blocks|key|4110579|text|CkXml将通过getXml方法为您提供所需的内容。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4110580|CkXml+xml+=+new+CkXml();
xml.LoadXml("<root><company><name>Chilkat+Software,+Inc.</name><url>http://www.chilkatsoft.com/</url><phone>630-784-9670</phone></company></root>");
xml.getXml();

//+Output+looks+like+this:
//+
//+<?xml+version="1.0"+encoding="utf-8"+?>
//+
//+<root>
//+++++<company>
//+++++++++<name>Chilkat+Software,+Inc.</name>
//+++++++++<url>http://www.chilkatsoft.com/</url>
//+++++++++<phone>630-784-9670</phone>
//+++++</company>
//+</root>|code-block|syntax|javascript|4110581|还有JTidy，它是专门针对超文本标记语言的，但它应该可以很好地满足你的需求。|4110582|entityMap|0|LINK|mutability|MUTABLE|url|http://www.chilkatsoft.com/refdoc/javaCkXmlRef.html|1|http://jtidy.sourceforge.net/^0|8|6|0|5|0|0|0|2|5|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|M|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]]]

<a href="http://www.chilkatsoft.com/refdoc/javaCkXmlRef.html" rel="nofollow">CkXml</a> will provide you with what you need via the <code>getXml</code> method.

<pre><code>CkXml xml = new CkXml();
xml.LoadXml("&lt;root&gt;&lt;company&gt;&lt;name&gt;Chilkat Software, Inc.&lt;/name&gt;&lt;url&gt;http://www.chilkatsoft.com/&lt;/url&gt;&lt;phone&gt;630-784-9670&lt;/phone&gt;&lt;/company&gt;&lt;/root&gt;");
xml.getXml();

// Output looks like this:
// 
// &lt;?xml version="1.0" encoding="utf-8" ?&gt;
// 
// &lt;root&gt;
// &lt;company&gt;
// &lt;name&gt;Chilkat Software, Inc.&lt;/name&gt;
// &lt;url&gt;http://www.chilkatsoft.com/&lt;/url&gt;
// &lt;phone&gt;630-784-9670&lt;/phone&gt;
// &lt;/company&gt;
// &lt;/root&gt;
</code></pre>

There is also <a href="http://jtidy.sourceforge.net/" rel="nofollow">JTidy</a> which is geared at HTML but should work good enough for what you need.

blocks|key|330045|text|不确定，但是JTidy呢？|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|330046|entityMap|0|LINK|mutability|MUTABLE|url|http://jtidy.sourceforge.net/^0|6|5|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Not sure, but what about <a href="http://jtidy.sourceforge.net/" rel="nofollow">JTidy</a>?

blocks|key|2670691|text|我将假定XML是格式良好的，只是无效。如果您自己通过JAXB生成XML，则可以在编组对象时输出人类可读的XML。您的Marshaller需要提供格式化输出的选项。您可以像这样设置该属性：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2670692|marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,+true);|code-block|syntax|javascript|2670693|如果文档已经提供给您(而您并没有生成它)，那么像UltraEdit这样的工具将是最容易使用的。它处理大型文档和格式化/编辑XML。有一个免费的试用，所以如果这是一个短期的开发问题，也许你可以在试用期间解决它。|2670694|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/javax/xml/bind/Marshaller.html|1|http://www.ultraedit.com/^0|1M|A|1M|A|0|0|0|O|9|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|M|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]]]

I'll assume the XML is well-formed, just not valid. If you're generating the XML yourself via JAXB you can output human-readable XML when you marshal the objects. Your <a href="http://docs.oracle.com/javase/6/docs/api/javax/xml/bind/Marshaller.html" rel="nofollow"><code>Marshaller</code></a> is required to provide an option for formatted output. You set the property like this:

<pre><code>marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
</code></pre>

If the document is provided to you (and you're not generating it) perhaps a tool like <a href="http://www.ultraedit.com/" rel="nofollow">UltraEdit</a> would be easiest to work with. It handles large documents and formats/edits XML. There's a free trial, so if this is a short-term development issue perhaps you can resolve it during the trial period.

blocks|key|4110657|text|我会考虑使用Transformer。类似于下面的内容：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4110658|Transformer+transformer+=+TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT,+"yes");
StreamResult+tranformedDoc+=+new+StreamResult(new+StringWriter());
DOMSource+source+=+new+DOMSource(new+Document());+//+Insert+content+here.

transformer.transform(source,+transformedDoc);

//+Output+string+to+byte+array
return+transformedDoc.getWriter().toString().getBytes();|code-block|syntax|javascript|4110659|考虑到XML的大小，我不知道这对您来说是不是一个好的解决方案，但这只是一个起点。也可能有更有效的方法来做到这一点，因此可能会受到批评。|4110660|entityMap^0|6|B|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

I would consider using a <code>Transformer</code>. Something along the lines of the following:

<pre><code>Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
StreamResult tranformedDoc = new StreamResult(new StringWriter());
DOMSource source = new DOMSource(new Document()); // Insert content here.

transformer.transform(source, transformedDoc);

// Output string to byte array
return transformedDoc.getWriter().toString().getBytes();
</code></pre>

Given the size of your XML, I don't know if this is going to be a good solution for you but it's a starting point. There are also probably more efficient ways of doing this too so would be open to criticism.

