为什么它只打印6个字段而不是7个python
为什么它只打印6个字段而不是7个python
提问于 2017-11-21 13:34:03
如何使用下面的代码获得第7条记录？
from pprint import pprint
def date_op(total_input_list):
total_pages=36
list=[]
for xy in total_input_list:
for i in range(1,len(xy)):
Start_page=xy[i]["start_page"]
End_page=xy[i+1]["start_page"]-1
Date = xy[i]["date"]
list.append(Date)
date=set(list)
d1 = [{i: {"start_page": Start_page, "end_page": End_page,"date":date}}]
print(d1)
total_input_list=[{1:{"start_page":1,"end_page":None,"date":"10/12/2015"},
2:{"start_page":4,"end_page":None,"date":"12/12/2015"},
3:{"start_page":8,"end_page":None,"date":"22/1/2016"},
4:{"start_page":15,"end_page":None,"date":"22/1/2016"},
5:{"start_page":22,"end_page":None,"date":"22/1/2016"},
6:{"start_page":24,"end_page":None,"date":"20/12/2016"},
7:{"start_page":28,"end_page":None,"date":"26/2/2017"}}]
date_op(total_input_list)我看到了这个输出
[{1: {'date': {'10/12/2015'}, 'end_page': 3, 'start_page': 1}}]
[{2: {'date': {'10/12/2015', '12/12/2015'}, 'end_page': 7, 'start_page': 4}}]
[{3: {'date': {'22/1/2016', '10/12/2015', '12/12/2015'}, 'end_page': 14, 'start_page': 8}}]
[{4: {'date': {'22/1/2016', '10/12/2015', '12/12/2015'}, 'end_page': 21, 'start_page': 15}}]
[{5: {'date': {'22/1/2016', '10/12/2015', '12/12/2015'}, 'end_page': 23, 'start_page': 22}}]
[{6: {'date': {'22/1/2016', '10/12/2015', '12/12/2015', '20/12/2016'}, 'end_page': 27, 'start_page': 24}}]回答 3
Stack Overflow用户
回答已采纳
发布于 2017-11-21 13:41:25
因为迭代器在len(xy)之前停止
def date_op(total_input_list):
total_pages=36
list=[]
for xy in total_input_list:
for i in range(1,len(xy)+1):
Start_page=xy[i]["start_page"]
if(i<len(xy)):
End_page=xy[i+1]["start_page"]-1
Date = xy[i]["date"]
list.append(Date)
date=set(list)
d1 = [{i: {"start_page": Start_page, "end_page": End_page,"date":date}}]
print(d1)
total_input_list=[{1:{"start_page":1,"end_page":None,"date":"10/12/2015"},
2:{"start_page":4,"end_page":None,"date":"12/12/2015"},
3:{"start_page":8,"end_page":None,"date":"22/1/2016"},
4:{"start_page":15,"end_page":None,"date":"22/1/2016"},
5:{"start_page":22,"end_page":None,"date":"22/1/2016"},
6:{"start_page":24,"end_page":None,"date":"20/12/2016"},
7:{"start_page":28,"end_page":None,"date":"26/2/2017"}}]
date_op(total_input_list)Stack Overflow用户
发布于 2017-11-21 13:41:19
这看起来像一个经典的错位错误。
7时间戳定义了6个持续时间。
要输出第一行，请执行以下操作：
[{1: {'date': {'10/12/2015'}, 'end_page': 3, 'start_page': 1}}]您需要从dict的第一个和第二个值中获得信息。
Stack Overflow用户
发布于 2017-11-21 13:58:26
由于您要从下一个字段获得一个值，所以必须将下一个值从位置7设置为空，我假设最后一部分的end_page将为空，否则您所要做的就是更改next部分。
这解决了以下问题：
for i in range(1,len(xy)+1):
Start_page=xy[i]["start_page"]
try:
End_page=xy[i+1]["start_page"]-1 #from 1 to 6, the value comes from here
except:
End_page=None # when on field 7, value will come from here
Date = xy[i]["date"]
list.append(Date)
date=set(list)
d1 = [{i: {"start_page": Start_page, "end_page": End_page,"date":date}}]
print(d1)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/47414418
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