尝试编写一个方便的toString()方法,该方法列出对象的所有属性及其赋值。
class FooModel
{
func toString() -> String
{
var result = "[\(String(describing: type(of: self))) "
let mirror = Mirror(reflecting: self)
mirror.children.forEach
{
child in
result += "\(child.label): \(child.value), "
}
return "\(result)]"
}
}
class FooProject : FooModel
{
var id = 0
var name = ""
var announcement:String?
var showAnnouncement = false
var isCompleted = false
var completedOn:String?
var suiteMode = 0
var url = ""
}输出:
[FooProject Optional("id"): 0, Optional("name"): , Optional("announcement"): nil, Optional("showAnnouncement"): false, Optional("isCompleted"): false, Optional("completedOn"): nil, Optional("suiteMode"): 0, Optional("url"): , ]首先,它不列出实际值,而是列出默认值。为什么会这样呢?第二,有办法摆脱Optional封装吗?
发布于 2017-09-08 01:59:14
根据关于Child 这里的文档:
儿童
反射实例结构的一个元素。可选标签可在适当时使用,例如表示存储的属性或活动枚举的名称,并将用于在String传递给子代方法时进行查找。
因为镜像中的类型子类型定义为
typealias Child = (label: String?, value: Any)因此,所有的名字都被打印为选项。
若要获取标签名称,可以使用可选绑定。
我在操场上做了一些改动,并尝试过:
class FooModel
{
func toString() -> String
{
var result = "[\(String(describing: type(of: self))) "
let mirror = Mirror(reflecting: self)
mirror.children.forEach
{
child in
print(child)
if let label = child.label {
result += "\(label): \(child.value), "
}
}
return "\(result)]"
}
}
class FooProject : FooModel
{
var id = 0
var name = ""
var announcement:String!
var showAnnouncement = false
var isCompleted = false
var completedOn:String!
var suiteMode = 0
var url = ""
init(id: Int, name: String, completedOn: String) {
self.completedOn = completedOn
self.id = id
self.name = name
//...
}
}
let fooProj = FooProject(id: 10, name: "Name", completedOn: "Sunday")
print(fooProj.toString())最重要的是:
[FooProject id: 10, name: Name, announcement: nil, showAnnouncement: false, isCompleted: false, completedOn: Sunday, suiteMode: 0, url: , ]高..。
https://stackoverflow.com/questions/46107334
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