#include <iostream>
#include <string>
void* operator new(size_t size) {
std::cout << "Allocated: " << size << " Bytes\n";
return malloc(size);
}
void operator delete(void* var) {
std::cout << "Deleted\n";
free(var);
}
int main() {
std::string name0 = "Ahmed Zaki Marei";
//std::string name1 = "Lara Mohammed";
std::cout << name0 << "\n";
//std::cout << name1 << "\n";
}当我试图运行这段代码时,它提供了以下输出:
Allocated: 8 Bytes
Allocated: 32 Bytes
Ahmed Zaki Marei
Deleted
Deleted为什么它先分配8个字节,然后再分配32个字节?有人能解释一下吗?( thx!)
发布于 2020-08-20 12:21:53
正如C.M.在评论中所指出的:这是MS在调试模式下的行为,与_ITERATOR_DEBUG_LEVEL有关。释放后一切都很好。
我很好奇,所以我自己测试了它,堆栈在new中的第一个断点上读取了这个
operator new(unsigned int size)
std::_Default_allocate_traits::_Allocate(const unsigned int _Bytes)
std::_Allocate<8,std::_Default_allocate_traits,0>(const unsigned int _Bytes)
std::allocator<std::_Container_proxy>::allocate(const unsigned int _Count)
std::_Container_proxy_ptr12<std::allocator<std::_Container_proxy>>::_Container_proxy_ptr12<std::allocator<std::_Container_proxy>>(std::allocator<std::_Container_proxy> & _Al_, std::_Container_base12 & _Mycont)
std::string::basic_string<char,std::char_traits<char>,std::allocator<char>>(const char * const _Ptr)
main()让我们看看basic_string构造函数:
basic_string(_In_z_ const _Elem* const _Ptr) : _Mypair(_Zero_then_variadic_args_t{}) {
auto&& _Alproxy = _GET_PROXY_ALLOCATOR(_Alty, _Getal());
_Container_proxy_ptr<_Alty> _Proxy(_Alproxy, _Mypair._Myval2);_Container_proxy_ptr的真正含义是:
#if _ITERATOR_DEBUG_LEVEL == 0
#define _GET_PROXY_ALLOCATOR(_Alty, _Al) _Fake_allocator()
template <class _Alloc>
using _Container_proxy_ptr = _Fake_proxy_ptr_impl;
#else // _ITERATOR_DEBUG_LEVEL == 0
#define _GET_PROXY_ALLOCATOR(_Alty, _Al) static_cast<_Rebind_alloc_t<_Alty, _Container_proxy>>(_Al)
template <class _Alloc>
using _Container_proxy_ptr = _Container_proxy_ptr12<_Rebind_alloc_t<_Alloc, _Container_proxy>>;
#endif // _ITERATOR_DEBUG_LEVEL == 0在Debug中是_Container_proxy_ptr12 (最终调用了.allocate(1)),在发布时是_Fake_proxy_ptr_impl (什么都不做)。
https://stackoverflow.com/questions/63496083
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