问为什么整数的地址指针有8个符号，整数二进制地址位置有8位？

EN

#include "stdafx.h"
#include <stdio.h>
#include <string.h>     /* strcat */
#include <stdlib.h>     /* strtol */


const char *byte_to_binary(int x)  //code taken from-https://stackoverflow.com/questions/111928/is-there-a-printf-converter-to-print-in-binary-format
{
    static char b[9];
    b[0] = '\0';

    int z;
    for (z = 128; z > 0; z >>= 1)
    {
        strcat(b, ((x & z) == z) ? "1" : "0");
    }

    return b;
}

int main(void) //my code starts here
{
    int A = 0;
    int *Ap = &A;
    unsigned int number = (unsigned int)Ap;

    printf("%s \t %d \n \n","int Value",A); //prints the value stored in Ap as an integer

    printf("%s \t %s \n \n","bin Value",byte_to_binary(A)); //prints the value stored in Ap as a binary number 

    printf("%s \t %p \n \n","adress Pointer",Ap); //prints pointer address as pointer type

    printf("%s \t \t %s \n \n","adress",byte_to_binary(number)); //prints pointer address in binary


    return 0;
}

int Value        0

bin Value        00000000

adress Pointer   003FFE1C

adress           00011100

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