blocks|key|1022045|text|foreach+($filename+in+Get-Content+.\ListOfFilesToZip.txt)
{
++++Compress-Archive+-Update+$filename+.\ZipFile.zip
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1022046|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>foreach ($filename in Get-Content .\ListOfFilesToZip.txt)
{
 Compress-Archive -Update $filename .\ZipFile.zip
}
</code></pre>

blocks|key|1107223|text|如果问题是关于从路径获取文件名，请进行编辑|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1107224|最有效的方法是使用正则表达式，但如果您不习惯使用它们，它们可能会相当复杂。|1107225|一种更简单的方法是简单地拆分每个字符串，并选择文件名所在的最后一部分：|1107226|$string+=+"c:\asd\qwe\zxc\dog.txt"

#Split+the+string+on+each+\
++++$string.Split("\")+

#This+will+output+a+list+like+this
c:
asd
qwe
zxc
dog.txt|code-block|syntax|javascript|1107227|现在我们只想选择列表中的最后一个条目，因为文件名始终是路径中的最后一个条目。因此我们使用Select+Object来实现这一点。|1107228|$string.Split("\")+%7C+Select-Object+-Last+1+|1107229|这将返回：|1107230|dog.txt|1107231|您可以通过列表上的foreach来获取每一项的值。|1107232|entityMap^0|J|2|0|0|11|0|0|Z|0|0|0|1S|0|0|0|5|0|0|0|P|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|19|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|L|7|1D|8|@]|D|@]|E|$M|N]]|$1|S|3|T|5|6|7|1E|8|@$9|1F|A|1G|B|C]]|D|@]|E|$]]|$1|U|3|V|5|L|7|1H|8|@]|D|@]|E|$M|N]]|$1|W|3|X|5|6|7|1I|8|@$9|1J|A|1K|B|C]]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|1L|8|@]|D|@]|E|$]]]|Z|$]]

Edit If question is about getting filename from the path 
The most efficient way would be with a regex, but they can be rather complicated if you are not used to working with them. 

A simpler way would be to simply split each string and select the last part where the file name is:

<pre><code>$string = "c:\asd\qwe\zxc\dog.txt"

#Split the string on each \
 $string.Split("\") 

#This will output a list like this
c:
asd
qwe
zxc
dog.txt
</code></pre>

Now we want to simply select the last entry in this list as the filename is always last in a path. So we use Select Object for that.

<pre><code>$string.Split("\") | Select-Object -Last 1 
</code></pre>

This will return:

<pre><code>dog.txt
</code></pre>

You can run this through a foreach on your list to get it for each item.

blocks|key|1022007|text|不知道有没有更好的方法，但你可以创建一个临时文件夹，将要存档的文件和所需的文件夹结构一起复制到那里，然后压缩整个文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1022008|看一下示例的here+(不是我的代码，但似乎就是这样做的|offset|length|1022009|entityMap|0|LINK|mutability|MUTABLE|url|https://www.petri.com/custom-archiving-powershell-5-0^0|0|6|4|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

Not sure if there's any better way of doing this, but you can create a temp folder, copy the files to be archived along with desired folder structure over there and then just zip up the whole thing.

Take a look <a href="https://www.petri.com/custom-archiving-powershell-5-0" rel="nofollow noreferrer">here</a> (not my code, but seems to do exactly that) for a sample

blocks|key|3338734|text|以下函数可以将整个文件夹结构压缩到一个压缩文件中，并将该结构保留在压缩文件中(甚至适用于PowerShell+<5)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3338735|function+createZipFile($outputFileName,+$sourceDirectory){
++++Add-Type+-AssemblyName+System.IO.Compression.FileSystem
++++$compressionLevel+=+[System.IO.Compression.CompressionLevel]::Optimal
++++[System.IO.Compression.ZipFile]::CreateFromDirectory($sourceDirectory,+$outputFileName,+$compressionLevel,+$false)
}|code-block|syntax|javascript|3338736|就这么叫吧：|3338737|createZipFile+"c:\temp\output.zip"+"c:\folder\to\compress"|3338738|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The following function can compresses a whole folder structure into a single zip file and will keep the structure within the zip (even works with PowerShell &lt;5).

