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问更改JSON对象数组的顺序
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Stack Overflow用户

提问于 2017-01-18 20:53:25

回答 3查看 48关注 0票数 0

我是Javascript的初学者。我正在使用Javascript创建一个具有两个JSON数组的项目：

 var interfaces = [
                {id:'123123-12-31-23',mac:'234',flowid:'1',status:'deployed'},
                {id:'456456-12-31-23',mac:'45645',flowid:'2',status:'deployed'},
                {id:'123123-12-31-234',mac:'45',flowid:'3',status:'deployed'},
                {id:'456456-12-31-234',mac:'89',flowid:'4',status:'deployed'}
            ];

    var reorderedInterfaces =   [

                {id:'456456-12-31-23',mac:'45645',flowid:'2',status:'deployed'},
                {id:'456456-12-31-234',mac:'89',flowid:'4',status:'deployed'},
                {id:'123123-12-31-234',mac:'45',flowid:'3',status:'deployed'},
                {id:'123123-12-31-23',mac:'234',flowid:'1',status:'deployed'},
            ];

我需要以下输出：

var finalOutput = {
    1:2,
    2:4,
    3:3,
    4:1
}

下面是我的代码：

var obj = {}
    for(i=0; i<interfaces.length; i++){
        console.log()
        for(j=0; j<reorderedInterfaces.length; j++){
            obj[interfaces[i].flowid] = reorderedInterfaces[j].flowid
            break;
        }

    }   
    console.log(obj)

这给了我错误的输出

javascript

json

回答 3

Stack Overflow用户

发布于 2017-01-18 20:59:42

当迭代器i和j具有相同的值时，您只需赋值即可。

if(i == j)
{
  obj[interfaces[i].flowid] = reorderedInterfaces[j].flowid
  break;
}

var interfaces = [{
  id: '123123-12-31-23',
  mac: '234',
  flowid: '1',
  status: 'deployed'
}, {
  id: '456456-12-31-23',
  mac: '45645',
  flowid: '2',
  status: 'deployed'
}, {
  id: '123123-12-31-234',
  mac: '45',
  flowid: '3',
  status: 'deployed'
}, {
  id: '456456-12-31-234',
  mac: '89',
  flowid: '4',
  status: 'deployed'
}];

var reorderedInterfaces = [

  {
    id: '456456-12-31-23',
    mac: '45645',
    flowid: '2',
    status: 'deployed'
  }, {
    id: '456456-12-31-234',
    mac: '89',
    flowid: '4',
    status: 'deployed'
  }, {
    id: '123123-12-31-234',
    mac: '45',
    flowid: '3',
    status: 'deployed'
  }, {
    id: '123123-12-31-23',
    mac: '234',
    flowid: '1',
    status: 'deployed'
  },
];


var obj = {}
for (i = 0; i < interfaces.length; i++) {
  for (j = 0; j < reorderedInterfaces.length; j++) {
    if(i == j)
    {
    obj[interfaces[i].flowid] = reorderedInterfaces[j].flowid
    break;
    }
  }

}
console.log(obj)

票数 3

Stack Overflow用户

发布于 2017-01-18 21:02:16

您只需要一个循环，并采用相同的索引。

var interfaces = [{ id: '123123-12-31-23', mac: '234', flowid: '1', status: 'deployed' }, { id: '456456-12-31-23', mac: '45645', flowid: '2', status: 'deployed' }, { id: '123123-12-31-234', mac: '45', flowid: '3', status: 'deployed' }, { id: '456456-12-31-234', mac: '89', flowid: '4', status: 'deployed' }],
    reorderedInterfaces = [{ id: '456456-12-31-23', mac: '45645', flowid: '2', status: 'deployed' }, { id: '456456-12-31-234', mac: '89', flowid: '4', status: 'deployed' }, { id: '123123-12-31-234', mac: '45', flowid: '3', status: 'deployed' }, { id: '123123-12-31-23', mac: '234', flowid: '1', status: 'deployed' }, ],
    result = {};

interfaces.forEach(function (a, i) {
    result[a.flowid] = reorderedInterfaces[i].flowid;
});

console.log(result);

票数 1

Stack Overflow用户

发布于 2017-01-18 21:28:57

更改您的代码

var obj = {}
    for(i=0; i<interfaces.length; i++){
        console.log()
        for(j=0; j<reorderedInterfaces.length; j++){
            obj[interfaces[i].flowid] = reorderedInterfaces[j].flowid
            break;
        }

    }

至

var obj = {}
    for(i=0; i<interfaces.length; i++){
        for(j=0; j<reorderedInterfaces.length; j++){
            if(i==j){
               obj[interfaces[i].flowid] = reorderedInterfaces[j].flowid;
            }
        }

    }

以获取预期输出。希望这能对你有所帮助

票数 0

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/41719958

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