在Q&A风格的中发布这个问题。
为什么两个相同的表之间的布尔匹配(其中一个是从HDB中选择的)生成0b而不是1b
q)trade:trade2:`sym`time xasc ([] sym:5?`apple`google;time:5?.z.t;price:100+5?1.)
q).Q.dpft[`:tmp;.z.d-1;`sym;`trade]
`trade加载HDB
\l tmp/
q)hist:select from trade where date=.z.d-1
q)hist
date sym time price
---------------------------------------
2018.04.23 apple 02:31:39.330 100.2392
2018.04.23 apple 04:25:17.604 100.1508
2018.04.23 apple 07:57:14.764 100.2782
2018.04.23 google 02:59:16.636 100.1567
2018.04.23 google 14:35:31.860 100.9785
q)(`date xcols update date:.z.d-1 from trade2)
date sym time price
---------------------------------------
2018.04.23 apple 02:31:39.330 100.2392
2018.04.23 apple 04:25:17.604 100.1508
2018.04.23 apple 07:57:14.764 100.2782
2018.04.23 google 02:59:16.636 100.1567
2018.04.23 google 14:35:31.860 100.9785表比较生成假(0b)
q)(`date xcols update date:.z.d-1 from trade2)~hist
0b发布于 2018-04-24 20:00:31
不匹配是由于从HDB中选择的表的sym列(20h)类型造成的。
\l tmp/
q)hist:select from trade where date=.z.d-1
q)type exec sym from hist
20h
q)type exec sym from trade2
11h
q)type exec value sym from hist
11h虽然它看起来非常像符号,但是有一个新的类型20h,类似于下面的(来自Kx wiki)
q)type `city$10?city:`london`paris`rome
21h使用value和sym来获得所需的结果:
q)(`date xcols update date:.z.d-1 from trade2)~update value sym from hist
1bhttps://stackoverflow.com/questions/50009893
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