blocks|key|938100|text|您可以使用setInterval进行间隔重复执行，然后在10次调用之后使用clearInterval：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|938101|callfunction();
var+callCount+=+1;
var+repeater+=+setInterval(function+()+{
++if+(callCount+<+10)+{
++++callfunction();
++++callCount+%2B=+1;
++}+else+{
++++clearInterval(repeater);
++}
},+1000);|code-block|syntax|javascript|938102|补充道：，但是如果您不知道执行调用函数需要多长时间，调用起点之间的精确时间并不重要，那么出于Paul提到的原因和这篇文章中描述的原因，使用setTimeout似乎更好。|style|BOLD|938103|entityMap|0|LINK|mutability|MUTABLE|url|http://www.w3schools.com/jsref/met_win_setinterval.asp|1|http://www.w3schools.com/jsref/met_win_clearinterval.asp|2|http://www.thecodeship.com/web-development/alternative-to-javascript-evil-setinterval/^0|5|B|0|11|D|1|0|0|0|4|1K|4|2|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]|$A|12|B|13|1|14]]|C|$]]|$1|D|3|E|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|16|8|@$A|17|B|18|K|L]]|9|@$A|19|B|1A|1|1B]]|C|$]]|$1|M|3|-4|5|6|7|1C|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]|W|$5|P|Q|R|C|$S|X]]]]

You can use <a href="http://www.w3schools.com/jsref/met_win_setinterval.asp" rel="noreferrer">setInterval</a> for repeated execution with intervals and then <a href="http://www.w3schools.com/jsref/met_win_clearinterval.asp" rel="noreferrer">clearInterval</a> after 10 invocations:

<pre><code>callfunction();
var callCount = 1;
var repeater = setInterval(function () {
 if (callCount &lt; 10) {
 callfunction();
 callCount += 1;
 } else {
 clearInterval(repeater);
 }
}, 1000);
</code></pre>

Added: But if you don't know how long it takes your callfunction to execute and the accurate timings between invocation starting points are not important it seems it's better to use setTimeout for reasons mentioned by Paul S and those described in <a href="http://www.thecodeship.com/web-development/alternative-to-javascript-evil-setinterval/" rel="noreferrer">this article</a>.

blocks|key|1216670|text|function+callNTimes(func,+num,+delay)+{
++++if+(!num)+return;
++++func();
++++setTimeout(function()+{+callNTimes(func,+num+-+1,+delay);+},+delay);
}
callNTimes(callfunction,+10,+1000);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1216671|编辑:函数主要是说:调用传递的函数，然后稍过一点，再做9次。|unstyled|1216672|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>function callNTimes(func, num, delay) {
 if (!num) return;
 func();
 setTimeout(function() { callNTimes(func, num - 1, delay); }, delay);
}
callNTimes(callfunction, 10, 1000);
</code></pre>

EDIT: The function basically says: make a call of the passed function, then after a bit, do it again 9 more times.

blocks|key|215322|text|另一种解决办法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|215323|for(var+x=0;+x<10;+x%2B%2B)+window.setTimeout(callfunction,+1000+*+x);|code-block|syntax|javascript|215324|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Another solution

<pre><code>for(var x=0; x&lt;10; x++) window.setTimeout(callfunction, 1000 * x);
</code></pre>

blocks|key|938114|text|您可以尝试使用setInterval并使用一个变量来计数10。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|938115|var+number+=+1;
function+oneSecond+()+{
++if(number+<=+10)+{
++++//+execute+code+here..
++++number%2B%2B;
++}
};|code-block|syntax|javascript|938116|现在使用setInterval：|938117|setInterval(oneSecond,+1000);|938118|entityMap^0|7|B|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

You can try to use <code>setInterval</code> and use a variable to count up to 10. Try this:

<pre><code>var number = 1;
function oneSecond () {
 if(number &lt;= 10) {
 // execute code here..
 number++;
 }
};
</code></pre>

Now use the setInterval:

<pre><code>setInterval(oneSecond, 1000);
</code></pre>

blocks|key|1216717|text|我不知道是否有合适的名字，但我用的是中继器：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1216718|function+Repeater(callback,+delay,+count)+{
++++var+self+=+this;
++++this.timer+=+setTimeout(function()+{self.run();},delay);
++++this.callback+=+callback;
++++this.delay+=+delay;
++++this.timesLeft+=+count;
++++this.lastCalled+=+new+Date().getTime();
}
Repeater.prototype.run+=+function()+{
++++var+self+=+this;
++++this.timesLeft--;
++++this.callback();
++++this.lastCalled+=+new+Date().getTime();
++++if(+this.timesLeft+>+0)+{
++++++++this.timer+=+setTimeout(function()+{self.run();},this.delay);
++++}
}
Repeater.prototype.changeDelay+=+function(newdelay)+{
++++var+self+=+this;
++++clearTimeout(this.timer);
++++this.timer+=+setTimeout(function()+{self.run();},
++++++++++++++++++++++++++newdelay-new+Date().getTime()%2Blastcalled);
++++this.delay+=+newdelay;
}
Repeater.prototype.changeCount+=+function(newcount)+{
++++var+self+=+this;
++++if(+this.timesLeft+==+0)+{
++++++++this.timer+=+setTimeout(function()+{self.run();},this.delay);
++++}
++++this.timesLeft+=+newcount;
++++if(+this.timesLeft+==+0)+clearTimeout(this.timer);
}|code-block|syntax|javascript|1216719|然后，您可以这样使用它：|1216720|new+Repeater(callfunction,+1000,+10);+//+1+second+delay,+10+times|1216721|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