blocks|key|330168|text|您可以使用JAXP标识转换，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|330169|javax.xml.transform.Source+xmlSource+=+
++++new+javax.xml.transform.stream.StreamSource(xmlFile);
javax.xml.transform.Result+result+=+
++++new+javax.xml.transform.stream.StreamResult(System.out);
javax.xml.transform.TransformerFactory+transFact+=+
++++javax.xml.transform.TransformerFactory.newInstance();
javax.xml.transform.Transformer+trans+=+
++++transFact.newTransformer();
trans.setOutputProperty("indent",+"yes")
trans.transform(xmlSource,+result);|code-block|syntax|javascript|330170|幸运的是，这将是一个流式转换(如果TransformerFactory是撒克逊人的话肯定会这样)。|330171|您可以扩展此方法，以将流式验证步骤插入到管道中，从而避免对数据进行两次传递。如果在Saxon中执行所有这些操作，额外的好处是缩进将是模式敏感的-确保缩进永远不会干扰模式有效性。|330172|然而，尽管这满足了规定的要求，但我不确定它是否会实现潜在的目标。缩进是为了使数据更具可读性。您是否考虑过将使用哪些工具来显示和手动编辑一个4+4GB的文档？我想不出任何可以完成这项工作的工具，而且它的可用性也很糟糕。此外，4+4Gb的文档很可能是机器生成的，所以如果它无效，您需要修复生成它的程序，而不是数据本身-很可能数据中的任何错误都会系统地重复多次。|330173|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You can use a JAXP identity transform, something like this:

<pre><code>javax.xml.transform.Source xmlSource = 
 new javax.xml.transform.stream.StreamSource(xmlFile);
javax.xml.transform.Result result = 
 new javax.xml.transform.stream.StreamResult(System.out);
javax.xml.transform.TransformerFactory transFact = 
 javax.xml.transform.TransformerFactory.newInstance();
javax.xml.transform.Transformer trans = 
 transFact.newTransformer();
trans.setOutputProperty("indent", "yes")
trans.transform(xmlSource, result);
</code></pre>

With luck this will be a streamed transformation (it certainly will if the TransformerFactory is Saxon).

You could extend this approach to insert a streamed validation step into the pipeline, avoiding the need to make two passes over the data. If you do this all in Saxon, an added bonus is that the indentation will be schema-sensitive - ensuring that indentation never disturbs schema-validity.

However, although that meets the stated requirement, I'm not sure it's going to achieve the underlying goals. Indentation is done to make the data human readable. Have you considered what tools you will use to display and manually edit a 4GB document? I can't think of any that will do the job, and the usability would be awful. Also a 4Gb document is likely to machine-generated, so if it's invalid you need to fix the program that generated it, not the data itself - it's likely that any errors in the data will be repeated systematically many times over.

blocks|key|330187|text|设置sax解析器http://docs.oracle.com/javase/6/docs/api/javax/xml/parsers/SAXParser.html|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|330188|创建您自己的内容处理程序并将其分配给sax解析器：|330189|saxParser.getXmlReader().setContentHandler(new+MyContentHandler());|code-block|syntax|javascript|330190|ContentHandler提供了对解析的所有方面的访问，如果它有不同的子部分，它将使您能够以不同的部分处理它。|330191|<doc>
+++<app></app>
+++<app></app>
</doc>|330192|您可以一次解组一个"app“，并在尝试下一个”app“之前对其进行处理。|330193|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/javax/xml/parsers/SAXParser.html^0|8|21|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|6|7|12|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|13|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|14|8|@]|9|@]|C|$]]|$1|M|3|N|5|H|7|15|8|@]|9|@]|C|$I|J]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|C|$]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]]]

setup a sax parser
<a href="http://docs.oracle.com/javase/6/docs/api/javax/xml/parsers/SAXParser.html" rel="nofollow">http://docs.oracle.com/javase/6/docs/api/javax/xml/parsers/SAXParser.html</a>

create your own content handler and assign it to the sax parser:

<pre><code>saxParser.getXmlReader().setContentHandler(new MyContentHandler());
</code></pre>

The ContentHandler provides access to all aspects of the parsing and will enable you to process the xml in parts if it has distinct sub-parts e.g:

<pre><code>&lt;doc&gt;
 &lt;app&gt;&lt;/app&gt;
 &lt;app&gt;&lt;/app&gt;
&lt;/doc&gt;
</code></pre>

you could unmarshal one "app" at a time and process it before trying the next one.

I have to process a 4GB XML file using Java.

The problem I have is that the XML file is provided unformatted, the content is actually all on one line with no line breaks.

I would like to format the XML file so it has sensible line breaks and indentation, so that if validation fails (I am using JAXB for the parsing), I can easy locate and inspect the problematic section of the XML. 

Does anyone know of a framework that can apply some basic XML formatting programmatically in Java?

How do you format a huge XML file in Java?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我必须使用Java处理一个4 4GB的XML文件。我遇到的问题是，XML文件是未格式化提供的，内容实际上都在一行上，没有换行。我想格式化XML文件，使其具有合理的换行符和缩进，以便如果验证失败(我使用JAXB进行解析)，我可以轻松地定位和检查XML中有问题的部分。有人知道有一个框架可以在Java中以编程方式应用一些基本的XML格式化吗？

问如何在Java中格式化一个巨大的XML文件？
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