<pre><code>function createZipFile($outputFileName, $sourceDirectory){
 Add-Type -AssemblyName System.IO.Compression.FileSystem
 $compressionLevel = [System.IO.Compression.CompressionLevel]::Optimal
 [System.IO.Compression.ZipFile]::CreateFromDirectory($sourceDirectory, $outputFileName, $compressionLevel, $false)
}
</code></pre>

Call it like that:

<pre><code>createZipFile "c:\temp\output.zip" "c:\folder\to\compress"
</code></pre>

blocks|key|3338762|text|function+DirNewTemp+{
++++$tmpdir+=+(New-TemporaryFile).FullName
++++Remove-Item+-Force+-Path+$tmpdir+-ErrorAction+'SilentlyContinue'
++++New-Item+-Type+Directory+$tmpdir+%7C+out-null
++++return+$tmpdir
}

function+ZipFiles+{
++++param(
++++++++[string]$Zip,
++++++++[string[]]$FileList
++++)
++++write-host+""
++++write-host+"====================================="
++++write-host+"ZipFile+$Zip"
++++write-host+"====================================="
++++
++++$pwd++++++=+(Get-Location).Path+++++
++++$tmpdir+++=+DirNewTemp
++++++++
++++try+{
++++++++$count+=+$FileList.Count
++++++++foreach+($file+in+$FileList)+{
++++++++++++$pwd_escaped+=+[Regex]::Escape($pwd)++++++++
++++++++++++$save_file+++=+$file+-replace+"%5E${pwd_escaped}\\",+"${tmpdir}\"
++++++++++++$save_path+++=+Split-Path+$save_file+-Parent
++++++++++++New-Item++-Force+-Path+$save_path+-ItemType+Directory+%7C+out-null
++++++++++++Copy-Item+-Force+$file+$save_file+++++++++++
++++++++}
++++++++set-location+$tmpdir++++++++
++++++++$dest+=+"$pwd\$Zip";
++++++++write-host+"Creating+Zip:+$dest"++++++++
++++++++Compress-Archive+-Force+-Path+*+-DestinationPath+$dest
++++}
++++finally+{
++++++++write-host+"cleanup"
++++++++set-location+$pwd
++++++++remove-item+-Force+-Recurse+-Path+$tmpdir+-ErrorAction+'SilentlyContinue'
++++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3338763|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>function DirNewTemp {
 $tmpdir = (New-TemporaryFile).FullName
 Remove-Item -Force -Path $tmpdir -ErrorAction 'SilentlyContinue'
 New-Item -Type Directory $tmpdir | out-null
 return $tmpdir
}

function ZipFiles {
 param(
 [string]$Zip,
 [string[]]$FileList
 )
 write-host &quot;&quot;
 write-host &quot;=====================================&quot;
 write-host &quot;ZipFile $Zip&quot;
 write-host &quot;=====================================&quot;
 
 $pwd = (Get-Location).Path 
 $tmpdir = DirNewTemp
 
 try {
 $count = $FileList.Count
 foreach ($file in $FileList) {
 $pwd_escaped = [Regex]::Escape($pwd) 
 $save_file = $file -replace &quot;^${pwd_escaped}\\&quot;, &quot;${tmpdir}\&quot;
 $save_path = Split-Path $save_file -Parent
 New-Item -Force -Path $save_path -ItemType Directory | out-null
 Copy-Item -Force $file $save_file 
 }
 set-location $tmpdir 
 $dest = &quot;$pwd\$Zip&quot;;
 write-host &quot;Creating Zip: $dest&quot; 
 Compress-Archive -Force -Path * -DestinationPath $dest
 }
 finally {
 write-host &quot;cleanup&quot;
 set-location $pwd
 remove-item -Force -Recurse -Path $tmpdir -ErrorAction 'SilentlyContinue'
 }
}
</code></pre>

I have a file with a list of files with directions.

Like this:

<pre><code>XXXXXX/sample.txt

XXXXXX/dog.txt

XXXXXX/cat.docx

ZZZZ/lamp.jpg
</code></pre>

How can I to compress all files and save files with sub-directions.

Now, I can to compress all files but without directions.

Like this:

<pre><code>sample.txt

dog.txt

cat.docx

lamp.jpg
</code></pre>

Sorry on my bad English.

Compress Files from list with PowerShell 5

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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社区新版编辑器体验调研

我有一个文件，里面有一系列带方向的文件。如下所示：XXXXXX/sample.txtXXXXXX/dog.txtXXXXXX/cat.docxZZZZ/lamp.jpg如何压缩所有文件并保存带有子方向的文件。现在，我可以压缩所有的文件，但没有说明。如下所示：sample.txtdog.txtcat.docxlamp.jpg对不起，我的英语不好。

问使用PowerShell 5压缩列表中的文件
EN

回答 5

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