I don't know if there's a proper name, but I use a repeater:

<pre><code>function Repeater(callback, delay, count) {
 var self = this;
 this.timer = setTimeout(function() {self.run();},delay);
 this.callback = callback;
 this.delay = delay;
 this.timesLeft = count;
 this.lastCalled = new Date().getTime();
}
Repeater.prototype.run = function() {
 var self = this;
 this.timesLeft--;
 this.callback();
 this.lastCalled = new Date().getTime();
 if( this.timesLeft &gt; 0) {
 this.timer = setTimeout(function() {self.run();},this.delay);
 }
}
Repeater.prototype.changeDelay = function(newdelay) {
 var self = this;
 clearTimeout(this.timer);
 this.timer = setTimeout(function() {self.run();},
 newdelay-new Date().getTime()+lastcalled);
 this.delay = newdelay;
}
Repeater.prototype.changeCount = function(newcount) {
 var self = this;
 if( this.timesLeft == 0) {
 this.timer = setTimeout(function() {self.run();},this.delay);
 }
 this.timesLeft = newcount;
 if( this.timesLeft == 0) clearTimeout(this.timer);
}
</code></pre>

You can then use it like this:

<pre><code>new Repeater(callfunction, 1000, 10); // 1 second delay, 10 times
</code></pre>

blocks|key|1216804|text|类似于阿马丹的回答，但具有不同的闭包风格，这意味着您将重用而不是创建新函数。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1216805|function+call(fn,+/*+ms+*/+every,+/*+int+*/+times)+{
++++var+repeater+=+function+()+{
++++++++fn();
++++++++if+(--times)+window.setTimeout(repeater,+every);
++++};
++++repeater();+//+start+loop
}
//+use+it
var+i+=+0;
call(function+()+{console.log(%2B%2Bi);},+1e3,+10);+//+1e3+is+1+second
//+1+to+10+gets+logged+over+10+seconds|code-block|syntax|javascript|1216806|在本例中，如果要将times设置为0或Infinity，则它将永远运行。|style|CODE|1216807|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/21648304/1615483^0|3|6|0|0|0|9|5|H|1|J|8|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@$A|10|B|11|K|L]|$A|12|B|13|K|L]|$A|14|B|15|K|L]]|9|@]|C|$]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

Similar to <a href="https://stackoverflow.com/a/21648304/1615483">Amadan's answer</a> but with a different style of closure which means you re-use instead of creating new functions

<pre><code>function call(fn, /* ms */ every, /* int */ times) {
 var repeater = function () {
 fn();
 if (--times) window.setTimeout(repeater, every);
 };
 repeater(); // start loop
}
// use it
var i = 0;
call(function () {console.log(++i);}, 1e3, 10); // 1e3 is 1 second
// 1 to 10 gets logged over 10 seconds
</code></pre>

In this example, if you were to set <code>times</code> to either <code>0</code> or <code>Infinity</code>, it would run forever.

blocks|key|215425|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|215426|const+functionCounterTimer+=+(callCount)+=>+{
++if+(callCount+<+10)+{
++++setTimeout(()+=>+{
++++++%2B%2BcallCount
++++++console.log("Function+Call+",+callCount);
++++++functionCounterTimer(callCount);
++++},+1000);
++}
}

functionCounterTimer(0);|code-block|syntax|javascript|215427|215428|以上就是我回答类似问题的方法。|215429|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|M|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const functionCounterTimer = (callCount) =&gt; {
 if (callCount &lt; 10) {
 setTimeout(() =&gt; {
 ++callCount
 console.log("Function Call ", callCount);
 functionCounterTimer(callCount);
 }, 1000);
 }
}

functionCounterTimer(0);</code></pre>
</div>
</div>


The above was my approach to a similar question.

blocks|key|1216703|text|setInterval(function(){},1000);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1216704|每一秒调用这个函数..。|unstyled|1216705|您也可以使用setTimeout让您的东西工作。|1216706|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|F|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>setInterval(function(){},1000);
</code></pre>

Calls the function for every second...

You can also use setTimeout for your thing to work.

How to call a function 10 times like

<pre><code>for(x=0; x&lt;10; x++) callfunction();
</code></pre>

but with 1 sec between each call?

javascript Call function 10 times with 1 second between

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何调用10次以下函数for(x=0; x<10; x++) callfunction();但每次通话间隔1秒？

问javascript调用函数10次，间隔1秒
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问javascript调用函数10次，间隔1秒
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