iOS将BLE数据快速传递给一个单独的类函数
我确信这个问题已经在某个地方得到了回答，但我不知道该寻找什么。我正处于一个简单的BLE iOS应用程序的早期阶段，并试图研究如何将传入的BLE数据转移到一个单独的函数中。从BLE传入的数据正在转换为数组，但我认为不可能将其发送到不同的函数。我试图将其作为字符串发送，但似乎不可能将该字符串拆分为数组。
有人能建议什么是将传入的BLE数据转移到单独的函数中最有效的方法吗？
这是func peripheral(_ peripheral: CBPeripheral, didUpdateValueFor characteristic: CBCharacteristic, error: Error?)中的代码
// Decode the incoming BLE into bytes
let data2 = characteristic.value
let count = (data2?.count)! / MemoryLayout<UInt8>.size
var array = [UInt8](repeating: 0, count: count)
data?.copyBytes(to: &array, count:count * MemoryLayout<UInt8>.size)
// Transfer the incoming BLE data to a sepurate class to decode
var stringFromData = String(data: characteristic.value!, encoding: String.Encoding.ascii)
// How to transfer the incoming BLE data to a sepurate class?
BLE_Element_One_DataExtract_class.DummyFunc(_IncomingElementOneData: stringFromData!, _IncomingUUID: characteristic.uuid)
print("BLE incoming data in an array = ")
let x=0
for x in array
{
print("\(array) BLE data \n")
}// Separate class and function to decode the BLE data and store in the MVVM
// This code does not work, as it does not treat the incoming data as a string
class BLE_Element_One_DataExtract
{
func DummyFunc(_IncomingElementOneData:String, _IncomingUUID:CBUUID)
{
let data
let data2 = _IncomingElementOneData
let count = (data2?.count)! / MemoryLayout<UInt8>.size
var array = [UInt8](repeating: 0, count: count)
data?.copyBytes(to: &array, count:count * MemoryLayout<UInt8>.size)
print("data is -> : ", terminator : "")
if(_IncomingUUID.isEqual(CBUUIDs.ECHO_DISPLAY_ELEMENT_STATUS_ONE_UUID_CHAR))
{
print ("Found ECHO_DISPLAY_ELEMENT_STATUS_ONE_UUID_CHAR inner func")
// BLE_Element_One_DataExtract(?? send data string ??)
}
}
}回答 2
Stack Overflow用户
发布于 2022-01-30 20:49:55
“来自BLE的数据正在转换为数组，但我认为不可能将其发送到不同的函数。”
不，将数据数组传递给另一个函数很简单：
// Your code
var array = [UInt8](repeating: 0, count: count)
data?.copyBytes(to: &array, count:count * MemoryLayout<UInt8>.size)
// At this point you can simply pass your array to another
// function (which could be in a different class)
otherClass.processData(data: array)接收数据的类/函数可以简单地如下所示：
class OtherClass {
func processData(data: [UInt8]) {
// Do something with your data
}
}Stack Overflow用户
发布于 2022-01-30 19:33:31
我想要将characteristic.value (它有Data?类型)转换为String类型的变量。
您提到您想要String，但是在代码中您也使用了[UInt8]，所以我不确定我是否理解您想要做什么。
您已经使用func peripheral(_ peripheral: CBPeripheral, didUpdateValueFor characteristic: CBCharacteristic, error: Error?)实现了侦听更新，并从characteristic.value读取传入数据，因此仍然需要将数据转换为所需的类型。
转换示例(如果characteristic.value为零，或转换错误，则结果为空字符串)：
let data = characteristic.value ?? Data()
let stringValue = String(data: data, encoding: .utf8) ?? ""
// pass stringValue where you need it此外，您还可以使用Data?类型将数据传递给目标函数“原样”，因此决定如何处理它是目的地函数的工作：
func peripheral(_ peripheral: CBPeripheral, didUpdateValueFor characteristic: CBCharacteristic, error: Error?) {
DataDestinationClass.doSomething(data: characteristic.value, uuid: characteristic.uuid)
}
class DataDestinationClass {
static func doSomething(data: Data?, uuid: CBUUID) {
let stringValue = String(data: data ?? Data(), encoding: .utf8) ?? ""
print("MYLOG: stringValue = '\(stringValue)'")
}
}下面是将接收到的characteristic.value放入Text字段的示例：https://github.com/alexanderlavrushko/BLEProof-collection/blob/5cbb089dbfed42cfb8aad0db236a376ff1cce620/iOS/BLEProofCentral/BLEProofCentral/BLECentralViewController.swift#L295
https://stackoverflow.com/questions/70915747
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