C++：调试确定，运行发行版得到错误答案
我已经提取出有问题的代码，下面的代码定义了一个带有向量的2D数组。然后打印二维数组。当我使用调试模式运行它时，它会打印正确的答案，但是当我在没有调试的情况下运行它时(即。释放模式)。有时它打印整个2D数组，有时打印一部分，然后退出，没有任何消息。为什么会发生这种事？谢谢你！
运行环境：
Windows 10 version: 10.0.16299.125 Clion 2017.3 Mingw64 5.0 狮子座的CmakeLists.txt：
cmake\_minimum\_required(VERSION 3.8) project(Test) set(CMAKE\_CXX\_STANDARD 11) set(SOURCE\_FILES main.cpp) add\_executable(Test ${SOURCE\_FILES})#include <vector>
#include <iostream>
using namespace std;
int main()
{
vector<vector<int>> graph{{0, 4, 0, 0, 0, 0, 0, 8, 0},
{4, 0, 8, 0, 0, 0, 0, 11, 0},
{0, 8, 0, 7, 0, 4, 0, 0, 2},
{0, 0, 7, 0, 9, 14, 0, 0, 0},
{0, 0, 0, 9, 0, 10, 0, 0, 0},
{0, 0, 4, 14, 10, 0, 2, 0, 0},
{0, 0, 0, 0, 0, 2, 0, 1, 6},
{8, 11, 0, 0, 0, 0, 1, 0, 7},
{0, 0, 2, 0, 0, 0, 6, 7, 0}};
for(int i = 0; i < graph.size(); i++)
{
for(int j = 0; j < graph[i].size(); j++)
{
cout << i << "-" << j << ": "<< graph[i][j] << endl;
}
cout << endl;
}
return 0;
}输出不稳定，有时成功，有时失败，下面是两个错误的输出第一个错误的输出：
E:\coding\LCCPP\Test\cmake-build-debug\Test.exe
0-0: 0
0-1: 4
0-2: 0
0-3: 0
0-4: 0
0-5: 0
0-6: 0
0-7: 8
0-8: 0
1-0: 4
1-1
1-1:
Process finished with exit code 0第二个错误输出：
E:\coding\LCCPP\Test\cmake-build-debug\Test.exe
0-0: 0
0-1: 4
0-2: 0
0-3: 0
0-4: 0
0-5: 0
0-6: 0
0-7: 8
0-8: 0
1-0: 4
1-1: 0
1-2: 8
1-3: 0
1-4: 0
1-5: 0
1-6: 0
1-7: 11
1-8: 0
2-0: 0
2-1: 8
2-2: 0
2-3: 7
2-4: 0
2-5: 4
2-6: 0
2-7: 0
2-8: 2
3-0: 0
3-1: 0
3-2: 7
3-3: 0
3-4: 9
3-5: 14
3-6: 0
3-7: 0
3-8: 0
4-0: 0
4-1: 0
4-2: 0
4-3: 9
4-4: 0
4-5: 10
4-6: 0
4-7: 0
4-8: 0
5-0: 0
5-1: 0
5-2: 4
5-3: 14
5-4: 10
5-5: 0
5-6: 2
5-7: 0
5-8: 0
6-0: 0
6-1: 0
6-2: 0
6-3: 0
6-4: 0
6-5: 2
6-6: 0
6-7: 1
6-8: 6
7-0: 8
7-1: 11
7-2: 0
7-3: 0
7-4: 0
7-5: 0
7-6: 1
7-7: 0
7-8: 7
8-0: 0
8-1: 0
8-2: 2
8-3: 0
8-4: 0
8-5: 0
8
Process finished with exit code 0正确的产出：
E:\coding\LCCPP\Test\cmake-build-debug\Test.exe
0-0: 0
0-1: 4
0-2: 0
0-3: 0
0-4: 0
0-5: 0
0-6: 0
0-7: 8
0-8: 0
1-0: 4
1-1: 0
1-2: 8
1-3: 0
1-4: 0
1-5: 0
1-6: 0
1-7: 11
1-8: 0
2-0: 0
2-1: 8
2-2: 0
2-3: 7
2-4: 0
2-5: 4
2-6: 0
2-7: 0
2-8: 2
3-0: 0
3-1: 0
3-2: 7
3-3: 0
3-4: 9
3-5: 14
3-6: 0
3-7: 0
3-8: 0
4-0: 0
4-1: 0
4-2: 0
4-3: 9
4-4: 0
4-5: 10
4-6: 0
4-7: 0
4-8: 0
5-0: 0
5-1: 0
5-2: 4
5-3: 14
5-4: 10
5-5: 0
5-6: 2
5-7: 0
5-8: 0
6-0: 0
6-1: 0
6-2: 0
6-3: 0
6-4: 0
6-5: 2
6-6: 0
6-7: 1
6-8: 6
7-0: 8
7-1: 11
7-2: 0
7-3: 0
7-4: 0
7-5: 0
7-6: 1
7-7: 0
7-8: 7
8-0: 0
8-1: 0
8-2: 2
8-3: 0
8-4: 0
8-5: 0
8-6: 6
8-7: 7
8-8: 0
Process finished with exit code 0回答 2
Stack Overflow用户
发布于 2018-01-18 06:42:15
代码没有实际问题，可能是IDE不提供输出的问题。实际上，在控制台中打印整个管道缓冲区之前，程序就会退出。当子进程退出时，管道被关闭，没有任何错误，父进程没有任何打印。如果在结束时暂停程序会发生什么情况？
虽然在非空函数中不提供“返回”是不好的，但是mingw将等效的return 0;添加到main().
PS:考虑使用range-fors：
int main()
{
using namespace std;
vector<vector<int>> graph{{0, 4, 0, 0, 0, 0, 0, 8, 0},
{4, 0, 8, 0, 0, 0, 0, 11, 0},
{0, 8, 0, 7, 0, 4, 0, 0, 2},
{0, 0, 7, 0, 9, 14, 0, 0, 0},
{0, 0, 0, 9, 0, 10, 0, 0, 0},
{0, 0, 4, 14, 10, 0, 2, 0, 0},
{0, 0, 0, 0, 0, 2, 0, 1, 6},
{8, 11, 0, 0, 0, 0, 1, 0, 7},
{0, 0, 2, 0, 0, 0, 6, 7, 0}};
for(auto &line: graph)
{
int i = 0, j= 0;
for(auto v : line )
{
cout << i << "-" << j << ": "<< v << endl;
j++;
}
i++;
cout << endl;
}
return 0;
}( http://en.cppreference.com/w/cpp/language/range-for )
Stack Overflow用户
发布于 2018-01-18 07:03:13
也许可以通过添加std::flush来检查这个解决方案
for(auto v : line )
{
cout << i << "-" << j << ": "<< v << endl << flush;
j++;
}它将“强制”所有输出。顺便说一下，在我看来，这是一些代码优化的问题。
https://stackoverflow.com/questions/48313786
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