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tsql 2012隐式连接8个表
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Stack Overflow用户
提问于 2014-04-25 06:05:59
回答 1查看 69关注 0票数 0

我正在尝试理解以下带有隐式连接的t-sql 2012目前是如何在生产中执行的:

代码语言:javascript
复制
SELECT  distinct Cyear
FROM     dbo.Individual INNER JOIN
              dbo.Course INNER JOIN
              dbo.CalendarYear ON dbo.Course.CalendarYearID = dbo.CalendarYear.CalendarYearID
      AND CalendarYear.endYear >= (SELECT DISTINCT A.endYear FROM CalendarYear A WHERE
              A.active = 1)
      INNER JOIN
              dbo.Cust ON dbo.CalendarYear.CustID = dbo.Cust.CustID INNER JOIN
              dbo.BridgeCust ON dbo.Course.CourseID = dbo.BridgeCust.CourseID ON 
              dbo.Individual.StudID = dbo.BridgeCust.StudID INNER JOIN
              dbo.User INNER JOIN
              dbo.BridgeUser ON dbo.User.UserID = dbo.BridgeUser.UserID
              ON dbo.BridgeCust.CourseID = dbo.BridgeUser.CourseID

与dbo.Course表的dbo.Individual没有直接连接。第一次连接dbo.Individual是使用BridgeCust表。仅为该表的键加上dbo.Individual和dbo.Course表的键设置bridgeCust表。

因此,你能向我解释一下隐式连接是如何设置的吗?

您是否可以编写sql来向我展示设置为真正显式执行的sql?

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回答 1

Stack Overflow用户

发布于 2014-11-06 19:58:09

这可能就是正在发生的事情。

代码语言:javascript
复制
SELECT  DISTINCT Cyear
FROM dbo.Individual
INNER JOIN dbo.Course
        INNER JOIN dbo.CalendarYear
            ON dbo.Course.CalendarYearID = dbo.CalendarYear.CalendarYearID
           AND CalendarYear.endYear >= (
                                        SELECT DISTINCT
                                               A.endYear
                                        FROM CalendarYear AS A
                                        WHERE A.active = 1)
        INNER JOIN dbo.Cust
            ON dbo.CalendarYear.CustID = dbo.Cust.CustID
        INNER JOIN dbo.BridgeCust
            ON dbo.Course.CourseID = dbo.BridgeCust.CourseID
ON dbo.Individual.StudID = dbo.BridgeCust.StudID
INNER JOIN dbo.[User]
        INNER JOIN dbo.BridgeUser
            ON dbo.[User].UserID = dbo.BridgeUser.UserID
ON dbo.BridgeCust.CourseID = dbo.BridgeUser.CourseID;

或者像下面这样重写它,它可能会更清楚。

代码语言:javascript
复制
SELECT  DISTINCT Cyear
FROM dbo.Individual
INNER JOIN (SELECT dbo.BridgeCust.StudID,dbo.BridgeCust.CourseID FROM dbo.Course
        INNER JOIN dbo.CalendarYear
            ON dbo.Course.CalendarYearID = dbo.CalendarYear.CalendarYearID
           AND CalendarYear.endYear >= (
                                        SELECT DISTINCT A.endYear
                                        FROM CalendarYear AS A
                                        WHERE A.active = 1)
        INNER JOIN dbo.Cust
            ON dbo.CalendarYear.CustID = dbo.Cust.CustID
        INNER JOIN dbo.BridgeCust
            ON dbo.Course.CourseID = dbo.BridgeCust.CourseID) F1
ON dbo.Individual.StudID = F1.StudID
INNER JOIN (SELECT dbo.BridgeUser.UserID, dbo.BridgeUser.CourseID FROM dbo.[User]
        INNER JOIN dbo.BridgeUser
            ON dbo.[User].UserID = dbo.BridgeUser.UserID) F2
ON F2.CourseID = F1.CourseID;
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/23280738

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