第一次尝试Powershell v3中的自定义对话框。我想在表单中添加一个浏览按钮。我有它,所以它显示了浏览按钮,但我似乎找不出从OpenFileDialog对象获取文件名并将其显示在objTextBox字段中的部分。我已经研究过了,但似乎找不到任何文章来解释这一过程。
$objTextBox = New-Object System.Windows.Forms.TextBox
$objTextBox.Name = 'Text1'
$objTextBox.Location = New-Object System.Drawing.Size(10,40)
$objTextBox.Size = New-Object System.Drawing.Size(260,20)
$objForm.Controls.Add($objTextBox)
#File Browser Code.
$FileBrowser = New-Object System.Windows.Forms.OpenFileDialog -Property @{
InitialDirectory = [Environment]::GetFolderPath('Desktop')
}
$browse_button = New-Object system.Windows.Forms.Button
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75)
$browse_button.Size = New-Object System.Drawing.Size(100,27)
$browse_button.Add_Click({[void]$FileBrowser.ShowDialog()})
$objForm.Controls.Add($browse_button)发布于 2015-02-03 21:31:11
我想我会稍微换一种方式。我会创建一个显示Browse对话框并输出一个字符串的函数(刚好放在手上)。然后,对于Add_Click设置textbox的值=函数。类似于:
Function Get-FilePath{
[CmdletBinding()]
Param(
[String]$Filter = "|*.*",
[String]$InitialDirectory = "C:\")
[void][System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms")
$OpenFileDialog = New-Object System.Windows.Forms.OpenFileDialog
$OpenFileDialog.initialDirectory = $InitialDirectory
$OpenFileDialog.filter = $Filter
[void]$OpenFileDialog.ShowDialog()
$OpenFileDialog.filename
}
$objTextBox = New-Object System.Windows.Forms.TextBox
$objTextBox.Name = 'Text1'
$objTextBox.Location = New-Object System.Drawing.Size(10,40)
$objTextBox.Size = New-Object System.Drawing.Size(260,20)
$objForm.Controls.Add($objTextBox)
$browse_button = New-Object system.Windows.Forms.Button
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75)
$browse_button.Size = New-Object System.Drawing.Size(100,27)
$browse_button.Add_Click({$objTextBox.Text = Get-FilePath -InitialDirectory "$env:UserProfile\Desktop"})
$objForm.Controls.Add($browse_button)
$browse_button.Text = "Choose...."
$browse_button.Location = New-Object System.Drawing.Size(10,75)
$browse_button.Size = New-Object System.Drawing.Size(100,27)
$browse_button.Add_Click({[void]$FileBrowser.ShowDialog()})
$objForm.Controls.Add($browse_button) https://stackoverflow.com/questions/28306339
复制相似问题