我有两份档案。其中一个是类声明,另一个是接口声明。类应该实现接口。如果类实现接口方法,我如何签入NRefactory?
我应该给出更多细节。
第一个文件--例如:
class Test : IF
{
}第二个
interface IF
{
void Foo();
}我必须读取这些文件并使用NRefactory进行解析。我需要检查类Test是否从接口IF实现方法。
无需编译和加载已编译程序集。
发布于 2013-12-14 18:43:46
我在NRefactory代码中找到了解决方案。为了实现我的目标,我对此进行了修改。首先,我们应该实现访问者,检查类是否实现了接口中的每个方法:
public class MissingInterfaceMemberImplementationVisitor : DepthFirstAstVisitor
{
private readonly CSharpAstResolver _resolver;
public bool IsInterfaceMemberMissing { get; private set; }
public MissingInterfaceMemberImplementationVisitor(CSharpAstResolver resolver)
{
_resolver = resolver;
IsInterfaceMemberMissing = false;
}
public override void VisitTypeDeclaration(TypeDeclaration typeDeclaration)
{
if (typeDeclaration.ClassType == ClassType.Interface || typeDeclaration.ClassType == ClassType.Enum)
return;
base.VisitTypeDeclaration(typeDeclaration);
var rr = _resolver.Resolve(typeDeclaration);
if (rr.IsError)
return;
foreach (var baseType in typeDeclaration.BaseTypes)
{
var bt = _resolver.Resolve(baseType);
if (bt.IsError || bt.Type.Kind != TypeKind.Interface)
continue;
bool interfaceMissing;
var toImplement = ImplementInterfaceAction.CollectMembersToImplement(rr.Type.GetDefinition(), bt.Type, false, out interfaceMissing);
if (toImplement.Count == 0)
continue;
IsInterfaceMemberMissing = true;
}
}
}现在我们必须以以下方式读取所有文件,解析它们并调用上面的类:
var solutionFiles = new List<FileInfo>();
var trees = new Dictionary<FileInfo, SyntaxTree>();
IProjectContent projectContent = new CSharpProjectContent();
foreach (var file in solutionFiles.Where(f => f.Extension == ".cs").Distinct())
{
var parser = new ICSharpCode.NRefactory.CSharp.CSharpParser();
SyntaxTree syntaxTree;
using (var fs = new FileStream(file.FullName, FileMode.Open, FileAccess.Read, FileShare.Read, 4096, FileOptions.SequentialScan))
{
syntaxTree = parser.Parse(fs, file.FullName);
}
trees.Add(file, syntaxTree);
var unresolvedFile = syntaxTree.ToTypeSystem();
projectContent = projectContent.AddOrUpdateFiles(unresolvedFile);
}
var compilation = projectContent.CreateCompilation();
foreach (var sharpFile in trees)
{
var originalResolver = new CSharpAstResolver(compilation, sharpFile.Value, sharpFile.Value.ToTypeSystem());
var visitor = new MissingInterfaceMemberImplementationVisitor(originalResolver);
sharpFile.Value.AcceptVisitor(visitor);
if (visitor.IsInterfaceMemberMissing)
return false;
}
return true;发布于 2013-12-12 15:17:34
使用is关键字
http://msdn.microsoft.com/en-us/library/scekt9xw.aspx
if (myObj is IMyInterface) {
....
}发布于 2013-12-12 15:19:46
或者,您也可以使用as关键字。
class MyClass { }
interface IInterface { }
MyClass instance = new MyClass();
var inst = instance as IInterface;
if (inst != null)
{
// your class implements the interface
}在不需要额外的引用输入的情况下,需要在事后使用该实例时使用此方法。使用is,您仍然需要做
if (instance is IInterface)
{
var inst = (IInterface) instance;
}或
(instance as IInterface).InstanceProperty那为什么不马上做呢。
https://stackoverflow.com/questions/20547187
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