我尝试在SWI Prolog中实现简单的专家系统。本系统从键盘读取输入数据,并查找语言。这是我的代码:
/* Paradigms */
paradigm('Ada', 'Imperative').
paradigm('C', 'Imperative').
/* Typization */
typization('Ada', 'Statical').
typization('C', 'Explicit').
/* Compiler */
compiler('Ada', 'OpenSource').
compiler('C', 'DebugPosibility').
/* Memory */
memory('Ada', 'Stack').
memory('C', 'Pointer').
language(L, P, T, C, M) :- paradigm(L, P), typization(L, T), compiler(L, C), memory(L, M).
run :- write('\nChoose language paradigm:\n1. imperative\n2. object-oriented\n3. distributed\n4. reflexive\n5. declarative\n6. functional\n7. general programming\n'), read(P),
write('\n\nChoose typization:\n1. statical\n2. explicit\n3. polymorfism\n4. runtime type information\n5. dynamical\n6. implicit\n7. cast without data lose\n8. implicit cast without data lose\n9. argument output at method call\n'), read(T),
write('\n\nChoose compiler type:\n1. open-source\n2. debug posibility\n3. bootstrapping\n4. multithreading compilation\n5. conditional compilation\n6. command line interpreter\n'), read(C),
write('\n\nChoose memory management type:\n1. stack\n2. pointer\n3. manual memory management\n4. garbage collector\n'), read(M),
language(L, P, T, C, M),
write(L).当我运行这个程序时,我总是接收所有的语言。但是在我的测试用例中,它应该只得到一种语言。语言是可以接受的,当来自语言的所有四个谓词返回相同语言L的真时,我的错误在哪里,我如何修复它?
非常感谢!
发布于 2014-12-19 00:09:48
错误存在于输入捕获的某个位置(特别是,用户被要求输入一个与程序实际期望不符的字符串;请注意这里)。如果使用原子并删除单个引用,则有两个测试用例的程序会读到:
paradigm(ada, imperative).
paradigm(c, imperative).
typization(ada, statical).
typization(c, explicit).
compiler(ada, openSource).
compiler(c, debugPosibility).
memory(ada, stack).
memory(c, pointer).
language(L, P, T, C, M) :- paradigm(L, P), typization(L, T), compiler(L, C), memory(L, M).
test1(L) :- language(L, imperative, statical, openSource, stack).
test2(L,P) :- language(L, P, statical, openSource, stack).运行test1(L)只生成L=ada,运行test2(L,P)只产生L=ada, P=imperative,这是必要的。
https://stackoverflow.com/questions/27557592
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