blocks|key|312093|text|对于安卓系统:在你的package.json中，在脚本中添加以下几行|type|unstyled|depth|inlineStyleRanges|entityRanges|data|312094|+"reload":"adb+shell+input+keyevent+82+&&+adb+shell+input+keyevent+66+&&+adb+shell+input+keyevent+66",
+"devmenu":"adb+shell+input+keyevent+82",
+"debug":"adb+shell+input+keyevent+82+&&+adb+shell+input+keyevent+61+&&+adb+shell+input+keyevent+66+&&+adb+shell+input+keyevent+66"|code-block|syntax|javascript|312095|现在你可以运行npm+run+devmenu打开安卓的摇晃菜单，运行reload重载应用，运行debug连接到远程调试器。|offset|length|style|CODE|312096|对于ios+:你可以在app中的某个地方为它做一个按钮，让这个东西只在app处于dev模式时显示。|312097|import+{NativeModules,Platform}+from+"react-native"


renderDevMenuTouchable+=+()+=>+{
++++if(__DEV__+&&+Platform.OS+==+"ios"+){
++++++++return+(
++++++++++++<TouchableOpacity
++++++++++++style={styles.touchableDebug}
++++++++++++onPress={()=>{
++++++++++++++++NativeModules.DevMenu.reload();
++++++++++++}}
++++++++++++onLongPress={()=>{
++++++++++++++++NativeModules.DevMenu.show();
++++++++++++}}
++++++++++++>+
++++++++++++<View+style={{backgroundColor:"red",width:23,height:25}}/>
++++++++++++</TouchableOpacity>
++++++++)
++++}
++++else+{
++++++++return+null;
++++}

}|312098|entityMap^0|0|0|7|F|Y|6|1B|5|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]|$I|X|J|Y|K|L]|$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|13|8|@]|9|@]|A|$]]]|R|$]]

for android :
in your package.json add following lines in scripts 

<pre><code> "reload":"adb shell input keyevent 82 &amp;&amp; adb shell input keyevent 66 &amp;&amp; adb shell input keyevent 66",
 "devmenu":"adb shell input keyevent 82",
 "debug":"adb shell input keyevent 82 &amp;&amp; adb shell input keyevent 61 &amp;&amp; adb shell input keyevent 66 &amp;&amp; adb shell input keyevent 66"
</code></pre>

now you can run <code>npm run devmenu</code> to open shake menu in android,
and <code>reload</code> to reload the app, and <code>debug</code> to connect to remote debugger.

for ios : you can make a button for it somewhere in app, and let this thing only be shown when app is in dev mode.

<pre><code>import {NativeModules,Platform} from "react-native"


renderDevMenuTouchable = () =&gt; {
 if(__DEV__ &amp;&amp; Platform.OS == "ios" ){
 return (
 &lt;TouchableOpacity
 style={styles.touchableDebug}
 onPress={()=&gt;{
 NativeModules.DevMenu.reload();
 }}
 onLongPress={()=&gt;{
 NativeModules.DevMenu.show();
 }}
 &gt; 
 &lt;View style={{backgroundColor:"red",width:23,height:25}}/&gt;
 &lt;/TouchableOpacity&gt;
 )
 }
 else {
 return null;
 }

}
</code></pre>

blocks|key|3207598|text|正如@bennygenel提示的那样，从那个页面你可以看到通过adb在Android上有一个命令|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3207599|adb+shell+input+keyevent+82|code-block|syntax|javascript|3207600|在无线设备上打开菜单|3207601|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

As @bennygenel hints, from that page you can see there is a command on Android through adb

<pre><code>adb shell input keyevent 82
</code></pre>

to open menu on wireless devices

blocks|key|3207644|text|你可以配置长按安卓系统的Recent按钮来打开/关闭菜单|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3207645|这将在react原生应用程序中打开dev菜单。|3207646|​|3207647|📷|atomic|3207648|3207649|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/636178197cf97ff649d40b8212a5cb1f.png|imageAlt^0|C|6|0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|10|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|11|8|@]|D|@$9|12|A|13|1|14]]|E|$]]|$1|M|3|I|5|6|7|15|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|O|$P|$5|Q|R|S|E|$T|U|V|-4]]]]

You can configure long pressing the Android system <code>Recent</code> button to Open/close menu

This would open the dev menu in a react native app.

<a href="https://i.stack.imgur.com/mpapu.png" rel="noreferrer"><img src="https://i.stack.imgur.com/mpapu.png" alt="enter image description here"></a>

blocks|key|310202|text|我已经在Assistive+Touch菜单中添加了Shake手势，这对我来说没问题。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|310203|📷|atomic|310204|​|310205|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/de1263dae7be9ea00086e0e814d1da15.png|imageAlt^0|4|F|P|5|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|I|3|J|5|6|7|12|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R|S|-4]]]]

I have added <code>Shake</code> gesture to <code>Assistive Touch</code> menu, and this works okay for me.<a href="https://i.stack.imgur.com/BwlK1.png" rel="noreferrer"><img src="https://i.stack.imgur.com/BwlK1.png" alt="enter image description here"></a>

blocks|key|312146|text|您可以使用：adb+shell+input+keyboard+text+"rr"向设备发送重新加载调用|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|312147|entityMap^0|6|Y|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

