blocks|key|422838|text|另一个sed解决方案：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|422839|$+cat+ip.txt
\\\\\\\\
\\\\\\\
\\\\\\
\\\\\
\\\\
\\\
\\
\
$+sed+-E+'s/(\\%2B)\1\\?/\1/g'+ip.txt
\\\\
\\\
\\\
\\
\\
\
\
\|code-block|syntax|javascript|422840|(\\%2B)\1\\?将均分反斜杠，最后的可选匹配将对奇数情况使用最后的反斜杠。|422841|如果应该删除单个反斜杠而不是保存，请使用|422842|sed+-E+'s/((\\%2B)\2)?\\?/\2/g'|422843|entityMap^0|3|3|0|0|0|A|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|Z|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|R|$]]

Another <code>sed</code> solution:
<pre class="lang-sh prettyprint-override"><code>$ cat ip.txt
\\\\\\\\
\\\\\\\
\\\\\\
\\\\\
\\\\
\\\
\\
\
$ sed -E 's/(\\+)\1\\?/\1/g' ip.txt
\\\\
\\\
\\\
\\
\\
\
\
\
</code></pre>
<code>(\\+)\1\\?</code> will evenly divide the backslashes, the optional matching at the end will consume the last backslash for odd cases.
If single backslash should be removed instead of being preserved, use
<pre class="lang-sh prettyprint-override"><code>sed -E 's/((\\+)\2)?\\?/\2/g'
</code></pre>

blocks|key|422834|text|你可以试试这个awk|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|422835|cat+file

\\\\\\\\\\\\\\\
\\\\\\\\\\\\\\

#+using+awk
awk+'{print+substr($0,+1,+int(length($0)/2))}'+file

\\\\\\\
\\\\\\\|code-block|syntax|javascript|422836|entityMap^0|7|3|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You may try this <code>awk</code>:
<pre class="lang-sh prettyprint-override"><code>cat file

\\\\\\\\\\\\\\\
\\\\\\\\\\\\\\

# using awk
awk '{print substr($0, 1, int(length($0)/2))}' file

\\\\\\\
\\\\\\\
</code></pre>

blocks|key|2393032|text|使用sed:在带有奇数\的行中，首先去掉最后一个。然后替换成对，就像你做的那样：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2393033|sed+-r+'s/((\\\\)*)(\\)?/\1/g;s/\\\\/\\/g'|code-block|syntax|javascript|2393034|演示：|2393035|$+cat+foo.txt
\\\\
\\\
\\
$+sed+-r+'s/((\\\\)*)(\\)?/\1/g;s/\\\\/\\/g'+foo.txt
\\
\
\|2393036|entityMap^0|B|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

Using sed: in lines with an odd number of <code>\</code> first get rid of the last one. Then substitute pairs, as you did:
<pre><code>sed -r 's/((\\\\)*)(\\)?/\1/g;s/\\\\/\\/g'
</code></pre>
Demo:
<pre><code>$ cat foo.txt
\\\\
\\\
\\
$ sed -r 's/((\\\\)*)(\\)?/\1/g;s/\\\\/\\/g' foo.txt
\\
\
\
</code></pre>

blocks|key|426028|text|在显示的示例中，请尝试遵循awk代码。这将适用于任意数量的/斜杠，并将给出一半的数字。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|426029|awk+'
BEGIN{+OFS=""+}
{
++val=""
++num=split($0,arr,"")
++till=(int(num/2))
++for(i=1;i<=till;i%2B%2B){
++++val=(val?val+OFS:"")arr[i]
++}
++print+val
}
'++Input_file|code-block|syntax|javascript|426030|解释：添加了上面的详细说明。|BOLD|426031|awk+'+++++++++++++++++++++++++++++##Starting+awk+program+from+here.
BEGIN{+OFS=""+}+++++++++++++++++++##Setting+OFS+to+null+here.
{
++val=""++++++++++++++++++++++++++##Nullifying+val+here.
++num=split($0,arr,"")++++++++++++##Splitting+current+line+to+arr+with+NULL+delimiter.
++till=(int(num/2))+++++++++++++++##getting+half+of+NF(number+of+fields)+in+till.
++for(i=1;i<=till;i%2B%2B){+++++++++++##Traversing+through+fields+till+value+of+till.
++++val=(val?val+OFS:"")arr[i]++++##Creating+val+here+which+has+array+individual+element+value.
++}
++print+val+++++++++++++++++++++++##Printin+val+here.
}
'+Input_file++++++++++++++++++++++##Mentioning+Input_file+name+here.|426032|entityMap^0|D|3|T|1|0|0|0|3|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|W|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|X|8|@$9|Y|A|Z|B|M]]|D|@]|E|$]]|$1|N|3|O|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|P|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|Q|$]]

With your shown samples, please try following <code>awk</code> code. This will work for any number of <code>/</code>slashes and will give half of the numbers.
<pre><code>awk '
BEGIN{ OFS=&quot;&quot; }
{
 val=&quot;&quot;
 num=split($0,arr,&quot;&quot;)
 till=(int(num/2))
 for(i=1;i&lt;=till;i++){
 val=(val?val OFS:&quot;&quot;)arr[i]
 }
 print val
}
' Input_file
</code></pre>
Explanation: Adding detailed explanation for above.
<pre><code>awk ' ##Starting awk program from here.
BEGIN{ OFS=&quot;&quot; } ##Setting OFS to null here.
{
 val=&quot;&quot; ##Nullifying val here.
 num=split($0,arr,&quot;&quot;) ##Splitting current line to arr with NULL delimiter.
 till=(int(num/2)) ##getting half of NF(number of fields) in till.
 for(i=1;i&lt;=till;i++){ ##Traversing through fields till value of till.
 val=(val?val OFS:&quot;&quot;)arr[i] ##Creating val here which has array individual element value.
 }
 print val ##Printin val here.
}
' Input_file ##Mentioning Input_file name here.
</code></pre>

blocks|key|3177570|text|编辑。尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3177571|sed+'s/\\//;+s/\\\\/\\/g'|code-block|syntax|javascript|3177572|说明:首先删除一个反斜杠，然后用一个反斜杠替换每对反斜杠。第二个命令末尾的g表示必须在整个行上重复操作。反斜杠需要逃脱。这就是你每次写两遍这些的原因。|3177573|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

EDITED. Try:
<pre><code>sed 's/\\//; s/\\\\/\\/g'
</code></pre>
Explanation: first remove one backslash; then replace every pair with one backslash. The g at the end of the second command indicates you have to repeat the operation on whole the line. The backslashes need to be escaped. That's the reason why you write these everytime twice.

Having a scenario to replace the even and odd occurrence of backslashes by the number of quotient when dividing by 2.
<pre><code>For example
Input: (15 backslashes)
\\\\\\\\\\\\\\\
output: (7 backslashes)
\\\\\\\

Input: (14 backslashes)
\\\\\\\\\\\\\\
output: (7 backslashes)
\\\\\\\
</code></pre>
I tried using sed command which is working for 4 backslashes to 2.
<code>sed 's/\\\\/\\/g'</code>
Appreciate if any help.

Replace odd and even occurrences of a pattern to another same pattern

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有一个场景，当除以2时，将反斜杠的偶数和奇数替换为商数。For exampleInput: (15 backslashes)\\\\\\\\\\\\\\\output: (7 backslashes)\\\\\\\Input: (14 backslashes)\\\\\\\\\\\\\\output: (7 backslashes)\\\\\\\我尝试使用sed命令，它可以处理4个反斜杠到2. s

问将模式的奇数和偶数替换为另一个相同的模式
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