blocks|key|709829|text|您可以使用Split并获得如下所示的号码：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|709830|string+Location+=+"1120+-+Main+Road";
int+number+=+int.Parse(Location.Split()[0]);|code-block|syntax|javascript|709831|如果在number.If之前没有空白，那么就可以使用StringSplitOptions.RemoveEmptyEntries了。|709832|int+number+=+int.Parse(Location.Split(new+[]{+'+'+},+
++++++++++++++StringSplitOptions.RemoveEmptyEntries)[0]);|709833|entityMap^0|5|5|0|0|Q|11|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|P|$]]

You can use <code>Split</code> and get your number like this:

<pre><code>string Location = "1120 - Main Road";
int number = int.Parse(Location.Split()[0]);
</code></pre>

This should work if there is no white-space before the number.If there is then use <code>StringSplitOptions.RemoveEmptyEntries</code>:

<pre><code>int number = int.Parse(Location.Split(new []{ ' ' }, 
 StringSplitOptions.RemoveEmptyEntries)[0]);
</code></pre>

blocks|key|1430490|text|您可以使用String.Split()函数根据-来拆分字符串，然后如果希望将字符串的第一部分转换为整数，则可以将其转换为整数变量。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1430491|解决方案1:如果希望将字符串的第一部分作为字符串获取，则为。|BOLD|1430492|string+Location+=+"11056+-+Main+Road";
Location+=+Location.Split('-')[0].Trim();|code-block|syntax|javascript|1430493|解决方案2:如果要将字符串的第一部分作为整数值获取，则为。|1430494|string+Location+=+"11056+-+Main+Road";
int+num;
int.TryParse(Location.Split('-')[0],out+num);|1430495|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.string.split%2528v=vs.110%2529.aspx^0|5|E|N|1|5|E|0|0|0|T|0|0|0|S|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|F|3|G|5|6|7|17|8|@$9|18|A|19|B|H]]|D|@]|E|$]]|$1|I|3|J|5|K|7|1A|8|@]|D|@]|E|$L|M]]|$1|N|3|O|5|6|7|1B|8|@$9|1C|A|1D|B|H]]|D|@]|E|$]]|$1|P|3|Q|5|K|7|1E|8|@]|D|@]|E|$L|M]]|$1|R|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|S|$T|$5|U|V|W|E|$X|Y]]]]

You can use <a href="http://msdn.microsoft.com/en-us/library/system.string.split%28v=vs.110%29.aspx" rel="nofollow"><code>String.Split()</code></a> function to split your string based on delimeter <code>-</code> and then you can convert the first part of the string into integer if you want it in a Integer variable.

Solution 1: if you want to get first part of string as as string.

<pre><code>string Location = "11056 - Main Road";
Location = Location.Split('-')[0].Trim();
</code></pre>

Solution 2: if you want to get the first part of the string as integer value.

<pre><code>string Location = "11056 - Main Road";
int num;
int.TryParse(Location.Split('-')[0],out num);
</code></pre>

blocks|key|709847|text|在空格上分开，然后先拿起任何东西，忽略其余的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|709848|string+GrabNumber(string+input)
{
++++return+input.Split('+')[0];
}|code-block|syntax|javascript|709849|假设您希望它是一个整数，那么您可以更进一步：|709850|int+GrabNumber(string+input)
{
++++return+int.Parse(input.Split('+')[0]);
}|709851|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

split on spaces, then grab whatever is first, ignore the rest.

<pre><code>string GrabNumber(string input)
{
 return input.Split(' ')[0];
}
</code></pre>

assuming you want it as an integer you can take it a step further:

<pre><code>int GrabNumber(string input)
{
 return int.Parse(input.Split(' ')[0]);
}
</code></pre>

blocks|key|709933|text|只需将子串调用与String.IndexOf一起使用，例如|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|709934|using+System;
using+System.Collections.Generic;
public+class+Test
{
++++public+static+void+Main()
++++{

++++++++List<string>+strings++=+new+List<string>();
++++++++strings.Add("110+-+Main+Road");
++++++++strings.Add("1104+-+Main+Road");
++++++++strings.Add("11088+-+Main+Road");

++++++++foreach(string+s+in+strings){
++++++++++++Console.WriteLine(s.Substring(0,s.IndexOf("-",0)-1));

++++++++}
++++}
}|code-block|syntax|javascript|709935|这样，即使街道号码是4,5,6,7字符长，这个方法仍然有效。|709936|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/system.string.substring%2528v=vs.110%2529.aspx|1|http://msdn.microsoft.com/en-us/library/system.string.indexof%2528v=vs.110%2529.aspx^0|3|2|0|8|E|1|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]|$A|Y|B|Z|1|10]]|C|$]]|$1|D|3|E|5|F|7|11|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|12|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|13|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

