我正在尝试使用Gnome glib/gio C库来创建一个客户端程序,以便通过IPv6连接到服务器。我的服务器盒有一个链路本地IPv6地址:
inet6 addr: fe80::2d0:c9ff:feda:99e0/64 Scope:Link因此,为了访问它,我必须告诉客户端软件使用哪个接口(在本例中为eth0)。因此,以下命令可以工作(使用端口1500):
nc -6 fe80::2d0:c9ff:feda:99e0%eth0 1500在glib中,使用%eth0表示法违反了URI表示法:
(process:31159): GLib-GIO-WARNING **: Invalid URI 'none://[fe80:0:0:0:2d0:c9ff:feda:99e0%eth0]:1500'我查看了代码,它显然希望看到百分号转义符号(即字符'%25'),但我似乎无法获得正确的格式:
** (process:5741): ERROR **: Invalid URI 'none://[fe80:0:0:0:2d0:c9ff:feda:99e0%25eth0]1500'那么,有人知道如何指定接口吗?
编辑:这是代码
// gchar test[255] = "fe80:0:0:0:2d0:c9ff:feda:99e0%eth0";
// gchar test[255] = "fe80:0:0:0:2d0:c9ff:feda:99e0\%eth0";
// gchar test[255] = "fe80:0:0:0:2d0:c9ff:feda:99e0\x25eth0";
// gchar test[255] = "fe80:0:0:0:2d0:c9ff:feda:99e0\%%25eth0";
gchar test[255] = "[fe80:0:0:0:2d0:c9ff:feda:99e0\%%eth0]";
connection = g_socket_client_connect_to_uri (client,
test,
1500,
NULL,
&error);编辑2:完整的代码(使用MichaelHampton的输入):
#include <glib.h>
#include <gio/gio.h>
int
main (int argc, char *argv[])
{
/* initialize glib */
g_type_init ();
GError * error = NULL;
/* create a new connection */
GSocketConnection * connection = NULL;
GSocketClient * client = g_socket_client_new();
connection = g_socket_client_connect_to_host (client,
(gchar*)"fe80::5054:ff:fe1f:6b6c\%br0",
1500, /* your port goes here */
NULL,
&error);
/* don't forget to check for errors */
if (error != NULL)
{
g_error (error->message);
}
else
{
g_print ("Connection successful!\n");
}
return 0;
}发布于 2014-01-07 01:27:54
啊,你调用了错误的函数。您应该使用g_socket_client_connect_to_host直接连接到主机和端口。
下面是一个有效的示例:
connection = g_socket_client_connect_to_host (client,
(gchar*)"fe80::5054:ff:fe1f:6b6c\%br0",
1500, /* your port goes here */
NULL,
&error);完整的示例代码,看起来像是您正在使用的,在相关问题中:GIO socket-server / -client example
https://stackoverflow.com/questions/20909160
复制相似问题