我检查了表、拼写,并重新键入了代码。
SELECT
employees.name as employee_name,
employees.role as employee_role,
departments.name as department_name
FROM
`my-project-practice-327821.employee_data.employees`
INNER JOIN
employee_data.departments ON
employees.department_id = departments.department_id发布于 2021-12-07 22:35:21
在完全限定的表名后,您将需要一个employees作为别名使用backticks:
FROM `my-project-practice-327821.employee_data.employees` employees相反,您可以从完全限定的表名中移除后退:
FROM my-project-practice-327821.employee_data.employeeshttps://stackoverflow.com/questions/70266998
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