问如何将regex对象与python中的列表进行比较？

EN

import re
x=["Set","Sets","ShowSets","Union","Intersect","SetUnion","SetIntersect"]
print (x)
while True:
    text_to_search = input('Introduce an instruction: ')

    for match1 in re.finditer('Sets?|ShowSet|ShowSets|Union|Intersect|SetUnion|SetIntersect',text_to_search):
        print("Instruction: ")
        #x.append(match1)
        print(match1)
    for match2 in re.finditer(r':=|{|}|;',text_to_search):
        print("Operator: ")
        print(match2)
    for match3 in re.finditer(r'[a-zA-Z0-9]+',text_to_search):
        if match3 in x:
            pass
        else:
            print("ID: ")
            print(match3)
    print(x)

Introduce an instrucción: Set Hi
Instruction: 
<_sre.SRE_Match object; span=(0, 3), match='Set'>
ID: 
<_sre.SRE_Match object; span=(0, 3), match='Set'>
ID: 
<_sre.SRE_Match object; span=(4, 6), match='Hi'>
['Set', 'Sets', 'ShowSets', 'Union', 'Intersect', 'SetUnion', 'SetIntersect']

Introduce an instrucción: Set Hi
    Instruction: 
    <_sre.SRE_Match object; span=(0, 3), match='Set'>
 ID: 
    <_sre.SRE_Match object; span=(4, 6), match='Hi'>
    ['Set', 'Sets', 'ShowSets', 'Union', 'Intersect', 'SetUnion', 'SetIntersect']