我需要自动生成的序列号从001开始在PHP / MYSQL中只有3位数字
例: 001下一步是002,下一步是003...009 ..010 ..119..120..etc但生成的数字应该是在序列明智不像001然后120或008等,我需要在序列号。
实际上,我有产品跟踪系统。我需要我的主产品id +自动序列号的混合器(如果需要,只有3位数字可以更改),因此我的最终产品id变成:
111-001、111-002、111-003、111-004 ....etc
注意:这个自动序列号将被插入到我的mysql数据库中(在ADD按钮之后跟随Update query (因此我的自动序列号将被输入到database with Update query ))
发布于 2013-11-29 18:37:09
只需在id列中添加length 3和zerofill即可。
ALTER TABLE `YOUR_TABLE` CHANGE
`id_column` `id_column` INT( 3 ) UNSIGNED ZEROFILL NOT NULL AUTO_INCREMENT发布于 2013-11-29 18:31:19
只要稍加修改,就能满足您的需求
<?php
$connection = mysql_connect("localhost","root","")
or die("no connection");
$db_select=mysql_select_db("test",$connection)
or die("no connection to db");
$query3 = "SELECT * FROM simple";
$result3 = mysql_query($query3);
$count = mysql_num_rows($result3);
if($count == 0)
{
$seq = 1;
$ref = 111;
$a = sprintf("%04d", $seq);
$emp_id = $ref.'-'.$a;
$query= "INSERT INTO simple (emp_id) VALUES ('$emp_id')";
$result=mysql_query($query)or die(mysql_error());
}
else
{
$query2 = "SELECT * FROM simple ORDER BY id DESC LIMIT 1";
$result2 = mysql_query($query2);
$row = mysql_fetch_array($result2);
$last_id = $row['emp_id'];
$rest = substr("$last_id", -4);
$insert_id = "$rest" + 1;
echo $ars = sprintf("%04d", $insert_id);
$ref = 111;
$emp_id = $ref.'-'.$ars;
$query= "INSERT INTO simple (emp_id) VALUES ('$emp_id')";
$result=mysql_query($query)or die(mysql_error());
}发布于 2016-03-18 15:13:52
尝试以下代码:
$maxDigit=5; //maximum digit of ur number
$currentNumber=0020; //example this is your last number in database all we need to do is remove the zero before the number . i dont know how to remove it
$count=strlen($currentNumber); //count the digit of number. example we already removed the zero before the number. the answer here is 2
$numZero="";
for($count;$count<=$maxDigit;$count++)
$numZero=$numZero+"0";
$newNum=$newNum+$currentNumber;输出:00020
https://stackoverflow.com/questions/20283458
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