我用Filestream来保存我的android游戏的分数。最近,我决定增加额外的等级。对于这些级别,我需要跟踪多种类型的分数。下面是我对一个变量的代码:
function writePion(): void { //First function to create/write in the file
var pion: Object = new Object();
pion.value = numeroPion; //value of object = variable value
trace("Pion (writeObject value)= " + pion.value);
var file2: File = File.applicationStorageDirectory.resolvePath("pion.menes");
var fileStream2: FileStream = new FileStream();
fileStream2.open(file2, FileMode.WRITE);
fileStream2.writeObject(pion);
fileStream2.close();
};
function readPion(): void { //second function to read the file and modify the variable.
var file2: File = File.applicationStorageDirectory.resolvePath("pion.menes");
if (!file2.exists) {
return;
}
var fileStream2: FileStream = new FileStream();
fileStream2.open(file2, FileMode.READ);
var pion: Object = fileStream2.readObject();
numeroPion = pion.value; //update the variable
trace("pion (readObject value)= " + numeroPion)
fileStream2.close();
};我想知道的是,我是否必须在每种类型的分数中设置一个函数,或者是否有一种方法来调整它以保存(大约10个)新变量?谢了:)杰瑞尔。
发布于 2015-02-07 18:16:20
如果filestream.writeObject()可以写入任何对象,则可以使用以下语法定义和分配其中的任意数量的字段:
var pion:Object = { value: numeroPion, value2: numeroPion2, some_other_value: numeroPionSomeOther }; // and so on你可以读取这些值
numeroPion = pion.value;
numeroPion2 = pion.value2;
// ... and so onhttps://stackoverflow.com/questions/28380404
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