我对sql很陌生,而且对这个包非常新手。SQL正在沃森DashDB中运行。在过去的几个小时里,我一直在努力寻找正确的代码。
下面的代码只创建2列,我需要4。SPACEX_SENTIMENTS.SENTIMENT_POLARITY包含负和正。
CREATE VIEW SENTIMENT
AS
(SELECT SPACEX_TWEETS.USER_SCREEN_NAME, SPACEX_SENTIMENTS.SENTIMENT_POLARITY
FROM dash015214.SPACEX_TWEETS
LEFT JOIN dash015214.SPACEX_SENTIMENTS ON
SPACEX_TWEETS.MESSAGE_ID=SPACEX_SENTIMENTS.MESSAGE_ID);
SELECT USER_SCREEN_NAME, COUNT(1) tweetsCount
FROM dash015214.SENTIMENT
GROUP BY USER_SCREEN_NAME
HAVING COUNT (1)>1
ORDER BY COUNT (USER_SCREEN_NAME) DESC
FETCH FIRST 20 ROWS ONLY;发布于 2017-03-04 14:31:32
您的视图SENTIMENT每条推特有一行,有两列:用户名,然后是极性列。从您的评论中,我假设极性列可以具有“正”或“负”的值。我认为你可以通过这个查询得到你想要的东西:
SELECT
USER_SCREEN_NAME,
COUNT(1) AS "Total Tweets",
COUNT(CASE SENTIMENT_POLARITY WHEN 'POSITIVE' THEN 1 ELSE NULL END) AS "Positive Tweets",
COUNT(CASE SENTIMENT_POLARITY WHEN 'NEGATIVE' THEN 1 ELSE NULL END) AS "Negative Tweets"
FROM
SENTIMENT
GROUP BY USER_SCREEN_NAME
HAVING COUNT(1) > 1
ORDER BY COUNT(1) DESC;这将给每个人至少2条推文(这是你想要的吗?),并告诉你每个用户的推文数量,有多少条是肯定的,有多少条是否定的。用任何用于指示列名的SQL替换"。
https://stackoverflow.com/questions/42596070
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