UILabel不显示inputView
我将使用UILabel来允许用户使用UIDatePicker选择日期。
为此，我创建了一个UILabel子类，覆盖了inputView和inputAccessoryView属性，使它们可写；我还实现了-(BOOL) canBecomeFirstResponder和-(BOOL) isUserInteractionEnabled方法，这两个方法都返回YES。然后，我为inputView属性分配了一个UIDatePIcker实例。
在这一点上，我的预期是，当标签被点击时，应该会出现一个UIDatePicker，但什么也不会发生。
有什么帮助吗？
代码如下：
YPInteractiveUILabel.h
@interface YPInteractiveUILabel : UILabel
@property (readwrite) UIView *inputView;
@property (readwrite) UIView *inputAccessoryView;
- (BOOL) canBecomeFirstResponder;
- (BOOL) isUserInteractionEnabled;
@end
YPInteractiveUILabel.h
#import "YPInteractiveUILabel.h"
@implementation YPInteractiveUILabel
- (id)initWithCoder:(NSCoder *)aDecoder
{
self = [super initWithCoder:aDecoder];
if (self)
{
UIDatePicker *datePicker = [[UIDatePicker alloc] init];
[self setInputView:datePicker];
}
return self;
}
- (BOOL)isUserInteractionEnabled
{
return YES;
}
- (BOOL)canBecomeFirstResponder
{
return YES;
}
@end回答 7
Stack Overflow用户
发布于 2012-10-12 22:12:24
多亏了这些建议(特别是来自NeverBe的评论和rdelmar提出的答案)，我发现了代码中的问题。简而言之，为了显示输入标签，需要在用户点击标签时调用becomeFirstResponder方法。
更正了UILabel子类实现之后(头文件保持不变)：
@implementation YPInteractiveUILabel
- (id)initWithCoder:(NSCoder *)aDecoder
{
self = [super initWithCoder:aDecoder];
if (self)
{
UIDatePicker *datePicker = [[UIDatePicker alloc] init];
[self setInputView:datePicker];
UITapGestureRecognizer *tapper = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(launchPicker:)];
[self addGestureRecognizer:tapper];
}
return self;
}
- (BOOL)isUserInteractionEnabled
{
return YES;
}
- (BOOL)canBecomeFirstResponder
{
return YES;
}
-(void)launchPicker:(UITapGestureRecognizer *) tapper
{
[self becomeFirstResponder];
}
@endStack Overflow用户
发布于 2016-08-06 19:18:36
UILabel + UIDatePicker --带有完成按钮的Swift版本。
import UIKit
class DatePickerLabel: UILabel {
private let _inputView: UIView? = {
let picker = UIDatePicker()
return picker
}()
private let _inputAccessoryToolbar: UIToolbar = {
let toolBar = UIToolbar()
toolBar.barStyle = UIBarStyle.Default
toolBar.translucent = true
toolBar.sizeToFit()
return toolBar
}()
override var inputView: UIView? {
return _inputView
}
override var inputAccessoryView: UIView? {
return _inputAccessoryToolbar
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
let doneButton = UIBarButtonItem(title: "Done", style: UIBarButtonItemStyle.Plain, target: self, action: #selector(doneClick))
let spaceButton = UIBarButtonItem(barButtonSystemItem: UIBarButtonSystemItem.FlexibleSpace, target: nil, action: nil)
_inputAccessoryToolbar.setItems([ spaceButton, doneButton], animated: false)
let tapRecognizer = UITapGestureRecognizer(target: self, action: #selector(launchPicker))
self.addGestureRecognizer(tapRecognizer)
}
override func canBecomeFirstResponder() -> Bool {
return true
}
@objc private func launchPicker() {
becomeFirstResponder()
}
@objc private func doneClick() {
resignFirstResponder()
}
}Stack Overflow用户
发布于 2015-04-29 17:28:27
您可以像在Apple documentation中解释的那样，直接使用inputView getter方法
- (UIView *)inputView {
return myInputView;
}
- (BOOL)canBecomeFirstResponder {
return YES;
}然后添加一个手势或按钮来调用becomeFirstResponder：
- (void)showInputView:(id)sender {
[self becomeFirstResponder];
}https://stackoverflow.com/questions/12849146
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