我创建了一个webservice,它工作正常,我执行节点创建操作,并且它工作正常。我需要验证将要保存的节点,就像在接口插入表单中验证它一样。
我试过了
drupal_form_submit($nodeType . '_node_form', $form_state, (object) $node);它总是给我错误--它的节点引用字段
您是否可以建议其他方法来进行与以编程方式创建的节点上的接口所做的验证相同的操作?
节点引用字段上的错误是:
“field_ente :不能引用此条目。
节点(6310)正确存在,如果我尝试执行node_save,它将被正确保存。
完整的函数如下
function my_ws_resource_create($field_nome = '', $field_cognome = '', $field_codice_fiscale = '', $field_data_di_nascita = '', $field_ente= '')
{
module_load_include('inc', 'node', 'node.pages');
global $user;
$nodeType = 'contatti';
$node = new stdClass();
$node->type = $nodeType;
$node->uid = $user->uid;
$node->status = 1;
$node->revision = 1;
$node->promote = 0;
$node->comment = 0;
node_object_prepare($node);
$node->field_cognome['und'][0]['value'] = $field_cognome;
$node->field_nome['und'][0]['value'] = $field_nome;
$node->field_codice_fiscale['und'][0]['cck_codicefiscale'] = $field_codice_fiscale;
$node->field_data_di_nascita['und'][0]['value'] = $field_data_di_nascita;
$node->field_categoria_contatto['und'][0]['tid'] = '66';
// $node->field_ente = array('und' => array(array('nid'=> $field_ente )));
// this field causes the error
$node->field_ente = array('und' => array(array('nid'=> '6310')));
$node->field_simplenews_term['it'][0]['tid'] = '13660';
$form_state = array();
$form_state['values']['type'] = $nodeType;
$form_state['values']['name'] = $user->name;
$form_state['values']['status'] = 1;
$form_state['values']['promote'] = 1;
$form_state['values']['sticky'] = 0;
$form_state['values']['op'] = t('Save');
drupal_form_submit($nodeType . '_node_form', $form_state, (object) $node);
if ($errors = form_get_errors()) {
return services_error(implode(" ", $errors), 406, array('form_errors' => $errors));
}
return 'Creation successful';
}发布于 2021-10-08 06:47:35
我已经成功地完成了以下工作(删除$form_state并替换drupal_form_submit):
if ($node = node_submit($node)) {
node_save($node);
// Success!
}
else {
// Fail :(
}https://stackoverflow.com/questions/60761226
复制相似问题