10名学生输入C++ GPA Trunc
10名学生输入C++ GPA Trunc
提问于 2016-02-22 02:58:04
我可以输入第一个学生，但是，一旦我请求第二个学生的输入，它就不接受：getline(cin, s2) on to getline(cin,s10)。请您帮助我理解错误发生在哪里，或者为什么输出不遵循与s1/GPA1相同的格式？
这是我的代码：
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
int main()
{
//Welcome
cout << "Welcome to your personal GPA Calculator! \n" << endl;
float GPA1, GPA2, GPA3, GPA4, GPA5, GPA6, GPA7, GPA8, GPA9, GPA10 = 0;
string s1, s2, s3, s4, s5, s6, s7, s8, s9, s10;
//Requesting User Input
cout << "Student One| Please enter your Last Name, First Name: " << endl;
getline(cin, s1);
cout << "What is your current GPA: " << endl;
cin >> GPA1;
cout << endl;
cout << "Student Two| Please enter your Last Name, First Name: " << endl;
getline(cin, s2);
cout << "What is your current GPA: " << endl;
cin >> GPA2;
cout << endl;
cout << "Student Three| Please enter your Last Name, First Name: " << endl;
getline(cin, s3);
cout << "What is your current GPA: " << endl;
cin >> GPA3;
cout << endl;
cout << "Student Four| Please enter your Last Name, First Name: " << endl;
getline(cin, s4);
cout << "What is your current GPA: " << endl;
cin >> GPA4;
cout << endl;
cout << "Student Five| Please enter your Last Name, First: " << endl;
getline(cin, s5);
cout << "What is your current GPA: " << endl;
cin >> GPA5;
cout << endl;
cout << "Student Six| Please enter your Last Name, First Name: " << endl;
getline(cin, s6);
cout << "What is your current GPA: " << endl;
cin >> GPA6;
cout << endl;
cout << "Student Seven| Please enter your Last Name, First Name: " << endl;
getline(cin, s7);
cout << "What is your current GPA: " << endl;
cin >> GPA7;
cout << endl;
cout << "Student Eight| Please enter your Last Name, First Name: " << endl;
getline(cin, s8);
cout << "What is your current GPA: " << endl;
cin >> GPA8;
cout << endl;
cout << "Student Nine| Please enter your Last Name, First Name: " << endl;
getline(cin, s9);
cout << "What is your current GPA: " << endl;
cin >> GPA9;
cout << endl;
cout << "Student Ten| Please enter your Last Name, First Name: " << endl;
getline(cin, s10);
cout << "What is your current GPA: " << endl;
cin >> GPA10;
cout << endl;
//Store in Tabular Format
cout << ("Student Name| \t\t |Student GPA Value \n");
cout << ("____________________________________________\n");
std::cout << s1 << "\t\t " << std::setprecision(2) << std::fixed << GPA1 << endl;
std::cout << s2 << "\t\t " << std::setprecision(2) << std::fixed << GPA2 << endl;
std::cout << s3 << "\t\t " << std::setprecision(2) << std::fixed << GPA3 << endl;
std::cout << s4 << "\t\t " << std::setprecision(2) << std::fixed << GPA4 << endl;
std::cout << s5 << "\t\t " << std::setprecision(2) << std::fixed << GPA5 << endl;
std::cout << s6 << "\t\t " << std::setprecision(2) << std::fixed << GPA6 << endl;
std::cout << s7 << "\t\t " << std::setprecision(2) << std::fixed << GPA7 << endl;
std::cout << s8 << "\t\t " << std::setprecision(2) << std::fixed << GPA8 << endl;
std::cout << s9 << "\t\t " << std::setprecision(2) << std::fixed << GPA9 << endl;
std::cout << s10 << "\t\t " << std::setprecision(2) << std::fixed << GPA10 << endl;
return (0);
}回答 2
Stack Overflow用户
回答已采纳
发布于 2016-02-22 03:14:41
您通常不希望直接用cin读取数字以供交互使用。它对换行符不太好--把换行符留给下一个条目。在本例中，您将得到person 2的空白名称。
试试这个：
string temp;
//Requesting User Input
cout << "Student One| Please enter your Last Name, First Name: " << endl;
getline(cin, s1);
cout << "What is your current GPA: " << endl;
getline(cin, temp);
GPA1 = strtof(temp.c_str(), 0);
cout << endl;Stack Overflow用户
发布于 2016-02-22 03:13:11
当您混合cin和getline(cin，"string")时，您必须小心。Cin将忽略任何空空格或行，而getline则不会。所发生的是，在输入第一个学生的GPA后，换行符被存储在缓冲区中，并被转到自动输入的getline中。尝试在每个cin cin.ignore gpa之后使用cin.ignore()。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/35545100
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