blocks|key|1633321|text|SELECT+name,+score
FROM+SCORES
JOIN+(SELECT+distinct+score+score3
++++++FROM+scores
++++++ORDER+BY+score+DESC
++++++LIMIT+2,+1)+x
ON+score+>=+score3
ORDER+by+score+DESC|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1633322|FIDDLE|unstyled|offset|length|1633323|entityMap|0|LINK|mutability|MUTABLE|url|http://www.sqlfiddle.com/#!2/5b7a0/5^0|0|0|6|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>SELECT name, score
FROM SCORES
JOIN (SELECT distinct score score3
 FROM scores
 ORDER BY score DESC
 LIMIT 2, 1) x
ON score &gt;= score3
ORDER by score DESC
</code></pre>

<a href="http://www.sqlfiddle.com/#!2/5b7a0/5" rel="noreferrer">FIDDLE</a>

blocks|key|3756461|text|SELECT+name,score
++++FROM+SCORES
++++WHERE+score+in+(
++++++++SELECT+distinct+s.score
++++++++FROM+SCORES+as+s
++++++++ORDER+BY+s.score+desc
++++++++LIMIT+3)
++++)
++++ORDER+BY+score|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3756462|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>SELECT name,score
 FROM SCORES
 WHERE score in (
 SELECT distinct s.score
 FROM SCORES as s
 ORDER BY s.score desc
 LIMIT 3)
 )
 ORDER BY score
</code></pre>

blocks|key|1633307|text|SELECT++Name,+MAX(Score)+Score
FROM++++TableName+a
WHERE+++EXISTS
++++++++(
++++++++++++SELECT++1
++++++++++++FROM++++TableName+b
++++++++++++WHERE+++a.Score+=+b.Score
++++++++++++GROUP+++BY+Score
++++++++++++ORDER+++BY+Score+DESC
++++++++++++LIMIT+++3
++++++++)
GROUP+++BY+Name
ORDER+++BY+Score+DESC|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1633308|unstyled|1633309|SQLFiddle+Demo|unordered-list-item|offset|length|1633310|1633311|基于上述记录的输出|1633312|╔══════╦═══════╗
║+NAME+║+SCORE+║
╠══════╬═══════╣
║+Mark+║++++29+║
║+John+║++++29+║
║+Matt+║++++29+║
║+Luke+║++++28+║
║+Paul+║++++27+║
╚══════╩═══════╝|1633313|entityMap|0|LINK|mutability|MUTABLE|url|http://www.sqlfiddle.com/#!2/5541a/6^0|0|0|0|E|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|Y|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|Z|8|@]|9|@$I|10|J|11|1|12]]|A|$]]|$1|K|3|-4|5|E|7|13|8|@]|9|@]|A|$]]|$1|L|3|M|5|E|7|14|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|15|8|@]|9|@]|A|$B|C]]|$1|P|3|-4|5|E|7|16|8|@]|9|@]|A|$]]]|Q|$R|$5|S|T|U|A|$V|W]]]]

<pre><code>SELECT Name, MAX(Score) Score
FROM TableName a
WHERE EXISTS
 (
 SELECT 1
 FROM TableName b
 WHERE a.Score = b.Score
 GROUP BY Score
 ORDER BY Score DESC
 LIMIT 3
 )
GROUP BY Name
ORDER BY Score DESC
</code></pre>

<ul>
<li><a href="http://www.sqlfiddle.com/#!2/5541a/6" rel="nofollow">SQLFiddle Demo</a></li>
</ul>

OUTPUT based on the records given above

<pre><code>╔══════╦═══════╗
║ NAME ║ SCORE ║
╠══════╬═══════╣
║ Mark ║ 29 ║
║ John ║ 29 ║
║ Matt ║ 29 ║
║ Luke ║ 28 ║
║ Paul ║ 27 ║
╚══════╩═══════╝
</code></pre>

blocks|key|500069|text|我会尝试这样的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|500070|SELECT+*+FROM+mytable
WHERE+score+IN+(SELECT+DISTINCT+score+FROM+mytable+ORDER+BY+score+DESC+LIMIT+3)
ORDER+BY+score+DESC|code-block|syntax|javascript|500071|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I would try something like:

