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社区首页 >问答首页 >对四行sql进行分组。

对四行sql进行分组。
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Stack Overflow用户
提问于 2016-01-22 13:27:53
回答 3查看 64关注 0票数 0

我有一个包含事务的表,其中的列是idcreated_atcompany_id。我想对每个公司的四个第一次事务进行分组,并在每一行上返回每个事务的created_at值。

换句话说,我希望输出的每一行对应于每个公司的四个最初事务(按company_id分组),列显示这四个事务的company_id和created_at。

我该怎么做?

样本数据:

代码语言:javascript
复制
  id  | company_id | created_at
---------------------------------
 1123 |    abcd    | 10/12/2015
 8291 |    abcd    | 10/14/2015
 9012 |    abcd    | 10/15/2015
 9540 |    abcd    | 10/16/2015
10342 |    abcd    | 10/21/2015
10456 |    abcd    | 10/22/2015
 2301 |    efgh    | 10/13/2015
 4000 |    efgh    | 11/01/2015
 4023 |    efgh    | 11/03/2015
 6239 |    efgh    | 11/08/2015
 7500 |    efgh    | 11/14/2015

样本输出:

代码语言:javascript
复制
  company_id | created_at_1 | created_at_2 | created_at_3 | created_at_4
--------------------------------------------------------------------------
     abcd    |  10/12/2015  |  10/14/2015  |  10/15/2015  |  10/16/2015
     efgh    |  10/13/2015  |  11/01/2015  |  11/03/2015  |  11/08/2015
EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2016-01-22 15:56:12

代码语言:javascript
复制
DROP TABLE IF EXISTS my_table;

CREATE TABLE my_table
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,company_id VARCHAR(12) NOT NULL
,created_at DATE NOT NULL
);

INSERT INTO my_table VALUES
( 1123,'abcd','2015/10/12'),
( 8291,'abcd','2015/10/14'),
( 9012,'abcd','2015/10/15'),
( 9540,'abcd','2015/10/16'),
(10342,'abcd','2015/10/21'),
(10456,'abcd','2015/10/22'),
( 2301,'efgh','2015/10/13'),
( 4000,'efgh','2015/11/01'),
( 4023,'efgh','2015/11/03'),
( 6239,'efgh','2015/11/08'),
( 7500,'efgh','2015/11/14');

SELECT x.* 
  FROM my_table x 
  JOIN my_table y 
    ON y.company_id = x.company_id 
   AND y.created_at <= x.created_at 
 GROUP 
    BY x.id 
HAVING COUNT(*) <= 4 
 ORDER 
    BY company_id
     , created_at;
+------+------------+------------+
| id   | company_id | created_at |
+------+------------+------------+
| 1123 | abcd       | 2015-10-12 |
| 8291 | abcd       | 2015-10-14 |
| 9012 | abcd       | 2015-10-15 |
| 9540 | abcd       | 2015-10-16 |
| 2301 | efgh       | 2015-10-13 |
| 4000 | efgh       | 2015-11-01 |
| 4023 | efgh       | 2015-11-03 |
| 6239 | efgh       | 2015-11-08 |
+------+------------+------------+

有变量的解决方案会更快,例如.

代码语言:javascript
复制
SELECT a.id
     , a.company_id
     , a.created_at
  FROM 
     ( SELECT x.*
            , CASE WHEN @prev = x.company_id THEN @i:=@i+1 ELSE @i:=1 END i, @prev:=x.company_id prev 
         FROM my_table x
            , (SELECT @i:=1,@prev:=null) vars 
        ORDER 
           BY x.company_id
            , x.created_at
     ) a
 WHERE i <= 4;
票数 1
EN

Stack Overflow用户

发布于 2016-01-22 15:17:52

一种可能的办法是:

代码语言:javascript
复制
select company_id, 
    min(created_at) as created_at_1,
    (select created_at from t where company_id=t1.company_id order by created_at limit 1 offset 1) as created_at_2,
    (select created_at from t where company_id=t1.company_id order by created_at limit 1 offset 2) as created_at_3,
    (select created_at from t where company_id=t1.company_id order by created_at limit 1 offset 3) as created_at_4
from t as t1
group by company_id

编辑:

另一种可能(受this answer启发)是:

代码语言:javascript
复制
select company_id, 
    min(created_at) as created_at_1,
    min(case r when 2 then created_at else null end) as created_at_2,
    min(case r when 3 then created_at else null end) as created_at_3,
    min(case r when 4 then created_at else null end) as created_at_4
from (
    select company_id, created_at,
        (case company_id when @curType 
        then @curRank := @curRank + 1
        else @curRank := 1 and @curType := company_id end)+1 as r
    from t, (select @curRank := 0, @curType := '') f
    order by company_id, created_at
) as o
where r <= 4
group by company_id
票数 0
EN

Stack Overflow用户

发布于 2016-01-22 17:09:32

像这样可以吗?

代码语言:javascript
复制
   SELECT S.company_id,
          A.created_at created_at_1,
          B.created_at created_at_2,
          C.created_at created_at_3,
          D.created_at created_at_4
     FROM sample S
LEFT JOIN sample A on S.company_id = A.company_id AND A.id NOT IN(S.id)
LEFT JOIN sample B on S.company_id = B.company_id AND B.id NOT IN(S.id, A.id)
LEFT JOIN sample C on S.company_id = C.company_id AND C.id NOT IN(S.id, A.id, B.id)
LEFT JOIN sample D on S.company_id = D.company_id AND D.id NOT IN(S.id, A.id, B.id, C.id)
 GROUP BY S.company_id

http://sqlfiddle.com/#!9/c577e/3

不过,这可能不是很有效率。

因为你的美国日期格式不好排序,所以它们是不合适的。最好切换到时间戳格式。

票数 -1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/34947833

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