You can send a reload call to the device with: <code>adb shell input keyboard text "rr"</code>

blocks|key|312100|text|对于iOS，我喜欢将我的应用程序包装在这样的组件中，它允许3个手指触摸就可以触发开发菜单：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|312101|import+{+NativeModules+}+from+'react-native';

//+wraps+the+app+in+a+function+to+allow+three+finger+dev+menu+access
const+DevMenuTrigger+=+({+children+})+=>+{
++const+{+DevMenu+}+=+NativeModules;
++const+panResponder+=+PanResponder.create({
++++onStartShouldSetPanResponder:+(evt,+gestureState)+=>+{
++++++if+(gestureState.numberActiveTouches+===+3)+{
++++++++DevMenu.show();
++++++}
++++},
++});
++return+<View+style={{+flex:+1+}}+{...panResponder.panHandlers}>{children}</View>;
};

const+DevApp+=+()+=>+(<DevMenuTrigger><App+/></DevMenuTrigger>);

//+export+default+App;
export+default+DevApp;|code-block|syntax|javascript|312102|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For iOS I like to wrap my app in a component like this which allows a 3 finger touch to trigger the dev menu:

<pre><code>import { NativeModules } from 'react-native';

// wraps the app in a function to allow three finger dev menu access
const DevMenuTrigger = ({ children }) =&gt; {
 const { DevMenu } = NativeModules;
 const panResponder = PanResponder.create({
 onStartShouldSetPanResponder: (evt, gestureState) =&gt; {
 if (gestureState.numberActiveTouches === 3) {
 DevMenu.show();
 }
 },
 });
 return &lt;View style={{ flex: 1 }} {...panResponder.panHandlers}&gt;{children}&lt;/View&gt;;
};

const DevApp = () =&gt; (&lt;DevMenuTrigger&gt;&lt;App /&gt;&lt;/DevMenuTrigger&gt;);

// export default App;
export default DevApp;
</code></pre>

blocks|key|5319642|text|对我来说，只使用adb+shell+input+keyevent+82就行了|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5319643|为方便起见，您可以将其添加到package.json文件内的scripts中|5319644|这里有个链接："android-menu":+"adb+shell+input+keyevent+82"|5319645|显然，KK设备也存在问题--+solved+here|5319646|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/45609855/adb-key-event-82-for-unlocking-the-android-device-screen-is-not-working-for-kk-d^0|8|R|0|E|C|U|7|0|7|19|0|F|B|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|14|8|@]|D|@$9|15|A|16|1|17]]|E|$]]|$1|L|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|M|$N|$5|O|P|Q|E|$R|S]]]]

For me only using <code>adb shell input keyevent 82</code> worked 

for convenience you can add it to your <code>scripts</code> inside the <code>package.json</code> file 

something link this:
<code>"android-menu": "adb shell input keyevent 82"</code>

also apparently there is an issue with KK devices - <a href="https://stackoverflow.com/questions/45609855/adb-key-event-82-for-unlocking-the-android-device-screen-is-not-working-for-kk-d">solved here</a>

blocks|key|2218162|text|在Android中也可以通过音量键打开调试菜单。检查下面的链接。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2218163|https://stackoverflow.com/a/59526945/958913|offset|length|2218164|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|17|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@$D|O|E|P|1|Q]]|A|$]]|$1|F|3|-4|5|6|7|R|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|C]]]]

It's also possible to open Debug menu by volume keys in Android. Check the below link.
<a href="https://stackoverflow.com/a/59526945/958913">https://stackoverflow.com/a/59526945/958913</a>

blocks|key|3207788|text|不适用于adb+shell+input+keyevent+82。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3207789|当您启动服务时，将在终端中打印提示。|3207790|"start":+"react-native+start",|3207791|按d|3207792|++++++Welcome+to+Metro!
Fast+-+Scalable+-+Integrated

To+reload+the+app+press+"r"
To+open+developer+menu+press+"d"|code-block|syntax|javascript|3207793|entityMap^0|4|R|0|0|0|U|0|1|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|L|3|M|5|N|7|12|8|@]|D|@]|E|$O|P]]|$1|Q|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|R|$]]

Not applicable for <code>adb shell input keyevent 82</code>.
When you start the service, a prompt will be printed in the terminal.
<code>&quot;start&quot;: &quot;react-native start&quot;,</code>
Press <code>d</code>
<pre><code> Welcome to Metro!
Fast - Scalable - Integrated

To reload the app press &quot;r&quot;
To open developer menu press &quot;d&quot;
</code></pre>

Is there a way to open dev menu or reload app without shaking the app?

Android
Wireless over wifi so no usb cable
Windows 10

Hot reload or Live reload is not good enough and my arm hurts :)

Open Dev Menu or reload app without shaking?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有没有办法在不摇动应用程序的情况下打开开发菜单或重新加载应用程序？Android Wireless over wifi，无需usb线缆Windows 10热重新加载或实时重新加载不够好，我的手臂很痛:)

问打开开发菜单或重新加载应用程序而不摇动？
EN

回答 9

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