在下面的引导程序3的代码中,我试图使第三列不堆栈。我希望它始终保持右上,就像左大多数列保持左上角一样。有简单的方法吗?我想把这个部分排除在引导程序之外,只需要应用css向右浮动,但是在Bootstrap中,我肯定可以做到这一点。
<header id="t3-header" class="container t3-header">
<div class="row">
<!-- LOGO -->
<div class="col-xs-12 col-md-2 logo"> I stay always top left</div>
<div class="col-xs-12 col-md-8"> I should stackunder 1st column as browser resizes </div>
<!-- I want this column to not stack below column 2 as the browser resizes. -->
<div class="col-xs-12 col-md-2">
I should always stay top right
<div class="row">
<div class="col-lg-6"> </div>
<div class="col-lg-6"> </div>
</div>
</div>
</div>
发布于 2014-05-30 11:30:49
如果我对你的理解是正确的,你必须让“右上角”的div,首先出现在级联中。要做到这一点,首先将其作为第一列,然后可以使用pull-left和pull-right助手类来欺骗前两列:
其次,可以在示例中删除col-xs-12:
<header id="t3-header" class="container t3-header">
<div class="row">
<div class="col-md-2 pull-right">
I should always stay top right
<div class="row">
<div class="col-lg-6"></div>
<div class="col-lg-6"></div>
</div>
</div>
<!-- LOGO -->
<div class="col-sm-12 col-md-2 logo pull-left">
I stay always top left
</div>
<div class="col-sm-12 col-md-8 pull-left">
I should stackunder 1st column as browser resizes
</div>
</div>
</div>示例: http://www.bootply.com/ee3E67pujY
https://stackoverflow.com/questions/23953417
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