我正在尝试执行一个XPath 2.0表达式,我可能遗漏了什么,我能够形成XPathSelector,问题是如何在org.w3c.dom.Document对象上运行选择器?我的代码如下:
public class XPath2Test {
public static void main(String[] args) throws Exception{
String assemblyXPathString="/child::AssemblyBase/child::Assembly[attribute::roles='ALL' or contains(attribute::roles,$role)]";
DOMParser parser=new DOMParser();
FileInputStream fis=new FileInputStream("E:\\workspaces\\dev_werewolf\\Platform_Manual\\manual\\UIFramework\\RoleBasedUIAssembly2.xml");
InputSource inputSource=new InputSource(fis);
parser.parse(inputSource);
Document document=parser.getDocument();
Processor processor=new Processor(false);
//processor.newDocumentBuilder().build(new File("E:\\workspaces\\dev_werewolf\\Platform_Manual\\manual\\UIFramework\\RoleBasedUIAssembly2.xml"));
XPathCompiler compiler=processor.newXPathCompiler();
compiler.declareVariable(new QName("role"));
XPathExecutable executable=compiler.compile(assemblyXPathString);
XPathSelector selector=executable.load();
ArrayList<String> values=new ArrayList<>();
values.add("CIO");
selector.setVariable(new QName("role"), XdmItem.makeSequence(values));
//Now what???, how to run the quesry against the 'document'???
selector.evaluate();//Exception
}//main closing
}//class closing发布于 2018-01-08 12:59:23
你需要做的
selector.setContextItem(item)若要设置XPath计算的上下文节点,以及获取引用DOM文档根节点的项的方式,请执行以下操作
XdmNode item = processor.newDocumentBuilder().wrap(document);请注意,只有在有充分理由的情况下,才应该对Saxon使用DOM节点;使用Saxon的内部树实现通常要快5到10倍。如果你不在乎它是什么样的树,用
XdmNode item = processor.newDocumentBuilder().build(
new File("E:\\workspaces\\dev_werewolf\\Platform_Manual\\manual\\UIFramework\\RoleBasedUIAssembly2.xml"));https://stackoverflow.com/questions/48148986
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