在OSX上,我为我的音频系统创建了一个AUGraph,如下所示:
OSStatus result = NewAUGraph(&mGraph);
AUNode outputNode;
AudioComponentDescription outputDesc;
outputDesc.componentType = kAudioUnitType_Output;
outputDesc.componentSubType = kAudioUnitSubType_DefaultOutput;
outputDesc.componentManufacturer = kAudioUnitManufacturer_Apple;
outputDesc.componentFlags = 0;
outputDesc.componentFlagsMask = 0;
result = AUGraphAddNode(mGraph, &outputDesc, &outputNode);
AUNode converterNode;
AudioComponentDescription converterDesc;
converterDesc.componentType = kAudioUnitType_FormatConverter;
converterDesc.componentSubType = kAudioUnitSubType_AUConverter;
converterDesc.componentManufacturer = kAudioUnitManufacturer_Apple;
converterDesc.componentFlags = 0;
outputDesc.componentFlagsMask = 0;
result = AUGraphAddNode(mGraph, &converterDesc, &converterNode);
result = AUGraphConnectNodeInput(mGraph, converterNode, 0, outputNode, 0);
result = AUGraphOpen(mGraph);
...initialize graph, start graph, etc...这一切都很好,我可以听到声音,等等。稍后系统关闭:
unsigned char isRunning = false;
AUGraphIsRunning(mGraph, &isRunning);
if (isRunning)
AUGraphStop(mGraph);
OSStatus result;
unsigned char isInitialized = false;
AUGraphIsInitialized(mGraph, &isInitialized);
if (isInitialized)
{
result = AUGraphUninitialize(mGraph);
}
result = DisposeAUGraph(mGraph);再说一次,这里没有问题。然而,不久之后,当系统重新启动时,第一个代码块再次被执行。在以下位置:
result = AUGraphOpen(mGraph);"result“表示为-2005 (badComponentType)。有人知道这是什么原因吗?
发布于 2011-12-03 01:32:24
在关机时调用AUGraphClose修复了这个问题。中不可能有两个具有相同输出单位的开放图?
https://stackoverflow.com/questions/8348537
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