我有两个桌子,第一个名叫table1
ID | Name | Type | isActive | isDeleted |
-----------------------------------------------
1 | item 1 | 4 | 1 | 0 |
2 | item 2 | 2 | 1 | 0 |
3 | item 3 | 1 | 1 | 1 |
4 | item 4 | 1 | 1 | 0 |
5 | item 5 | 1 | 1 | 0 |
6 | item 6 | 3 | 1 | 0 |
7 | item 7 | 1 | 1 | 0 |
8 | item 8 | 2 | 1 | 0 |
9 | item 9 | 1 | 1 | 0 |
10 | item 10 | 1 | 1 | 0 |第二个名为table1_meta
ID | table1_id | options | value
------------------------------------
1 | 1 | dont_ask | 1
2 | 2 | dont_ask | 1
3 | 5 | dont_ask | 1
4 | 6 | dont_ask | 1
5 | 8 | alwasys_ask| 1
6 | 9 | alwasys_ask| 1
7 | 1 | is_flagged | 1
8 | 2 | is_flagged | 0
9 | 3 | is_flagged | 0
10 | 4 | is_flagged | 0
11 | 5 | is_flagged | 0
12 | 6 | is_flagged | 1
13 | 7 | is_flagged | 0
14 | 8 | is_flagged | 0
15 | 9 | is_flagged | 0
16 | 10 | is_flagged | 0我试图在满足某些特定条件的table1中计算行,其中一些条件。
WHERE条件必须包含以下条件:
table1.type = 1 and table1.isActive = 1 and table1.isDeleted = 0 and table1_meta.options = 'is_flagged' and table1_meta.value = 0这是:
table1_meta.options = 'dont_ask' and table1_meta.value = 1这是:
table1_meta.options = 'always_ask' and table1_meta.value = 1那我该怎么做呢?
SQLFiddle链接:http://sqlfiddle.com/#!2/2eb27b
谢谢。
发布于 2014-09-22 22:04:06
我想我找到了问题的答案。
查询是:
SELECT Count(*) AS total FROM
(SELECT Count(*)
FROM table1 t1,
table1_meta t1meta
WHERE t1.type = 1
AND t1.isactive = 1
AND t1.isdeleted = 0
AND t1meta.options = 'is_flagged'
AND t1meta.value = 0
AND t1.id NOT IN (SELECT table1_id
FROM table1_meta tm
WHERE tm.options = 'dont_ask'
AND tm.value = 1)
UNION
SELECT Count(*)
FROM table1_meta tm,
table1 t1
WHERE t1.id = tm.table1_id
AND tm.options = 'always_ask'
AND tm.value = 1) x不管怎样,谢谢,戈登。
发布于 2014-09-21 16:13:05
我假设您正在尝试计算第一个表中的行数。下面是一种使用子查询的方法:
select count(*)
from table1 t1
where t1.type = 1 and t1.isActive = 1 and t1.IsDeleted = 0 and
exists (select 1
from table1_meta tm
where t1.id = tm.table1_id and tm.options = 'is_flagged' and tm.value = 0
) and
not exists (select 1
from table1_meta tm
where t1.id = tm.table1_id and
tm.options = 'dont_ask' and tm.value = 1
) and
exists (select 1
from table1_meta tm
where t1.id = tm.table1_id and
tm.options = 'always_ask' and tm.value = 1
);这对于元表上的每个条件都有一个单独的子查询。
https://stackoverflow.com/questions/25961140
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