我有一个包含事务的表,其中的列是id、created_at和company_id。我想对每个公司的四个第一次事务进行分组,并在每一行上返回每个事务的created_at值。
换句话说,我希望输出的每一行对应于每个公司的四个最初事务(按company_id分组),列显示这四个事务的company_id和created_at。
我该怎么做?
样本数据:
id | company_id | created_at
---------------------------------
1123 | abcd | 10/12/2015
8291 | abcd | 10/14/2015
9012 | abcd | 10/15/2015
9540 | abcd | 10/16/2015
10342 | abcd | 10/21/2015
10456 | abcd | 10/22/2015
2301 | efgh | 10/13/2015
4000 | efgh | 11/01/2015
4023 | efgh | 11/03/2015
6239 | efgh | 11/08/2015
7500 | efgh | 11/14/2015样本输出:
company_id | created_at_1 | created_at_2 | created_at_3 | created_at_4
--------------------------------------------------------------------------
abcd | 10/12/2015 | 10/14/2015 | 10/15/2015 | 10/16/2015
efgh | 10/13/2015 | 11/01/2015 | 11/03/2015 | 11/08/2015发布于 2016-01-22 15:56:12
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,company_id VARCHAR(12) NOT NULL
,created_at DATE NOT NULL
);
INSERT INTO my_table VALUES
( 1123,'abcd','2015/10/12'),
( 8291,'abcd','2015/10/14'),
( 9012,'abcd','2015/10/15'),
( 9540,'abcd','2015/10/16'),
(10342,'abcd','2015/10/21'),
(10456,'abcd','2015/10/22'),
( 2301,'efgh','2015/10/13'),
( 4000,'efgh','2015/11/01'),
( 4023,'efgh','2015/11/03'),
( 6239,'efgh','2015/11/08'),
( 7500,'efgh','2015/11/14');
SELECT x.*
FROM my_table x
JOIN my_table y
ON y.company_id = x.company_id
AND y.created_at <= x.created_at
GROUP
BY x.id
HAVING COUNT(*) <= 4
ORDER
BY company_id
, created_at;
+------+------------+------------+
| id | company_id | created_at |
+------+------------+------------+
| 1123 | abcd | 2015-10-12 |
| 8291 | abcd | 2015-10-14 |
| 9012 | abcd | 2015-10-15 |
| 9540 | abcd | 2015-10-16 |
| 2301 | efgh | 2015-10-13 |
| 4000 | efgh | 2015-11-01 |
| 4023 | efgh | 2015-11-03 |
| 6239 | efgh | 2015-11-08 |
+------+------------+------------+有变量的解决方案会更快,例如.
SELECT a.id
, a.company_id
, a.created_at
FROM
( SELECT x.*
, CASE WHEN @prev = x.company_id THEN @i:=@i+1 ELSE @i:=1 END i, @prev:=x.company_id prev
FROM my_table x
, (SELECT @i:=1,@prev:=null) vars
ORDER
BY x.company_id
, x.created_at
) a
WHERE i <= 4;发布于 2016-01-22 15:17:52
一种可能的办法是:
select company_id,
min(created_at) as created_at_1,
(select created_at from t where company_id=t1.company_id order by created_at limit 1 offset 1) as created_at_2,
(select created_at from t where company_id=t1.company_id order by created_at limit 1 offset 2) as created_at_3,
(select created_at from t where company_id=t1.company_id order by created_at limit 1 offset 3) as created_at_4
from t as t1
group by company_id编辑:
另一种可能(受this answer启发)是:
select company_id,
min(created_at) as created_at_1,
min(case r when 2 then created_at else null end) as created_at_2,
min(case r when 3 then created_at else null end) as created_at_3,
min(case r when 4 then created_at else null end) as created_at_4
from (
select company_id, created_at,
(case company_id when @curType
then @curRank := @curRank + 1
else @curRank := 1 and @curType := company_id end)+1 as r
from t, (select @curRank := 0, @curType := '') f
order by company_id, created_at
) as o
where r <= 4
group by company_id发布于 2016-01-22 17:09:32
像这样可以吗?
SELECT S.company_id,
A.created_at created_at_1,
B.created_at created_at_2,
C.created_at created_at_3,
D.created_at created_at_4
FROM sample S
LEFT JOIN sample A on S.company_id = A.company_id AND A.id NOT IN(S.id)
LEFT JOIN sample B on S.company_id = B.company_id AND B.id NOT IN(S.id, A.id)
LEFT JOIN sample C on S.company_id = C.company_id AND C.id NOT IN(S.id, A.id, B.id)
LEFT JOIN sample D on S.company_id = D.company_id AND D.id NOT IN(S.id, A.id, B.id, C.id)
GROUP BY S.company_idhttp://sqlfiddle.com/#!9/c577e/3
不过,这可能不是很有效率。
因为你的美国日期格式不好排序,所以它们是不合适的。最好切换到时间戳格式。
https://stackoverflow.com/questions/34947833
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