问存储3个最近的坐标

EN

mypoints = [(distance12, x1, x2),...,(distancenm, xn, xm)]
mypoints.sort()
three_closer = mypoints[:3]

..............
mypoints = []
for row in rows:
     # Get coords for current record
     curr_coords = row.getAttribute("lat") + ',' + row.getAttribute("lng")
     # Get distance
     tempDistance = distance.distance(user_coords, curr_coords).miles
     mypoints.append((tempDistance, row))

mypoints.sort()
#the three closest points:
mythree_shorter = mypoints[0:3]
for distance, row in mythree_shorter:
    shortestStation = json.dumps(
                            {'number': row.getAttribute("number"),
                             'address': row.getAttribute("address"),
                             'lat': row.getAttribute("lat"),
                             'lng': row.getAttribute("lng"),
                             'open': row.getAttribute("open")},
                             sort_keys=True,
                             indent=4)
    save_in_some_way(shortestStation)   #maybe writing to a file?
..................

closest = points[:NUM_CLOSEST]
closest.sort()
for point in points[NUM_CLOSEST:]:
    if point.distance < closest[-1].distance:
        closest[-1] = point
        closest.sort()