我想在Model.find()方法中的where()中添加一个函数，但是它给出的错误包含在Body中
我想在Model.find()方法中的where()中添加一个函数，但是它给出的错误包含在Body中
提问于 2018-08-24 06:12:16
提供代码，在传递路径时给出一个类型错误，如下所示
function maxDis(lat1, lon1, location) {
var fields = location.split(':');
var lat2 = parseFloat(fields[0]);
var lon2 = parseFloat(fields[1]);
var maxDis = parseInt(fields[2]);
var theta = lon1 - lon2;
var dist = Math.sin(deg2rad(lat1)) * Math.sin(deg2rad(lat2))
+ Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2))
* Math.cos(deg2rad(theta));
dist = Math.acos(dist);
dist = rad2deg(dist);
dist = dist * 60; // 60 nautical miles per degree of seperation
dist = dist * 1852; // 1852 meters per nautical mile
if (Math.abs(dist) < maxDis) {
return true;
} else {
return false;
}
}这里也有一个错误：
resRouter.route('/locationfilters/veg/:location')
.options(cors.corsWithOptions, (req, res) => { res.sendStatus(200) })
.get(cors.cors, (req, res, next) => {
Res.find({})
.where(maxDis(parseFloat(this.latitude), parseFloat(this.longitude), req.params.location) == true)
.then((rest) => {
res.statusCode = 200;
res.setHeader('Content-Type', 'application/json');
res.json(rest);
}, (err) => next(err))
.catch((err) => next(err));
});我无法找到不属于字符串类型的路径
错误登录执行请求->
TypeError: path must be a string or object
at model.Query.Query.where (/home/yash/Documents/FoodApp/conFusionServer/node_modules/mquery/lib/mquery.js:299:9)
at resRouter.route.options.get (/home/yash/Documents/FoodApp/conFusionServer/routes/resRouter.js:351:14)
at Layer.handle [as handle_request] (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/layer.js:95:5)
at next (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/route.js:137:13)
at cors (/home/yash/Documents/FoodApp/conFusionServer/node_modules/cors/lib/index.js:188:7)
at /home/yash/Documents/FoodApp/conFusionServer/node_modules/cors/lib/index.js:224:17
at originCallback (/home/yash/Documents/FoodApp/conFusionServer/node_modules/cors/lib/index.js:214:15)
at /home/yash/Documents/FoodApp/conFusionServer/node_modules/cors/lib/index.js:219:13
at optionsCallback (/home/yash/Documents/FoodApp/conFusionServer/node_modules/cors/lib/index.js:199:9)
at corsMiddleware (/home/yash/Documents/FoodApp/conFusionServer/node_modules/cors/lib/index.js:204:7)
at Layer.handle [as handle_request] (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/layer.js:95:5)
at next (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/route.js:137:13)
at next (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/route.js:131:14)
at next (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/route.js:131:14)
at Route.dispatch (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/route.js:112:3)
at Layer.handle [as handle_request] (/home/yash/Documents/FoodApp/conFusionServer/node_modules/express/lib/router/layer.js:95:5)回答 1
Stack Overflow用户
回答已采纳
发布于 2018-08-24 08:42:11
您需要Model.$where()方法而不是Query.where()。由于您的查询使用的是JavaScript表达式，所以可以通过Model.find({ $where: <javascript_function> })进行查询，也可以通过查询链或从参数为javascript字符串或匿名函数的蒙鹅模型使用$where快捷方法。
Res.$where(() => maxDis(parseFloat(this.latitude), parseFloat(this.longitude), req.params.location))
.then((rest) => {
res.statusCode = 200;
res.setHeader('Content-Type', 'application/json');
res.json(rest);
}, (err) => next(err))
.catch((err) => next(err));页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51998476
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