Just use a <a href="http://msdn.microsoft.com/en-us/library/system.string.substring%28v=vs.110%29.aspx" rel="nofollow">Substring</a> call with a <a href="http://msdn.microsoft.com/en-us/library/system.string.indexof%28v=vs.110%29.aspx" rel="nofollow">String.IndexOf</a>, for example

<pre><code>using System;
using System.Collections.Generic;
public class Test
{
 public static void Main()
 {

 List&lt;string&gt; strings = new List&lt;string&gt;();
 strings.Add("110 - Main Road");
 strings.Add("1104 - Main Road");
 strings.Add("11088 - Main Road");

 foreach(string s in strings){
 Console.WriteLine(s.Substring(0,s.IndexOf("-",0)-1));

 }
 }
}
</code></pre>

That way even if the street number is 4,5,6,7 characters long this will still work

blocks|key|709903|text|如果你只想要前4个字符，你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|709904|Location+=+Location.Substring(0,+4);|code-block|syntax|javascript|709905|第一个参数是起始位置，第二个参数是长度。|709906|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

If you just want the first 4 characters you would do this:

<pre><code>Location = Location.Substring(0, 4);
</code></pre>

The first argument is the start position and the second argument is the length.

blocks|key|1430557|text|使用字符串的子字符串函数(startIndex，numberOfCharToKeep)如下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1430558|string+Location+=+"110+-+Main+Road";
string+NewLocation+=+Location.SubString(0,4);+|code-block|syntax|javascript|1430559|这保留了你的前4个字符|1430560|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

use the substring function of string(startIndex,numberOfCharToKeep) like this:

<pre><code>string Location = "110 - Main Road";
string NewLocation = Location.SubString(0,4); 
</code></pre>

this keeps your first 4 chars

blocks|key|709975|text|取决于您的输入有多可靠。如果你总是在数字之后有一个空格，你可以用IndexOf找到那个位置。然而，每当我使用字符串时，我更喜欢正则表达式。以下是这两种方法的一个示例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|709976|using+System;
using+System.Text.RegularExpressions;

class+Program
{
++++static+void+Main(string[]+args)
++++{
++++++++string[]+locations+=+
++++++++{+
++++++++++++"110+-+Main+Road",+
++++++++++++"123+-+Highway",+
++++++++++++"234+-+My+House",+
++++++++++++"1120+-+Main+Road"+
++++++++};

++++++++Regex+r+=+new+Regex(@"%5E\d%2B");

++++++++foreach+(string+location+in+locations)
++++++++{
++++++++++++Console.WriteLine(location.Substring(0,+location.IndexOf('+')));
++++++++++++Console.WriteLine(r.Match(location).Captures[0].Value);
++++++++}
++++}
}|code-block|syntax|javascript|709977|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Depends on how reliable your input is. If you will always have a space after the numbers you can find that location using IndexOf. However, whenever I work with strings I prefer regular expressions. Here is an example of both approaches:

<pre><code>using System;
using System.Text.RegularExpressions;

class Program
{
 static void Main(string[] args)
 {
 string[] locations = 
 { 
 "110 - Main Road", 
 "123 - Highway", 
 "234 - My House", 
 "1120 - Main Road" 
 };

 Regex r = new Regex(@"^\d+");

 foreach (string location in locations)
 {
 Console.WriteLine(location.Substring(0, location.IndexOf(' ')));
 Console.WriteLine(r.Match(location).Captures[0].Value);
 }
 }
}
</code></pre>

I need to figure out how to remove the end of a string. The only trouble is, the string itself is not set. All I want to keep is the first 3-4 characters in the string.

<pre><code>string Location = "110 - Main Road";
string Location = "123 - Highway";
string Location = "234 - My House";
</code></pre>

It could also be;

<pre><code>string Location = "1120 - Main Road";
</code></pre>

I know if I can cut it down to the first 4 characters, I can just use <code>.Trim()</code> to remove the white spaces if it is only 3 characters, but I don't know how to cut it down to the first 4 characters?

Cut off the end of a string

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要弄清楚如何删除字符串的结尾。唯一的问题是，字符串本身没有被设置。我只想保留字符串中的前3-4个字符。string Location = "110 - Main Road";string Location = "123 - Highway";string Location = "234 - My House";也可能是这样；string Location = "1120 - Main Road

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