我有下表documents
+--------+-------------+------------+----------+---------+
| doc_id | module_name | mapping_id | doc_type | version |
+--------+-------------+------------+----------+---------+
| 5 | asdf | asd | POI | 1 |
| 6 | asdf | asd | POI | 2 |
| 7 | asdf | asd | CAF | 1 |
| 8 | asdf | abc | POI | 1 |
| 9 | asdf | abc | ISR | 1 |
| 10 | asdf | abc | ISR | 2 |
| 11 | asdf | xyz | POA | 1 |
| 12 | asdf | xyz | CAF | 1 |
| 13 | asdf | xyz | CAF | 2 |
| 14 | asdf | xyz | CAF | 3 |
| 15 | pqrs | asd | POI | 1 |
| 16 | pqrs | asd | POI | 2 |
| 17 | pqrs | asd | CAF | 1 |
| 18 | pqrs | abc | POI | 1 |
| 19 | pqrs | abc | ISR | 1 |
| 20 | pqrs | abc | ISR | 2 |
| 21 | pqrs | xyz | POA | 1 |
| 22 | pqrs | xyz | CAF | 1 |
| 23 | pqrs | xyz | CAF | 2 |
| 24 | pqrs | xyz | CAF | 3 |
+--------+-------------+------------+----------+---------+我想得到的结果是:
+--------+-------------+------------+----------+---------+
| doc_id | module_name | mapping_id | doc_type | version |
+--------+-------------+------------+----------+---------+
| 6 | asdf | asd | POI | 2 |
| 7 | asdf | asd | CAF | 1 |
| 8 | asdf | abc | POI | 1 |
| 10 | asdf | abc | ISR | 2 |
| 11 | asdf | xyz | POA | 1 |
| 14 | asdf | xyz | CAF | 3 |
| 16 | pqrs | asd | POI | 2 |
| 17 | pqrs | asd | CAF | 1 |
| 18 | pqrs | abc | POI | 1 |
| 20 | pqrs | abc | ISR | 2 |
| 21 | pqrs | xyz | POA | 1 |
| 24 | pqrs | xyz | CAF | 3 |
+--------+-------------+------------+----------+---------+其中,max版本号行应结合module_name、mapping_id和doc_type返回。
我想不出这个查询。需要帮助。
发布于 2016-02-20 13:00:18
在大多数数据库中,您将使用row_number()。在MySQL中,这是不可用的。一种方法是join和group by。
select t.*
from t join
(select module_name, mapping_id, doc_type, max(version) as version
from t
group by module_name, mapping_id, doc_type
) tt
using (module_name, mapping_id, doc_type, version);如果我们把OP的话当真的话,或者可能只是
select t.*
from t join
(select doc_type, max(version) as version
from t
group by doc_type
) tt
using (doc_type, version);发布于 2016-02-20 13:05:15
另一种选择
select *
from documents d
where not exists
(
select 1 from documents dv
where dv.doc_type = d.doc_type
and dv.version > d.version
)字面意思:“对于相同的值,没有更大的版本号”
https://stackoverflow.com/questions/35523573
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