我正试图将一个HashMap作为一个列表来分发和解压缩。编组工作在两个Java版本(6u 45和7u 21)中,但是用Java 6u 45解组列表条目将提供一个空myModels。在Java 7u21中,被填充。
我尝试在Java 6u45中使用JAXB2.2.7(将jaxb-api.jar复制到lib /核可dir中),将另一个JAXB核心的jaxb核/impl\jxc\xjc\xjc/xjc添加到我的应用库中,并将它们添加到类路径中,但是我得到了相同的结果。
谢谢你的回答。
编组的xml:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<myStore>
<myModels>
<value>My Model 2</value>
<myEnum>VALUE2</myEnum>
</myModels>
<myModels>
<value>My Model 1</value>
<myEnum>VALUE1</myEnum>
</myModels>
<name>My Store</name>
</myStore>MyModel:
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class MyModel {
public enum MyEnum {
VALUE1, VALUE2
}
private String value;
private MyEnum myEnum;
public MyModel() {
}
public MyModel(String value, MyEnum myEnum) {
this.setValue(value);
this.setMyEnum(myEnum);
}
public String toString() {
return getValue() + ", " + getMyEnum();
}
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
public MyEnum getMyEnum() {
return myEnum;
}
public void setMyEnum(MyEnum myEnum) {
this.myEnum = myEnum;
}}
MyStore:
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
@XmlAccessorType(XmlAccessType.PUBLIC_MEMBER)
public class MyStore {
private String name;
private Map<String, MyModel> myModels = new HashMap<String, MyModel>();
public MyStore() {
}
public MyStore(String name) {
this.setName(name);
}
public void addMyModel(MyModel myModel) {
myModels.put(myModel.getValue(), myModel);
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<MyModel> getMyModels() {
return new ArrayList<MyModel>(myModels.values());
}
public void setMyModels(List<MyModel> myModels) {
for (MyModel myModel: myModels) {
this.myModels.put(myModel.getValue(), myModel);
}
}
}用于编组/解组的测试类
import java.io.File;
import javax.xml.bind.JAXB;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import MyModel.MyEnum;
public class MyStoreTest {
public static void main(String[] args) throws JAXBException {
MyStore myStore = new MyStore("My Store");
myStore.addMyModel(new MyModel("My Model 1", MyEnum.VALUE1));
myStore.addMyModel(new MyModel("My Model 2", MyEnum.VALUE2));
File fileMyStore = new File("MyStore.xml");
JAXB.marshal(myStore, fileMyStore);
JAXBContext context = JAXBContext.newInstance(MyStore.class,
MyModel.class);
Unmarshaller m = context.createUnmarshaller();
MyStore myStoreFromXml = (MyStore) m.unmarshal(fileMyStore);
System.out.println(myStoreFromXml.getName());
for (MyModel myModel : myStoreFromXml.getMyModels()) {
System.out.println(myModel.toString());
}
}
}发布于 2014-02-21 11:28:15
在解组List属性时,JAXB将检查get方法,以查看List是否已经初始化。如果有一个值,它将被用来将值添加到。这允许您选择底层List实现是什么。
get方法总是返回ArrayList的一个实例。因为它没有被任何东西引用,所以被解封到它中的数据就会丢失。
如果您的Map是空的,您可以让您的属性返回null,而不是一个空的ArrayList来使您的用例工作。
https://stackoverflow.com/questions/21929889
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