<pre><code>SELECT * FROM mytable
WHERE score IN (SELECT DISTINCT score FROM mytable ORDER BY score DESC LIMIT 3)
ORDER BY score DESC
</code></pre>

blocks|key|1640913|text|这将给出前三名的分数，而不考虑平局。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1640914|SELECT+score+FROM+mytable+group+by+score+score+DESC+LIMIT+3|offset|length|style|CODE|1640915|现在拿到第三分。|1640916|选择MIN(score')+FROM+(SELECTscoreFROMmytablegroup+by+score+ORDER+BYscore`+DESC+LIMIT+3)作为top3|1640917|最终获得等于或高于第三个分数的所有内容|1640918|SELECT+*+FROM+mytable+WHERE+score'+>=+(SELECT+MIN(score')+FROM+(SELECT+score+FROM+mtyable+group+by+score'+ORDER+BYscore`+DESC+LIMIT+3)+as+top3)|1640919|entityMap^0|0|7|5|I|7|15|5|0|0|6|K|V|4|16|N|0|0|E|7|S|M|1Z|5|2A|7|2R|F|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@$D|T|E|U|F|G]|$D|V|E|W|F|G]|$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|10|8|@$D|11|E|12|F|G]|$D|13|E|14|F|G]|$D|15|E|16|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|17|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|18|8|@$D|19|E|1A|F|G]|$D|1B|E|1C|F|G]|$D|1D|E|1E|F|G]|$D|1F|E|1G|F|G]|$D|1H|E|1I|F|G]]|9|@]|A|$]]|$1|P|3|-4|5|6|7|1J|8|@]|9|@]|A|$]]]|Q|$]]

this will give the top three scores, regardless of ties.

SELECT <code>score</code> FROM <code>mytable</code> group by score
ORDER BY <code>score</code> DESC
LIMIT 3

now get the third score.

SELECT MIN(<code>score') FROM (SELECT</code>score<code>FROM</code>mytable<code>group by score
ORDER BY</code>score` DESC
LIMIT 3) as top3

finally get everything equal or above the third score

SELECT * FROM <code>mytable</code> WHERE <code>score' &gt;=
(SELECT MIN(</code>score') FROM 
(SELECT <code>score</code> FROM <code>mtyable</code> group by <code>score'
ORDER BY</code>score` DESC
LIMIT 3) as top3)

blocks|key|3756489|text|这是。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3756490|SELECT
++NAME,
++score
FROM+SCORES
WHERE+FIND_IN_SET(score,(SELECT
+++++++++++++++++++++++++++SUBSTRING_INDEX(GROUP_CONCAT(+DISTINCT+score+ORDER+BY+score+DESC),',',3)
+++++++++++++++++++++++++FROM+SCORES))+>+0
ORDER+BY+score+desc|code-block|syntax|javascript|3756491|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here IS <a href="http://www.sqlfiddle.com/#!2/5b7a0/11" rel="nofollow">SQL FIDDLE</a>.

<pre><code>SELECT
 NAME,
 score
FROM SCORES
WHERE FIND_IN_SET(score,(SELECT
 SUBSTRING_INDEX(GROUP_CONCAT( DISTINCT score ORDER BY score DESC),',',3)
 FROM SCORES)) &gt; 0
ORDER BY score desc
</code></pre>

I'm building a "Top 3 Scores" Leaderboard. I want to display the top three scores, drawing the max per person, but I don't want to limit 3, because I want to display anyone that has the top 3 scores. So for example, with the data below, 

<pre><code>+----+-----+
|Name|Score|
+----+-----+
|Matt| 17|
|Mark| 29|
|Luke| 28|
|John| 29|
|Paul| 27|
|Matt| 29|
|Mark| 22|
+----+-----+
</code></pre>

I want to display:

<pre><code>+------+-----+
|Name |Score|
+------+-----+
|1.Matt| 30|
|2.Mark| 29|
|2.John| 29|
|3.Luke| 28|
+------+-----+
</code></pre>

My first thought is to extract the max for everyone, and then stop displaying after the score changes (using PHP).

<pre><code>select name, max(score)
from SCORES
group by name
order by name
</code></pre>

Is there any way to do this directly in SQL?

Top 3 Scores - MySQL

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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社区新版编辑器体验调研

我正在建立一个“前3名”排行榜。我想要显示前三个分数，绘制每个人的最大分数，但我不想限制3个，因为我想显示具有前三个分数的任何人。例如，使用下面的数据，+----+-----+|Name|Score|+----+-----+|Matt|   17||Mark|   29||Luke|   28||John|   29||Paul|   27||Matt|   29||Mark|   22|+---

问前3名-- MySQL
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回答 6

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