52.276408,
"Lon":21.167618,
"Time":"2018-08-24 11:50:05",
"Lines":"225",
"Brigade":"4"
},
{
"Lat":52.222656,
"Lon":21.102633,
"Time":"2018-08-24 11:51:03",
"Lines":"225",
"Brigade":"2"
},
{
"Lat":52.2100185,
"Lon":21.2054211,
"Time":"2018-08-24 11:51:08",
"Lines":"119",
"Brigade":"2"
},
{
"Lat":52.1676735,
"Lon":21.2222606,
"Time":"2018-08-24 11:51:07",
"Lines":"213",
"Brigade":"3"
}
]
}我在考虑创建一个公共汽车课程
class Bus {
var latitude : Double = 1.11
var longitude : Double = 2.22
var lines : Int = 0
init (lat: Double, lon: Double, line: Int) {
latitude = lat
longitude = lon
lines = line
}
}但是，我正在尝试从JSON创建这些总线对象的集合，JSON(完整的)包含大约1000个对象(数量在一天中变化)。
有人能给我指明正确的方向吗？我不需要完全编码的解决方案，只是一些关于我应该如何处理这个问题的提示。
我很可能会使用SwiftyJSON CocoaPod进行JSON解析，同时使用Alamofire来获得它。
谢谢!
回答 3
Stack Overflow用户
回答已采纳
发布于 2018-08-24 10:48:22
您可以使用Codable类下面的Larme在评论中说。
import Foundation
class MyModelClass: Codable {
let result: [Result]
init(result: [Result]) {
self.result = result
}
}
class Result: Codable {
let lat, lon: Double
let time, lines, brigade: String
enum CodingKeys: String, CodingKey {
case lat = "Lat"
case lon = "Lon"
case time = "Time"
case lines = "Lines"
case brigade = "Brigade"
}
init(lat: Double, lon: Double, time: String, lines: String, brigade: String) {
self.lat = lat
self.lon = lon
self.time = time
self.lines = lines
self.brigade = brigade
}
}如果您想使用ObjectMapper，那么您可以使用下面的类
import Foundation
import ObjectMapper
class MyModelClass: Mappable {
var result: [Result]?
required init?(map: Map){
}
func mapping(map: Map) {
result <- map["result"]
}
}
class Result: Mappable {
var lat: NSNumber?
var lon: NSNumber?
var time: String?
var lines: String?
var brigade: String?
required init?(map: Map){
}
func mapping(map: Map) {
lat <- map["Lat"]
lon <- map["Lon"]
time <- map["Time"]
lines <- map["Lines"]
brigade <- map["Brigade"]
}
} Stack Overflow用户
发布于 2018-08-24 10:49:10
这样的写列表模型
class BusListModel {
var list = [Bus]()
var longitude : Double = 2.22
var lines : Int = 0
init (With dict:[String:Any]) {
if let result = dict["result"] as? [[String:Any]]{
for busDetail in result{
let model = Bus(lat: **valueHere**, lon: **valueHere**, line: **valueHere**)
list.append(model)
}
}
}
}Stack Overflow用户
发布于 2018-08-24 21:15:17
感谢大家的回答，特别是@dahiya_boy
我定制了@dahiya_boy发布的代码，最终得到了我所需要的。
下面是密码。例如，我创建了一个jsonString。
import Foundation
class MyModelClass: Codable {
let busArray: [Bus]
enum CodingKeys: String, CodingKey {
case busArray = "result"
}
init(busArray: [Bus]) {
self.busArray = busArray
}
}
class Bus: Codable {
let lat, lon: Double
let time, lines, brigade: String
enum CodingKeys: String, CodingKey {
case lat = "Lat"
case lon = "Lon"
case time = "Time"
case lines = "Lines"
case brigade = "Brigade"
}
init(lat: Double, lon: Double, time: String, lines: String, brigade: String) {
self.lat = lat
self.lon = lon
self.time = time
self.lines = lines
self.brigade = brigade
}
}
var jsonString = """
{
"result":[
{
"Lat":52.276408,
"Lon":21.167618,
"Time":"2018-08-24 11:50:05",
"Lines":"225",
"Brigade":"4"
},
{
"Lat":52.222656,
"Lon":21.102633,
"Time":"2018-08-24 11:51:03",
"Lines":"225",
"Brigade":"2"
},
{
"Lat":52.2100185,
"Lon":21.2054211,
"Time":"2018-08-24 11:51:08",
"Lines":"119",
"Brigade":"2"
},
{
"Lat":52.1676735,
"Lon":21.2222606,
"Time":"2018-08-24 11:51:07",
"Lines":"213",
"Brigade":"3"
}
]
}
"""
if let jsonData = jsonString.data(using: .utf8) {
let decodedJSON = try! JSONDecoder().decode(MyModelClass.self, from: jsonData)
print("Latitude: \(decodedJSON.busArray[0].lat), Longitude: \(decodedJSON.busArray[0].lon), Line: \(decodedJSON.busArray[0].lines)")
}这将打印以下控制台输出：
Latitude: 52.276408, Longitude: 21.167618, Line: 225页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52002740
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