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社区首页 >问答首页 >MSSQL:使用count时基于行创建列

MSSQL:使用count时基于行创建列
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Stack Overflow用户
提问于 2017-10-13 21:23:52
回答 2查看 156关注 0票数 1

如何基于列创建列。

因此,对于行"EOIVR - SB_Internal_LN -3- Operator",它将创建一个名为"operator“的列,值将是"option press”中的值。

在此sql fiddle

下表

代码语言:javascript
复制
CREATE TABLE IVRInterval
    ([cLevelName] varchar(50), [nLevel] FLOAT(20), [I3TimeStampGMT] DATETIME, [cExitPath] varchar(20))
;
INSERT INTO IVRInterval
    ([cLevelName], [nLevel], [I3TimeStampGMT], [cExitPath])
VALUES
    ('EOIVR - SB_Internal_LN - 3 - Operator', '5', '2017-10-05 09:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 3 - Operator', '5', '2017-10-05 10:00:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 3 - Operator', '5', '2017-10-11 11:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 3 - Operator', '5', '2017-10-11 12:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-11 13:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-09 08:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-09 11:00:00.000', '*'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-11 15:00:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-06 09:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-06 11:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 1 - SD', '5', '2017-10-09 14:30:00.000', '*'),
    ('EOIVR - SB_Internal_LN - 2 - Lobby', '5', '2017-10-06 13:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 2 - Lobby', '5', '2017-10-09 14:00:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 2 - Lobby', '5', '2017-10-04 07:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 2 - Lobby', '5', '2017-10-04 08:30:00.000', 'Workgroup Queue'),
    ('EOIVR - SB_Internal_LN - 2 - Lobby', '5', '2017-10-10 08:00:00.000', '*')

我运行这个查询

代码语言:javascript
复制
select 

Convert(date,I3TimeStampGMT) as 'Dates',
(select cLevelName) as 'Options Name',
count(I3TimeStampGMT) as 'Option Press'

from IVRInterval

where
I3TimeStampGMT between '2017-10-04 00:00:00' and '2017-10-11 23:59:59'
and cLevelName like '%%EOIVR - SB_Internal_LN -%%'
and nLevel = '5'
and not cExitPath = '*'

group by cLevelName, Convert(date,I3TimeStampGMT)

我得到了这个结果

代码语言:javascript
复制
Dates       Options Name                         Option Press
2017-10-04  EOIVR - SB_Internal_LN - 2 - Lobby      2
2017-10-05  EOIVR - SB_Internal_LN - 3 - Operator   2
2017-10-06  EOIVR - SB_Internal_LN - 1 - SD         2
2017-10-06  EOIVR - SB_Internal_LN - 2 - Lobby      1
2017-10-09  EOIVR - SB_Internal_LN - 1 - SD         1
2017-10-09  EOIVR - SB_Internal_LN - 2 - Lobby      1
2017-10-11  EOIVR - SB_Internal_LN - 1 - SD         2
2017-10-11  EOIVR - SB_Internal_LN - 3 - Operator   2

我希望我的结果是这样

代码语言:javascript
复制
Date       Lobby    SD    Operator
2017-10-11  0       1       1

我在mssql上是只读的

EN

回答 2

Stack Overflow用户

发布于 2017-10-13 21:53:57

您可以使用条件聚合:

代码语言:javascript
复制
SELECT CAST([I3TimeStampGMT]  AS DATE) AS [date],
     COUNT(CASE WHEN [cLevelName] LIKE '%Lobby' THEN 1 END)    AS Lobby,
     COUNT(CASE WHEN [cLevelName] LIKE '%SD' THEN 1 END)       AS SD,
     COUNT(CASE WHEN [cLevelName] LIKE '%Operator' THEN 1 END) AS Operator
FROM IVRInterval
GROUP BY CAST([I3TimeStampGMT]  AS DATE);
票数 1
EN

Stack Overflow用户

发布于 2017-10-13 22:52:19

我们需要使用'%%‘表达式,当在name列中使用like时,它在任何地方都是有意义的。因为如果单词末尾有空隙,则在分组时会曲解所需的单词并给出错误的结果。

代码语言:javascript
复制
create table stack(Dates date,name nvarchar(100))

insert into stack values

('2017-10-04', 'EOIVR - SB_Internal_LN - 2 - Lobby  ') ,
('2017-10-05', 'EOIVR - SB_Internal_LN - 3 - Operator') ,
('2017-10-06', 'EOIVR - SB_Internal_LN - 1 - SD') ,
('2017-10-06', 'EOIVR - SB_Internal_LN - 2 - Lobby') ,
('2017-10-09', 'EOIVR - SB_Internal_LN - 1 - SD') ,
('2017-10-09', 'EOIVR - SB_Internal_LN - 2 - Lobby') ,
('2017-10-11', 'EOIVR - SB_Internal_LN - 1 - SD') ,
('2017-10-11', 'EOIVR - SB_Internal_LN - 3 - Operator')

SELECT Dates as Date,
     COUNT(CASE WHEN name LIKE '%Lobby%' THEN 1 END)    AS Lobby,
     COUNT(CASE WHEN name LIKE '%SD%' THEN 1 END)       AS SD,
     COUNT(CASE WHEN name LIKE '%Operator%' THEN 1 END) AS Operator
FROM stack
GROUP BY Dates
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/46731024

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