我来自MySQL,所以我像这样设计parse.com表
Vehicle | license, year, & pool_id
Pool | address & city_id
City | namePool_id在车辆指针中指向池,City_id在池中指向城市。
在mySQL中,我们可以连接三个表并使用where子句。
在关系查询中,docs说
-数据-urlencode‘where={“Post”:{“__type”:“指针”,"className":"Post","objectId":"8TOXdXf3tz"}}’
基于对象id的查询关系1表
我如何查询到车辆在哪里城市名称=“某些人”?
发布于 2016-11-17 01:08:57
在angularJS中
var config = {
params: {
where: {
vehicle_year: "2013",
pool_id: {
$inQuery: {
where: {
city_id: {
$inQuery: {
where: {
city_name: "Jakarta"
},
className: "city"
}
}
//pool_address: "JL. DEF"
},
className: "pool"
}
},
car_id: {
$inQuery: {
where: {
car_class_id: {
$inQuery: {
where: {
name: "Box"
},
className: "car_class"
}
}
},
className: "car"
}
}
},
include: 'pool_id.city_id,car_id.car_class_id',
},
headers: { 'X-Parse-Application-Id' : 'gMKfl1wDyk3m6I5x0IrIjJyI87sumz58' }
};然后
$http.get('http://ip/parse/classname', config).then(function(response){
}, function(error){
});https://stackoverflow.com/questions/40603473
复制相似问题